Chapter 6, Problem 6.12QP

Interpretation Introduction

Interpretation: From the given data of $\text{ClO}$, magnitude of the partial charge in $\text{ClO}$ should be determined.

Concept introduction:

Conversion formula

• $\text{1}\text{D}\text{=3}\text{.336}{\text{×10}}^{\text{-30}}\text{Cm}$
• $\text{1}\stackrel{}{\stackrel{\text{°}}{\text{A}}}{\text{=1×10}}^{\text{-10}}\text{m}$

• $\begin{array}{l}\text{Partial charge, Q}\text{=}\frac{\text{μ}}{\text{r}}\\ \text{μ=}\text{dipole}\text{momnet}\\ \text{r=}\text{bond}\text{distance}\end{array}$

• • ${\text{1e}}^{\text{-}}=\text{1}\text{.66022}{\text{×10}}^{\text{-19}}\text{C}$

To determine: The magnitude for the partial charge in $\text{ClO}$.