Chapter 6, Problem 19PP

(a)

Interpretation Introduction

Interpretation:

Bond-dissociation energy should be identified for the red line bond in the given structure.

Concept introduction:

Bond-dissociation energy (BDE) is determined from the strength of a single chemical bond.

Bond-dissociation energy is mainly depends on the hybridization of the carbon atom and substitution on the carbon atom

It is also determined by the electronegativity of the molecule and polarization of the molecule to which carbon atom bonded with.

Sigma bond: A covalent bond formation is mainly due to end to end overlap of atomic orbitals.

Pi bond: A covalent bond formation is mainly due to side to side overlap of atomic orbitals

Electronegativity: The ability of an atom to attract electrons towards itself.

Polarization: A partial charge separation between the carbon and an other heteroatom due to its electronegativity difference.

Answer to Problem 19PP

Answer

The bond dissociation energy of the bonds in red line of the molecule (a) is given below

Carbon - carbon triple bond has more dissociation energy

Carbon - carbon triple bond has more dissociation energy than the carbon – carbon double bond and Carbon – carbon double bond more dissociation than the carbon – carbon single bond.

Explanation of Solution

To find: Bond-dissociation energy of the given compounds.

Draw the given molecule and analyze the nature of C-C bonds present in it.

The given molecule is drawn and it has three types of C-C bonds. They are $\text{C-}\text{C,C=C and C}\equiv \text{C}$.

Carbon – Carbon Single bond has less dissociation energy than carbon – carbon double bond and triple bond. Carbon – carbon triple bond (sp hybridization) has more dissociation energy because it consists of three bonds (two pi bonds and one sigma bond) so it requires more energy to break the bonds than the other carbon- carbon double bonds (one pi bonds and one sigma bond) and carbon – carbon single bond (only one sigma bond).

(b)

Interpretation Introduction

Interpretation:

Bond-dissociation energy should be identified for the red line bond in the given structure.

Concept introduction:

Bond-dissociation energy (BDE) is determined from the strength of a single chemical bond.

Bond-dissociation energy is mainly depends on the hybridization of the carbon atom and substitution on the carbon atom

It is also determined by the electronegativity of the molecule and polarization of the molecule to which carbon atom bonded with.

Sigma bond: A covalent bond formation is mainly due to end to end overlap of atomic orbitals.

Pi bond: A covalent bond formation is mainly due to side to side overlap of atomic orbitals

Electronegativity: The ability of an atom to attract electrons towards itself.

Polarization: A partial charge separation between the carbon and an other heteroatom due to its electronegativity difference.

Answer to Problem 19PP

Answer

C-F bond has more dissociation energy

Explanation of Solution

To find: Bond-dissociation energy of the given compounds.

Draw the given molecule and analyze the nature of C-C bonds present in it.

The given molecule is drawn and it has four types of C-C bonds. They are $\text{C-}\text{F, C-}\text{Cl,}\text{C-}\text{Br}\text{and}\text{C-}\text{I}$.

Bond dissociation energy depends on the electronegativity of the molecule and polarization of the molecule. If the molecule has high electronegativity (less polarizability) the dissociation energy of the molecule is high.

The electronegativity order in the halogen series given below

$\text{C-F }\text{>}\text{ C-Cl }\text{>}\text{ C-Br }\text{>}\text{ C-I}\text{.}$

C-F has more Bond dissociation energy in the given molecule since it has more electronegativity than the other halogen atoms.