Part (a) To determine Landing speed in the absence of air resistance. Explanation Given: Mass of flight including pilot =980 kg Initial horizontal speed of flight =480 km/h Initial height of pilot =3500 m Final land speed of flight =210 km/h Formula used: Conservation of energy (only gravitational force is acting which is conservative in nature) K . E 1 + P . E 1 = K . E 2 + P . E 2 W N C = Δ K . E + Δ P . E W N C : Work done by non-conservative force.Here, it is air resistance. Calculation: v 1 =480 km/h = 480×1000 60×60 m/s =133 .33 m/s Initial kinetic energy: ( K . E 1 ) = 1 2 m v 1 2 = 1 2 ×980 × ( 133.3 ) 2 Initial potential energy: ( P . E 1 ) = m g h 1 = 9 80×9 .80×3500 J Final kinetic energy: ( K . E 2 ) = 1 2 m v 2 2 = 1 2 × m × v 2 2 Final potential energy: ( P Part (b) To determine The average force of air resistance exerted if it came in at a constant glide angle of 12 ° to the earth’s surface.

7th Edition

ISBN: 9780321733627

Author: Douglas C. Giancoli

Publisher: PEARSON

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Chapter 6, Problem 56P

Part (a)

To determine

Landing speed in the absence of air resistance.

Part (b)

To determine

The average force of air resistance exerted if it came in at a constant glide angle of 12° to the earth’s surface.

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Chapter 6, Problem 55P

Chapter 6, Problem 57P

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