Chapter 6, Problem 23Q

(a)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

${\text{2CuCl}}_{\text{(aq)}}{\text{+Mg}}_{\text{(s)}}\to {\text{2Cu}}_{\text{(s)}}{\text{+MgCl}}_{\text{2(aq)}}$

In your equation, $\text{Mg}$ went from 0 oxidation number to $\text{+2}$, loss electrons got oxidized is the reducing agent

$\text{Cu}$ went from $\text{+1}\text{to}\text{0}$ gained an electron, got reduced is the oxidizing agent

(b)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

${\text{2CuCl}}_{\text{(aq)}}{\text{+Mg}}_{\text{(s)}}\to {\text{2Cu}}_{\text{(s)}}{\text{+MgCl}}_{\text{2(aq)}}$

In your equation, $\text{Mg}$ went from 0 oxidation number to $\text{+2}$, loss electrons got oxidized is the reducing agent

$\text{Cu}$ went from $\text{+1}\text{to}\text{0}$ gained an electron, got reduced is the oxidizing agent

(c)

Interpretation Introduction

Interpretation: The given following terms has to be differentiated.

Concept introduction:

Oxidation: Oxidation can be defined as the process by which a molecule, atom or ion loses its electron in chemical reaction.

Reduction: Reduction can be defined as the process by which a molecule, atom or ion gains electrons by one of atoms in a chemical reaction.

Oxidizing agents: These are chemical substances that generally gains electrons and is reduced during a chemical reaction. These are otherwise known as electron acceptors.

Reducing agents: These are chemical substances that generally lose electrons and are oxidized during a chemical reaction. These are otherwise called as electron donors.

${\text{2CuCl}}_{\text{(aq)}}{\text{+Mg}}_{\text{(s)}}\to {\text{2Cu}}_{\text{(s)}}{\text{+MgCl}}_{\text{2(aq)}}$

In your equation, $\text{Mg}$ went from 0 oxidation number to $\text{+2}$, loss electrons got oxidized is the reducing agent

$\text{Cu}$ went from $\text{+1}\text{to}\text{0}$ gained an electron, got reduced is the oxidizing agent