Chapter 6, Problem 70AE

a)

Interpretation Introduction

Interpretation:Value of equilibrium constant $K$ in below reaction is to be determined.

  $\frac{1}{2}{\text{N}}_{\text{2}}\left(g\right)+\frac{3}{2}{\text{H}}_{\text{2}}\left(g\right)\rightleftharpoons {\text{NH}}_3\left(g\right)$

Concept introduction:Chemical equilibrium is taken into consideration if rate of backward and forward reactions become equal. At this stage, reactants and products have constant concentration. Equilibrium constant is denoted by $K$ .

b)

Interpretation Introduction

Interpretation:Value of equilibrium constant $K$ in below reaction is to be determined.

  ${\text{2NH}}_3\left(g\right)\rightleftharpoons {\text{N}}_{\text{2}}\left(g\right)+3{\text{H}}_{\text{2}}\left(g\right)$

Concept introduction:Chemical equilibrium is taken into consideration if rate of backward and forward reactions become equal. At this stage, reactants and products have constant concentration. Equilibrium constant is denoted by $K$ .

c)

Interpretation Introduction

Interpretation:Value of equilibrium constant $K$ in below reaction is to be determined.

  ${\text{NH}}_3\left(g\right)\rightleftharpoons \frac{1}{2}{\text{N}}_{\text{2}}\left(g\right)+\frac{3}{2}{\text{H}}_{\text{2}}\left(g\right)$

Concept introduction:Chemical equilibrium is taken into consideration if rate of backward and forward reactions become equal. At this stage, reactants and products have constant concentration. Equilibrium constant is denoted by $K$ .

d)

Interpretation Introduction

Interpretation:Value of equilibrium constant $K$ in below reaction is to be determined.

  $2{\text{N}}_{\text{2}}\left(g\right)+6{\text{H}}_{\text{2}}\left(g\right)\rightleftharpoons 4{\text{NH}}_3\left(g\right)$

Concept introduction:Chemical equilibrium is taken into consideration if rate of backward and forward reactions becomes equal. At this stage, reactants and products have constant concentration. Equilibrium constant is denoted by $K$ .