Chapter 6, Problem 22PP

Interpretation Introduction

Interpretation:

The correct value of $\Delta G$ which corresponds with $K_{eq}=1$ has to be determined from the given values of $\Delta G$

Concept introduction:

The Gibbs free energy or the free energy change is a thermodynamic quantity represented by $\Delta G$. The expression for the free energy change with respect to the $K_{eq}$ is written below,

 $\text{ΔG}={\text{-RTlnK}}_{\text{eq}}$  where, R is the gas constant, T is the temperature in Kelvin.

Sample values of $\Delta G$ and corresponding $K_{eq}$ are mentioned in the below table.

$\begin{array}{ccc}{\text{ΔG}}^{\text{0}}\left(\text{KJ/mol}\right)& {\text{K}}_{\text{eq}}& \text{\%}\text{Products}\text{at}\text{equilibrium}\\ \text{-17}& {\text{10}}^{\text{3}}& \text{99}\text{.9\%}\\ \text{-11}& {\text{10}}^{\text{2}}& \text{99\%}\\ \text{-6}& {\text{10}}^{\text{1}}& \text{90\%}\\ \text{0}& \text{1}& \text{50\%}\end{array}$