Chapter 6, Problem 72E

(a)

Interpretation Introduction

Interpretation: To calculate the volume of the given solutions where one of the solution has volume of $\text{25}\text{.0}\text{mL}\text{and}\text{0}\text{.200}\text{M}$ $\text{HCl}$

$\text{0}\text{.100}\text{M}\text{NaOH}$

Concept introduction: By volumetric analysis principle,

${\text{V}}_{\text{1}}{\text{M}}_{\text{1}}{\text{=V}}_{\text{2}}{\text{M}}_{\text{2}}$

Where ${\text{V}}_{\text{1}}\text{and}{\text{M}}_{\text{1}}$ are the molarity and volume of one solution, and

            ${\text{V}}_{\text{2}}\text{and}{\text{M}}_{\text{2}}$ are the molarity and volume of other .

(b)

Interpretation Introduction

Interpretation: To calculate the volume of the given solutions where one of the solution has volume of $\text{25}\text{.0}\text{mL}\text{and}\text{0}\text{.200}\text{M}$ $\text{HCl}$

$\text{0}\text{.0500}\text{M}{\text{Sr(OH)}}_{\text{2}}$

Concept introduction: By volumetric analysis principle,

${\text{V}}_{\text{1}}{\text{M}}_{\text{1}}{\text{=V}}_{\text{2}}{\text{M}}_{\text{2}}$

Where ${\text{V}}_{\text{1}}\text{and}{\text{M}}_{\text{1}}$ are the molarity and volume of one solution, and

            ${\text{V}}_{\text{2}}\text{and}{\text{M}}_{\text{2}}$ are the molarity and volume of other .

(c)

Interpretation Introduction

Interpretation: To calculate the volume of the given solutions where one of the solution has volume of $\text{25}\text{.0}\text{mL}\text{and}\text{0}\text{.200}\text{M}$ $\text{HCl}$

$\text{0}\text{.250}\text{M}\text{KOH}$

Concept introduction: By volumetric analysis principle,

${\text{V}}_{\text{1}}{\text{M}}_{\text{1}}{\text{=V}}_{\text{2}}{\text{M}}_{\text{2}}$

Where ${\text{V}}_{\text{1}}\text{and}{\text{M}}_{\text{1}}$ are the molarity and volume of one solution, and

            ${\text{V}}_{\text{2}}\text{and}{\text{M}}_{\text{2}}$ are the molarity and volume of other .