Explanation Given The mass of the student is m = 56 kg . The speed of the student is v = 6.0 m/s . The length of the rope is l = 10.0 m . Formula used The running kinetic energy of the student is converted to potential energy when he makes a swing. Therefore, the formula to be used is 1 2 m v 2 = m g l ..... ( 1 ) Here, l is the height from the lowest point. To calculate the tension of the rope, the necessary formula is T = m g cos θ .... ( 2 ) . The tension is maximum at the beginning of the swing. Therefore, its value at that position is T m = m v 2 r + m g cos θ . .... ( 3 ) Calculations a. The height reached by the student is: l = v 2 2 g l = ( 6.0 ) 2 2 × 9

7th Edition

ISBN: 9780321733627

Author: Douglas C. Giancoli

Publisher: PEARSON

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Static and Kinetic Friction

Kinetic friction comes into existence when there are moving surfaces means in other words we can say that the force which comes into existing between moving surfaces is known as kinetic friction.

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Chapter 6, Problem 92GP

To determine

a. The angle θ when the person’s releases the rope.

b. The tension in the rope just before the person’s releases it.

c. Maximum tension in the rope during the swing.

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Chapter 6, Problem 91GP

Chapter 6, Problem 93GP

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a. The angle θ when the person’s releases the rope. b. The tension in the rope just before the person’s releases it. c. Maximum tension in the rope during the swing.