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(a)
Interpretation:
The two
Concept introduction:
Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.
Nucleophilic nature depends on the negative charge present in the molecule, the solvent in which it present and the electronegativity of the atom.
Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.
Addition Reaction: It is defined as chemical reaction in which two given molecules combines and forms product. The types of addition reactions are electrophilic addition, nucleophilic addition, free radical additions and cycloadditions. Generally, compounds with carbon-hetero atom bonds favors addition reaction.
In addition reaction of alkenes when two substituents are placed on same side of
Acid Catalyzed Hydration Reaction: The reaction involves breaking of phi bonds between carbon-carbon multiple bonds and addition of alcohol to more substituted position of carbon in the molecule.
First step is the acid donates proton to the alkene which leads to the formation of more stable carbo cation.
Then, the water is added to the given alkene through acid catalyzed reaction where the water gets added to the carbo cation finally, the removal of one proton from oxonium ion (oxygen with one positive charge) using water results in the formation of product.
(b)
Interpretation:
The products formed in presence of
Concept introduction:
Addition Reaction: It is defined as chemical reaction in which two given molecules combines and forms product. The types of addition reactions are electrophilic addition, nucleophilic addition, free radical additions and cycloadditions. Generally, compounds with carbon-hetero atom bonds favors addition reaction.
In addition reaction of alkenes when two substituents are placed on same side of
Acid Catalyzed Hydration Reaction: The reaction involves breaking of phi bonds between carbon-carbon multiple bonds and addition of alcohol to more substituted position of carbon in the molecule.
First step is the acid donates proton to the alkene which leads to the formation of more stable carbo cation.
Then, the water is added to the given alkene through acid catalyzed reaction where the water gets added to the carbo cation finally, the removal of one proton from oxonium ion (oxygen with one positive charge) using water results in the formation of product.
Carbocation: it is carbon ion that bears a positive charge on it.
Carbocation stability order:
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Chapter 6 Solutions
Organic Chemistry (8th Edition)
- Could you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but (color-coded) and step by step so I can understand it better? Thank you! I want to see what they are doingarrow_forward
- Can you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.arrow_forwardPart 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answerarrow_forwardPart 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet. water and benzene. What is the formal concentration of butanoic acid in each phase when 0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene 100 mL of a) at pit 5.00 b) at pH 9.00arrow_forward
- Calculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 Group of answer choices 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 choices: 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0arrow_forward
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