Chapter 6, Problem 9ALQ

(a)

Interpretation Introduction

Interpretation: The making of $\text{0}\text{.1M}\text{NaCl}$ has to be explained.

Concept Introduction: Concentration can be defined in terms of molarity as moles of solute per volume of solution in litres.  It can be given by the expression,

$\text{Weight=}\frac{\text{volume×molarity×molecularweight}}{\text{1000}}$

(b)

Interpretation Introduction

Concept introduction: By volumetric analysis principle,

                                     ${\text{V}}_{\text{1}}{\text{M}}_{\text{1}}{\text{=V}}_{\text{2}}{\text{M}}_{\text{2}}$

Where ${\text{V}}_{\text{1}}\text{and}{\text{M}}_{\text{1}}$ are the Molarity and Volume of one solution, and

            ${\text{V}}_{\text{2}}\text{and}{\text{M}}_{\text{2}}$ are the Molarity and Volume of other.