
Interpretation:
For n-butane, the molar volume, enthalpy and entropy as a saturated vapor as well as saturated liquid at 370 K needs to be calculated.
Concept Introduction:
The equation used to calculate the molar volume of vapor is:
Here,
Here,
The formula to calculate enthalpy of vapor
Here,
Here,
The formula to calculate entropy of vapor
Here,
Here,
To calculate molar volume of saturated liquid, the formula to be used is:
Equation to calculate enthalpy of liquid
Here,
Equation by Reidel to calculate heat of vaporization at normal boiling point
Watson equation to calculate heat of vaporization at any temperature using known heat of vaporization at another temperature is:
Equation to calculate entropy of liquid

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Chapter 6 Solutions
Introduction to Chemical Engineering Thermodynamics
- Exhaust gas from a power plant passes through a 15-by-20-it rectangular duct at an average velocity of 50 ft/s. The total length of duct is 250 ft and there are two 90° bends.The gas is at 180°F and about 1 atm, and the properties are similar to those of air. Calculate the pressure drop in the duet and the power required to overcome pressure losses.arrow_forwardUntuk sistem gas etilena (1)/propilena (2), estimasi (f^1, f^2, $^1, dan ^2 pada t = 150°C, P = 30 bar, dan y1 = 0,35; kij = 0. (a) Dengan menerapkan Persamaan (10.63). (b) Dengan asumsi bahwa campuran adalah lingkungan idealarrow_forwardOnly focus on H(3), which is the specific enthalpy for nitrogen gas. chemical engineeringarrow_forward
- chemical engineering. Only focus on H(3), which is the nitrogen gas. Start with the reference state to the process state. Be thorough to the fullestarrow_forwardacetone with these parameters: po:=101325; #Standard atmospheric pressure in PaTfo:=273.15-94.45; #Melting temperature in K Tvo:=273.15+56.15; #Boiling temperature in K Hv:=31270; #Enthalpy of vaporization in J/molR:=8.314; #Gas Constant in J/mol*KNLe:=1.76; #Lewis number for acetoneMw:= 0.05808 ; #kg/mol molecular weight of acetoneW0:= 0.15; Wsp:=0.005;Am:= 0.12; #m^2/kg dry solid for the exposed wet areah:= 11; #W/m^2K for heat transfer coefficienttau__min:= Hv*(W0-Wsp)/Mw/Am/h/(T8-TS); tau__min/60;arrow_forwardchemical engineering Material-energy balance. Only focus on the nitrogen gas, which is H(3)arrow_forward
- 1. The settling chamber, shown schematically in Figure 2E1.1, is used as a primary separation device in the removal of dust particles of density 1500 kg/m³ from a gas of density 0:7 kg/m³ and viscosity 1.90 x 10-5 Pa s. Gas inlet Elevation Gas Gas exit exit H Collection surface -W Section X-X Dimensions: H=3m L = 10 m W=2m Figure 2E1.1 Schematic diagram of settling chamber Assuming Stokes' law applies, show that the efficiency of collection of particles of size x is given by the expression collection efficiency, x = x²8(pp - Pi)L 18μHU where U is the uniform gas velocity through the parallel-sided section of the chamber. State any other assumptions made. (b) What is the upper limit of particle size for which Stokes' law applies? (c) When the volumetric flow rate of gas is 0.9 m³/s, and the dimensions of the chamber are those shown in Figure 2E1.1, determine the collection efficiency for spherical particles of diameter 30 mm.arrow_forwardCan you answer this sequantially correct like show me the full process. Also, since it is chemical engineering related problem a perry's handbook is used. Thank youarrow_forwardchemical engineering Demonstrate how each specific enthalpy was calculated, from the reference state to the process state. Be thorough to the fullest. This is a material-energy balance. The answers are H(1) = 35.7 KJ/kmol, H(2) = 32.0 KJ/kmol, and H(3) = -1.26 KJ/kmol.arrow_forward
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