Explanation The estimated speed is 60 mi / h , density 45.24 pc / mi / ln is level of service is LOS E . Given: The lane width is 11 ft . The speed limit is 55 mi / h . The traffic during peak hour is 720 cars , 56 STs, 24 TTs . Formula Used: Write the expression for total number of vehicle. Total vehicles = Passenger cars + SUT + TTs …… (I) Here, SUT is the single unit truck and TTs is the tractor-trailers. Write the expression for estimated free flow speed. B F F S = speed limit + 5 mi/h …… (II) Here, B F F S is the estimated free flow speed. Write the expression for the free flow speed. F F S = B F F S − f LW − f TLC − f M − f A …… (III) Here, F F S is the free flow speed, B F F S is the free flow sped for base condition, f LW is the adjustment for lane width, f TLC is the adjustment for total lateral clearance, f M if the adjustment for median type and f A is the adjustment for number of access points. Write the expression for the analysis flow rate. v p = V 15 × 4 N × f HV …… (IV) Here, v p is the flow rate, V is the hourly volume, P H F is the peak hour factor, N is the number of lanes and f HV is the heavy vehicle adjustment factor. Write the expression for the heavy vehicle adjustment factor. f HV = 1 1 + P T ( E T − 1 ) …… (V) Here, P T is the proportion of the heavy vehicles and E T is the passenger car equivalent for heavy vehicles. Write the expression for capacity at peak hour. c = Min [ 1900 + 20 ( F F S − 45 ) , 2300 ] …… (VI) Here, c is the capacity and F F S is the free flow speed. Write the expression for average speed. S = F F S − ( F F S − c 45 ) ( v p − 1400 ) 1.31 ( c − 1400 ) 1.31 …… (VII) Write the expression for density of traffic stream. D = v p S …… (VIII) Here, D is density and S is the average passenger car speed. Calculation: Substitute 720 for Passenger cars , 56 for SUTs and 24 for TTs in equation (1). Total vehicles = 720 + 56 + 24 = 800 Substitute 55 mi / h for speed limit in equation (II). B F F S = 55 mi / h + 5 mi / h = 60 mi / h Refer Table 6.3 “Adjustment of the lane width” of the book “Principles of Highway Engineering and traffic, 6 th Edition. The f LW for lane width 11 ft is 1.9 mi / h . Refer Table 6.11 “Adjustment of lateral clearance” of the book “Principles of Highway Engineering and traffic, 6 th Edition. The f TLC for no shoulderis 1.3 mi / h . Refer Table 6.12 “Adjustment of median type” of the book “Principles of Highway Engineering and traffic, 6 th Edition.” The f M for undivided highwayis 1.6 mi / h . Refer Table 6.13 “Adjustment of access point frequency” of the book “Principles of Highway Engineering and traffic, 6 th Edition.” The reduction in free flow speed for 20 access points per mile is 5.0 . The reduction in free flow speed for 10 access points per mile is 2.5 . Calculate the reduction in free flow speed for 17 access points per mile using interpolation. x = 5.0 − ( 20 − 17 ) ( 5.0 − 2.5 ) ( 20 − 10 ) = 5.0 − 0.75 = 4.25 Substitute 4.25 mi / h for f A , 1.6 mi / h for f M , 1.3 mi / h for f TLC , 1.9 mi / h for f LW and 60 mi/h for B F F S in equation (III)

The estimated speed, density and level of service of highway.

PRINCIPLES OF HIGHWAY ENGINEERING+TRAFF

7th Edition

ISBN: 9781119688372

Author: Mannering

Publisher: WILEY

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The estimated speed, density and level of service of highway.

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