Basic Biomechanics
7th Edition
ISBN: 9780073522760
Author: Susan J Hall
Publisher: McGraw-Hill Education
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Textbook Question
Chapter 6, Problem 5AP
If the fibers of a pennate muscle are oriented at a 45° angle to a central tendon, how much tension is produced in the tendon when the muscle fibers contract with 150 N of force? (Answer: 106 N)
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ney:
Load (L) = 5 kgs
= Effort
E = Fulcrum
Weight of forearm = 1.8 kgs
L = Load
Biceps brachii
muscle
Distance of load from elbow joint = 35 cm
%3D
Effort (E) = contraction
of biceps brachii
Distance of center of mass of forearm from elbow = 17 cm
Distance of tendon from elbow = 4 cm
A) Draw the free-body diagram to represent the forces and moments
Load (L) = weight of
object plus forearm
B) Write the torque equation for static equilibrium
Fulcrum (F) = elbow joint
a) Describe how the isolated muscle behaved as it was stretched progressively.
b) What effect does stretching the muscle have on contraction strength? Is this effect linear?
c) What stretch resulted in the highest contraction force? What happens to the muscle at the highest stretch levels?
Describe the relationship between the resting muscle length and the strength of its contraction. Hint: look at the length tension curve for skeletal muscle
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- Arrange the following in statements in the order that they occur during muscle contraction: 1-10 ACh leaves the synaptic knob and enters the synaptic cleft The action potential is carried deep into the muscle cell by T tubules The muscle cell relaxes and lengthens Myosin binds to and pulls on actin, resulting in muscle shortening Calcium attaches to troponin As calcium re-enters the sarcoplasmic reticulum, its concentration at the myofilaments decreases Calcium is released from the sarcoplasmic reticulum Tropomyosin rolls out of the way, exposing actin ACh diffuses across the synaptic cleft and attaches to protein receptors on the sarcolemma, resulting in muscle "excitation" Na+ enters the muscle cell and K+ exits, resulting in an action potentialarrow_forwardHill's equation gives a relation between muscle contraction rates νν and muscle tension TT (T+α)(ν+β)=(T0+α)β(T+α)(ν+β)=(T0+α)β for positive parameters αα and ββ and resting tension T0T0. Rewrite the equation so that the contraction rate is a function of tension.arrow_forwarddescribe the events that lead to muscle contraction starting at the level of the neuromuscular junction. Make sure to use the terms: myosin, actin, calcium, troponin, tropomyosin, T tubules, SR, myosin head, ATP.arrow_forward
- Indicate which of the following are true. Chronically shortened muscles will lose sarcomeres in series in order to maintain ideal amounts of myofilament overlap. Contractile force is proportional to the length of a muscle. Muscle organ contraction is all or nothing. Muscle cells are surrounded by an endomysium. Actin is the thick filament and Z-lines are where the cross-bridges zig-zag to adjacent actin filaments. Muscles with fewer motor units are weaker, i.e., capable of less force. A nerve impulse, calcium, and ATP are necessary for muscle contraction. Tendons attach bones to bones and help to limit the range of motion at joints. Muscle tissue is very dynamic and will respond to chronic stress by becoming stronger (making more myofilaments), chronic contraction by becoming shorter (losing sarcomeres in series), and stretching by becoming longer (adding sarcomeres in series). Myofilaments are actually long strands of proteins.arrow_forwardExplain the sliding filament theory of muscle contraction, including the following parts; thich (myosion) filaments, thin (actin) filaments, myosin heads, tropomyosin, troponin, ATP, active sites, calcium.arrow_forwardThe maximum amount of tension developed by a muscle fiber is when the sarcomeres are at their longest length. T/F + Justificationarrow_forward
- < The three main forces that act on the patella are shown on the diagram of the knee joint below. These forces are the quadriceps muscle force (FQ), the patella ligament force (FPL), and the patellofemoral joint reaction force (FPF). The angles a and ẞ are with respect to a line that is perpendicular to FPF. Assuming a = 15°, ẞ = 20°, and FQ = 3725 N, use equations for static equilibrium to calculate (a) FPL, and (b) FPF. (Hint: To solve this problem consider using a coordinate system that is aligned with the principal axes of the patella instead of the usual vertical and horizontal axes). (c) Many people assume FQ and FPL are always equal in magnitude but this is only true under certain circumstances. Under what conditions are FQ and FPL equal in magnitude? Fo FPF FP B GriffithUNIVERSITY Queensland Australiaarrow_forwardIf the muscle fiber is stretched to 150% of muscle length and thentechnically stimulated, what would be the total force measured?arrow_forwardIf your biceps brachii muscle attaches to your forearm 2 inches below your elbow, the distance from the elbow to the palm of your hand is 18 inches, and you lift a 20 pound weight, how much pull must your muscle exert to achieve elbow flexion? If your biceps brachii muscle attaches to your forearm 2 inches below your elbow, the distance from the elbow to the palm of your hand is 18 inches, and you lift a 20 pound weight, how much pull must your muscle exert to achieve elbow flexion? hhharrow_forward
- When utilizing microprocessor technology for testing muscle strength, you are typically looking at what form of muscle contraction? Concentric Isokinetic Isometric Eccentricarrow_forwardDraw a graph of the isometric force–length relationshipof striated muscle, indicating where maximal overlap betweenactin and myosin filaments occurs.arrow_forwardWhen discussing the hierarchy of skeletal muscle organization, the is the Highest level of organization and the the Smallest level of organization. O Fascicle : Muscle cell (AKA Myocyte, AKA myofiber) O Muscle belly: Muscle cell (AKA Myocyte, AKA myofiber) O Myofbril : Sarcomere O Sarcomere: Muscle belly O Muscle belly Sarcomere « Previous Next »arrow_forward
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