Explanation Given The mass of the student is m = 56 kg . The speed of the student is v = 6.0 m/s . The length of the rope is l = 10.0 m . Formula used The running kinetic energy of the student is converted to potential energy when he makes a swing. Therefore, the formula to be used is 1 2 m v 2 = m g l ..... ( 1 ) Here, l is the height from the lowest point. To calculate the tension of the rope, the necessary formula is T = m g cos θ .... ( 2 ) . The tension is maximum at the beginning of the swing. Therefore, its value at that position is T m = m v 2 r + m g cos θ . .... ( 3 ) Calculations a. The height reached by the student is: l = v 2 2 g l = ( 6.0 ) 2 2 × 9

7th Edition

ISBN: 9780321733627

Author: Douglas C. Giancoli

Publisher: PEARSON

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Chapter 6, Problem 92GP

To determine

a. The angle θ when the person’s releases the rope.

b. The tension in the rope just before the person’s releases it.

c. Maximum tension in the rope during the swing.

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Chapter 6, Problem 91GP

Chapter 6, Problem 93GP

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a. The angle θ when the person’s releases the rope. b. The tension in the rope just before the person’s releases it. c. Maximum tension in the rope during the swing.