To determine The spring constant k of spring. Explanation Given: Mass of car, m = 1200 kg Initial speed of car, u = 95 km/h = 26 .39 m/s Final speed of car, v = 0 Maximum occupant acceleration, a = 4.0 g FormulaUsed: Conservation of mechanical energy P E 1 + K E 1 = P E 2 + K E 2 Initial potential energy: P E 1 Final potential energy: P E 2 Initial kinetic energy: K E 1 Final kinetic energy: K E 2 Newton’s second law of motion: F n e t = m a Mass is m , a is acceleration and F n e t is net force. Spring force: F = - k x Where, k is the spring constant and x is the extension. Potential energy stored in spring: P E = 1 2 k x 2 k : spring constant x : deformation in spring Calculation: Initial potential energy: P . E 1 = 1 2 k x 1 2 = 1 2 k ( 0 ) 2 = 0 J Initial kinetic energy, ( K E 1 ) = 1 2 m v 1 2 Maximum compression in spring, x max Final potential energy, ( P E 2 ) = 1 2 k x max 2 Final kinetic energy, ( K E 2 ) = 0 J Because lift is at rest Conservation of mechanical energy: ( P E 1 + K E 1 ) = ( P E 1 + K E 2 ) 0 + 1 2 m v 1 2 = 1 2 k x max <

7th Edition

ISBN: 9780321733627

Author: Douglas C. Giancoli

Publisher: PEARSON

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Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The p…

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Chapter 6, Problem 42P

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The spring constant k of spring.

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