Concept explainers
(a)
Interpretation: The carbon radical which is formed by homolysis of the
Concept introduction: The formation of carbocation, carbanion and free radical occur due to the heterolysis or homolysis process. Homolysis is opposite to the heterolysis. It forms radical with an unpaired electron.
Resonance is the delocalisation of
(b)
Interpretation: The carbon radical which is formed by homolysis of the
Concept introduction: The formation of carbocation, carbanion and free radical occur due to the heterolysis or homolysis process. Homolysis is opposite to the heterolysis. It forms radical with an unpaired electron.
Resonance is the delocalisation of
(c)
Interpretation: The weaker
Concept introduction: The energy which is released or absorbed in the
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Organic Chemistry-Package(Custom)
- 10. Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction.arrow_forwardBased on the characteristics of the carbonyl group (C = O), what reactions or transformations take place with aldehydes and ketones? a. nucleophilic additions by oxygenb. electrophilic additions by carbon attackc. nucleophilic additions by carbon attackd. electrophilic substitutions through a carbocationand. acid-base because carbonyl can act as both an electrophile and a nucleophilearrow_forwardCarvone is the major constituent of spearmint oil. Draw the major organic product of the reaction of carvone with HOCH2CH2OH, HCI. Carvone • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered in the grading. • In cases where there is more than one answer, just draw one. • If no reaction occurs, draw the organic starting material. + Sn 1arrow_forward
- 10. Draw an energy diagram for the addition of HBr to 1-pentene. Let one curve on your diagram show the formation of 1-bromopentane product and another curve on the same diagram show the formation of 2- bromopentane product. Draw and label the positions for all reactants, intermediates, and products. Which curve has the higher-energy carbocation intermediate? Which curve has the higher-energy first transition state?arrow_forwardOrganic Chemistry - nucleophilic substitution and elimination rxns chapterarrow_forwardN,N-diethyl-m-toluamide (DEET) is the active ingredient in many insect repellent preparations. Following is one of the steps in its synthesis. In the box below draw the structure of the product of this reaction. H3C MgBr 1. CO₂ 2. H₂O* product • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered in the grading. • Draw the Grignard reagent as a covalent magnesium bromide.arrow_forward
- The compound below is treated with chlorine in the presence of light. CH3 CH3CHCH₂CH3 Draw the structure for the organic radical species produced by reaction of the compound with a chlorine atom. Assume reaction occurs at the weakest C-H bond. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. n [ ]# ?arrow_forwardDraw a structural formula for the substitution product of the reaction shown below. Br H NH3 CH₂OH • Use the wedge/hash bond tools to indicate stereochemistry where it exists. If more than one stereoisomer of product is formed, draw both. • Separate multiple products using the + sign from the drop-down menu. • Products that are initially formed as ions should be drawn in their neutral forms.arrow_forwardDraw the organic product you would expect to isolate from the nucleophilic substitution reaction between the molecules shown. Note: You do not need to draw any of the side products of the reaction, only the substitution product. SH + 0 Br + X S C Click and drag to start drawing a structure.arrow_forward
- 8. Give an example of a carbene and give a reason why CHCl3 readily forms a carbene in NaOH.arrow_forwardThe electrophile in the reaction between Br2 and an alkene is the ion.arrow_forwardWhy is less energy required to break a C-H bond to form a more highly substituted radical? Can somebody summarize the words on this page to make it more understandable?arrow_forward