Explanation Given: The free flow speed is 45 mi/h . The directional traffic flow is 1300 . The percent of heavy vehicle is 8 % . The peak hour factor is 0.85 . Formula Used: Write the expression for the analysis flow rate. v p = V P H F × N × f HV × f p …… (I) Here, v p is the flow rate, V is the peak hour volume, P H F is the peak hour factor, f p is the adjustment factor and f HV is the heavy vehicle adjustment factor. Write the expression for the heavy vehicle adjustment factor. f HV = 1 1 + P T ( E T − 1 ) + P R ( E R − 1 ) …… (II) Here, D is the directional distribution factor, and AADT is the average annual daily traffic. Write the expression for number of vehicle can be added. n = V − V prev …… (III) Here, n is the number of vehicle Calculation: Refer Table 6.16 “Passenger car equivalent of heavy vehicles for average travel speed and time spent “Principles of Highway Engineering and traffic, 6 th Edition”. The value of E T for directional flow rate 1300 is 1.5 . Refer Table 6.16 “Passenger car equivalent of heavy vehicles for average travel speed and time spent “Principles of Highway Engineering and traffic, 6 th Edition”. The value of E R for directional flow rate 1300 is 1.2