Study Guide with Student Solutions Manual and Problems Book for Garrett/Grisham's Biochemistry, 6th
6th Edition
ISBN: 9798214167343
Author: GARRETT
Publisher: Cengage Learning US
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Textbook Question
Chapter 6, Problem 3P
Answers to all problems are at the end of this book. Detailed solutions are available in the Student Solutions Manual, Study Guide, and Problems Book.
Assessing the Roles of Weak Forces Between Amino Acids in Proteins
Discuss the potential contributions to hydrophobic and van der Waals interactions and ionic and hydrogen bonds for the side chains of Asp, Leu, Tyr and His in a protein.
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Draw the predominant form of
glutamic acid at pH = 8.4. The pKa
of the side chain is 4.1. Include
proper stereochemistry.
HO
H2N
OH
pH = 8.4
How would I draw this?
Calculate the standard change in Gibbs free energy, AGrxn, for the given reaction at 25.0 °C. Consult the table of
thermodynamic properties for standard Gibbs free energy of formation values.
NH,Cl(s) →NH; (aq) + C1 (aq)
AGrxn
-7.67
Correct Answer
Determine the concentration of NH+ (aq) if the change in Gibbs free energy, AGrxn, for the reaction is -9.27 kJ/mol.
6.49
[NH+]
Incorrect Answer
kJ/mol
M
Chapter 6 Solutions
Study Guide with Student Solutions Manual and Problems Book for Garrett/Grisham's Biochemistry, 6th
Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...
Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...Ch. 6 - Answers to all problems are at the end of this...
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- draw in the structure of each amino acid (as L-amino acids) using the Fischer projection style. an example has been included. Draw the structure for glycine, alanine, valine, isoleucine, methionine, proline, phenylalanine, tryptophan, serine, threonine, asparagine, glutamine, lysine, arginine, aspartic acid, glutamic acid, histidine, tyrosine, cysteinearrow_forwarddraw in the structure of each amino acid (as L-amino acids) using the Fischer projection style. an example has been includedarrow_forwarddraw in the structure of each amino acid (as L-amino acids) using the Fischer projection style. an example has been includedarrow_forward
- Draw out the following peptide H-R-K-E-D at physiological pH (~7.4). Make sure toreference table 3.1 for pKa values.arrow_forwardThe table provides the standard reduction potential, E', for relevant half-cell reactions. Half-reaction E'° (V) Oxaloacetate² + 2H+ + 2e malate²- -0.166 Pyruvate + 2H+ + 2e → lactate -0.185 Acetaldehyde + 2H+ + 2e¯ →→→ ethanol -0.197 NAD+ + H+ + 2e--> NADH -0.320 NADP+ + H+ + 2e →→ NADPH Acetoacetate + 2H+ + 2e¯ - -0.324 B-hydroxybutyrate -0.346 Which of the reactions listed would proceed in the direction shown, under standard conditions, in the presence of the appropriate enzymes? Malate + NAD+ oxaloacetate + NADH + H+ Malate + pyruvate oxaloacetate + lactate Pyruvate + NADH + H+ lactate + NAD+ Pyruvate + p-hydroxybutyrate lactate + acetoacetate Acetaldehyde + succinate ethanol + fumerate Acetoacetate + NADH + H+ → B-hydroxybutyrate + NAD+arrow_forwardArrange the four structures in order from most reduced to most oxidized. Most reduced R-CH2-CH3 R-CH2-CH₂-OH R-CH,-CHO R-CH₂-COO Most oxidizedarrow_forward
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