ENGINEERING CIRCUIT...(LL)>CUSTOM PKG.<
9th Edition
ISBN: 9781260540666
Author: Hayt
Publisher: MCG CUSTOM
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Chapter 6, Problem 28E
(a)
To determine
Design the required op amp circuit to meet the given conditions.
(b)
To determine
Verify the circuit design by analyzing the final circuit.
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For circuit shown, use Mesh method to find the voltage Vo as follows. Enter, in the matrix format, as
below, the loop currents, where row 1, and row 2, correspond to i₁, and i2 loop current expressions,
respectively. Let Vs1-5, Vs2-15, R₁=5, R₂=2, and R3=8.
The matrix values are shown here:
[R11 R12 21
R21 R22
Rx - M - M
iz
=
The relative tolerance for this problem is 5%.
Vst
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R1
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Loop i₁
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G12
V₁ =
Loop 12
R21
R22
V₂=
Ω
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V
Ω
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V
R₂
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VS2
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Ry
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Vo
Use Cramer's rule (matrix), substitution, or any other method to calculate the voltages:
=
=
For the circuit shown, let V, 15 V, I, 4A, R₁ =5, R₂ 10, R3 10, and R4 5. Determine the output
voltage Vo as follows All resistor values are in ohms.
1. Identify the supermesh and write its corresponding Mesh equation. Provide your expression in terms
of the shown mesh current i₁, and 12 of the form (R11 · 11+ R12 · 12 = V₁), then enter the
corresponding values:
R11
Ω
R12
V₁=
V
Ω
2. Use the above equation, and supermesh inner expression to calculate i₂:
i₂-
Find Vo
V₁ =
A
V
R₁
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M
R3
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V
R4
V₁
0
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R₁
The relative tolerance for this problem is 7 %.
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11.18 In the circuit of Fig. P11.18, what should the value of thecoupling coefficient k be so that Vout/Vin = 0.49?
Chapter 6 Solutions
ENGINEERING CIRCUIT...(LL)>CUSTOM PKG.<
Ch. 6.2 - Derive an expression for vout in terms of vin for...Ch. 6.2 - Prob. 2PCh. 6.3 - An historic bridge is showing signs of...Ch. 6.4 - Design a circuit that provides a 12 V output if a...Ch. 6.4 - Design a noninverting Schmitt trigger that that...Ch. 6.5 - Assuming a finite open-loop gain (A), a finite...Ch. 6.5 - Use SPICE to simulate a voltage follower using an...Ch. 6 - For the op amp circuit shown in Fig. 6.39,...Ch. 6 - FIGURE 6.39 Determine the power dissipated by a...Ch. 6 - For the circuit of Fig. 6.40, calculate vout if...
Ch. 6 - For the circuit in Fig. 6.40, find the values of...Ch. 6 - (a) Design a circuit which converts a voltage...Ch. 6 - Prob. 6ECh. 6 - For the circuit of Fig. 6.40, R1 = RL = 50 ....Ch. 6 - Prob. 8ECh. 6 - (a) Design a circuit using only a single op amp...Ch. 6 - Prob. 11ECh. 6 - Determine the output voltage v0 and the current...Ch. 6 - Prob. 13ECh. 6 - Prob. 14ECh. 6 - Prob. 15ECh. 6 - Prob. 16ECh. 6 - Consider the amplifier circuit shown in Fig. 6.46....Ch. 6 - Prob. 18ECh. 6 - Prob. 19ECh. 6 - Prob. 20ECh. 6 - Referring to Fig. 6.49, sketch vout as a function...Ch. 6 - Repeat Exercise 21 using a parameter sweep in...Ch. 6 - Obtain an expression for vout as labeled in the...Ch. 6 - Prob. 24ECh. 6 - Prob. 25ECh. 6 - Prob. 26ECh. 6 - Prob. 27ECh. 6 - Prob. 28ECh. 6 - Prob. 29ECh. 6 - Prob. 30ECh. 6 - Prob. 31ECh. 6 - Determine the value of Vout for the circuit in...Ch. 6 - Calculate V0 for the circuit in Fig. 6.55. FIGURE...Ch. 6 - Prob. 34ECh. 6 - The temperature alarm circuit in Fig. 6.56...Ch. 6 - Prob. 36ECh. 6 - For the circuit depicted in Fig. 6.57, sketch the...Ch. 6 - For the circuit depicted in Fig. 6.58, (a) sketch...Ch. 6 - For the circuit depicted in Fig. 6.59, sketch the...Ch. 6 - In digital logic applications, a +5 V signal...Ch. 6 - Using the temperature sensor in the circuit in...Ch. 6 - Examine the comparator Schmitt trigger circuit in...Ch. 6 - Design the circuit values for the single supply...Ch. 6 - For the instrumentation amplifier shown in Fig....Ch. 6 - A common application for instrumentation...Ch. 6 - (a) Employ the parameters listed in Table 6.3 for...Ch. 6 - Prob. 49ECh. 6 - For the circuit of Fig. 6.62, calculate the...Ch. 6 - Prob. 51ECh. 6 - FIGURE 6.63 (a) For the circuit of Fig. 6.63, if...Ch. 6 - The difference amplifier circuit in Fig. 6.32 has...Ch. 6 - Prob. 55ECh. 6 - Prob. 56ECh. 6 - Prob. 57ECh. 6 - Prob. 58ECh. 6 - Prob. 59ECh. 6 - Prob. 60ECh. 6 - A fountain outside a certain office building is...Ch. 6 - For the circuit of Fig. 6.44, let all resistor...
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