
a)
Interpretation:
R and S configuration is to be assigned to the following molecules.
Concept introduction:
Rule 1:
a) Higher
b) An atom node duplicated closer to the root ranks higher than one duplicated further.
Rule 2: Higher
Rule 3: Z precedes E and this precedes nonstereogenic (nst) double bonds.
Rule 4:
a) Chiral stereogenic units precede pseudoasymmetric stereogenic units and these precede nonstereogenic units (R = S > r = s > nst).
b) When two ligards have different descriptor pairs, the one with the first chosen like descriptor pairs has priority over the one with a corresponding unlike descriptor pairs.
c) r precedes s.
Rule 5: An atom or group with descriptor R has priority over its enantiomorph S.

Answer to Problem 43AP
R configuration
Explanation of Solution
By ranking the substituent in the following examples based on Cahn-Ingold Prelog rules,
R and S configuration can be assigned to the following molecules.
1. Determine the priorities of the four attached groups from highest (1) to lowest (4).
This is the same as in all methods.
2. Draw the steering wheel. Draw a curved arrow around from 1 to 2 to 3 and back to 1 and note which direction this arrow goes, clockwise (cw) or counterclockwise (ccw).
This distinct feature of this method is that you make a full circle, from 1 to 2 to 3 to 1, completely ignoring the lowest priority group.
3a. If the lowest priority group is behind the steering wheel, then this is the standard orientation: clockwise is R and counter-clockwise is S. (Turning the steering wheel clockwise turns the car to the right-R).
Note that Fischer projections are best depicted as bow ties with horizontal groups coming out and vertical groups back from the central carbon atom.
3b. If the lowest priority group is in front of this curved arrow, then the assignment is reversed: clockwise is S and counterclockwise is R. (Basically, you are looking at the steering wheel from the perspective of the engine compartment!)
The stereochemical configuration of a carbon atom can be specified as either R (rectus) or S (sinister) by using the Cahn-Ingold-Prelog sequence rules. First assign priorities to the four substituents on the chiral carbon atom, and then orient the molecule so that the lowest-priority group points directly back. If a curved arrow drawn in the direction of decreasing priority (1 → 2 → 3) for the remaining three groups is clockwise, the chirality center has the R configuration. If the direction is counterclockwise, the chirality center has the S configuration.
b)
Interpretation:
R and S configuration is to be assigned to the following molecules.
Concept introduction:
Rule 1:
a) Higher atomic number precedes lower.
b) An atom node duplicated closer to the root ranks higher than one duplicated further.
Rule 2: Higher atomic mass number precedes lower.
Rule 3: Z precedes E and this precedes nonstereogenic (nst) double bonds.
Rule 4:
a) Chiral stereogenic units precede pseudoasymmetric stereogenic units and these precede nonstereogenic units (R = S > r = s > nst).
b) When two ligards have different descriptor pairs, the one with the first chosen like descriptor pairs has priority over the one with a corresponding unlike descriptor pairs.
c) r precedes s.
Rule 5: An atom or group with descriptor R has priority over its enantiomorph S.

Answer to Problem 43AP
S configuration
Explanation of Solution
By ranking the substituent in the following examples based on Cahn-Ingold Prelog rules,
R and S configuration can be assigned to the following molecules.
1. Determine the priorities of the four attached groups from highest (1) to lowest (4).
This is the same as in all methods.
2. Draw the steering wheel. Draw a curved arrow around from 1 to 2 to 3 and back to 1 and note which direction this arrow goes, clockwise (cw) or counterclockwise (ccw).
This distinct feature of this method is that you make a full circle, from 1 to 2 to 3 to 1, completely ignoring the lowest priority group.
3a. If the lowest priority group is behind the steering wheel, then this is the standard orientation: clockwise is R and counter-clockwise is S. (Turning the steering wheel clockwise turns the car to the right-R).
Note that Fischer projections are best depicted as bow ties with horizontal groups coming out and vertical groups back from the central carbon atom.
3b. If the lowest priority group is in front of this curved arrow, then the assignment is reversed: clockwise is S and counterclockwise is R. (Basically, you are looking at the steering wheel from the perspective of the engine compartment!)
The stereochemical configuration of a carbon atom can be specified as either R (rectus) or S (sinister) by using the Cahn-Ingold-Prelog sequence rules. First assign priorities to the four substituents on the chiral carbon atom, and then orient the molecule so that the lowest-priority group points directly back. If a curved arrow drawn in the direction of decreasing priority (1 → 2 → 3) for the remaining three groups is clockwise, the chirality center has the R configuration. If the direction is counterclockwise, the chirality center has the S configuration.
c)
Interpretation:
R and S configuration is to be assigned to the following molecules.
Concept introduction:
Rule 1:
a) Higher atomic number precedes lower.
b) An atom node duplicated closer to the root ranks higher than one duplicated further.
Rule 2: Higher atomic mass number precedes lower.
Rule 3: Z precedes E and this precedes nonstereogenic (nst) double bonds.
Rule 4:
a) Chiral stereogenic units precede pseudoasymmetric stereogenic units and these precede nonstereogenic units (R = S > r = s > nst).
b) When two ligards have different descriptor pairs, the one with the first chosen like descriptor pairs has priority over the one with a corresponding unlike descriptor pairs.
c) r precedes s.
Rule 5: An atom or group with descriptor R has priority over its enantiomorph S.

Answer to Problem 43AP
S configuration
Explanation of Solution
By ranking the substituent in the following examples based on Cahn-Ingold Prelog rules,
R and S configuration can be assigned to the following molecules.
1. Determine the priorities of the four attached groups from highest (1) to lowest (4).
This is the same as in all methods.
2. Draw the steering wheel. Draw a curved arrow around from 1 to 2 to 3 and back to 1 and note which direction this arrow goes, clockwise (cw) or counterclockwise (ccw).
This distinct feature of this method is that you make a full circle, from 1 to 2 to 3 to 1, completely ignoring the lowest priority group.
3a. If the lowest priority group is behind the steering wheel, then this is the standard orientation: clockwise is R and counter-clockwise is S. (Turning the steering wheel clockwise turns the car to the right-R).
Note that Fischer projections are best depicted as bow ties with horizontal groups coming out and vertical groups back from the central carbon atom.
3b. If the lowest priority group is in front of this curved arrow, then the assignment is reversed: clockwise is S and counterclockwise is R. (Basically, you are looking at the steering wheel from the perspective of the engine compartment!)
The stereochemical configuration of a carbon atom can be specified as either R (rectus) or S (sinister) by using the Cahn-Ingold-Prelog sequence rules. First assign priorities to the four substituents on the chiral carbon atom, and then orient the molecule so that the lowest-priority group points directly back. If a curved arrow drawn in the direction of decreasing priority (1 → 2 → 3) for the remaining three groups is clockwise, the chirality center has the R configuration. If the direction is counterclockwise, the chirality center has the S configuration.
Want to see more full solutions like this?
Chapter 5 Solutions
Organic Chemistry
- Germanium (Ge) is a semiconductor with a bandgap of 2.2 eV. How could you dope Ge to make it a p-type semiconductor with a larger bandgap? Group of answer choices It is impossible to dope Ge and have this result in a larger bandgap. Dope the Ge with silicon (Si) Dope the Ge with gallium (Ga) Dope the Ge with phosphorus (P)arrow_forwardWhich of the following semiconductors would you choose to have photons with the longest possible wavelengths be able to promote electrons to the semiconductor's conduction band? Group of answer choices Si Ge InSb CdSarrow_forwardWhich of the following metals is the only one with all of its bands completely full? Group of answer choices K Na Ca Alarrow_forward
- 2. Specify the solvent and reagent(s) required to carry out each of the following FGI. If two reagent sets must be used for the FGI, specify the solvent and reagent(s) for each reagent set. If a reaction cannot be carried out with reagents (sets) class, write NP (not possible) in the solvent box for reagent set #1. Use the letter abbreviation for each solvent; use a number abbreviation for reagent(s). Solvents: CH2Cl2 (A); Reagents: H₂O (B); CH3CO₂H (D) NaHCO3 (4); Hg(OAc)2 (5); HBr (1); R₂BH (6); H2SO4 (2); CH3OH (C); Br₂ (3); H₂O₂ / HO- (7); NaBH4 (8) Reagent Set #1 Reagent Set #2 FGI OH - α-α Br + enant Solvent Reagent(s) Solvent Reagent(s)arrow_forwardBased on concepts from Lecture 3-5, which of the following ionic compounds should be most soluble in water? Group of answer choices MgO BeO CaO BaOarrow_forwardFrom an energy standpoint, which two process - in the correct order - are involved in the dissolving of an ionic compound crystal? Group of answer choices Water coordination to the ions followed by sublimation into the gas phase Sublimation of the crystal into gas-phase ions followed by water coordination to the ions Ion dissociation from the crystal followed by water coordination to the ions Water coordination to the ions followed by ion dissociation from the crystalarrow_forward
- For which Group 2 metal (M), is this process the most exothermic? M2+(g) + O2−(g) + CO2(g) → MO(s) + CO2(g) Group of answer choices M = Sr M = Mg M = Ca M = Baarrow_forward2. Specify the solvent and reagent(s) required to carry out each of the following FGI. If two reagent sets must be used for the FGI, specify the solvent and reagent(s) for each reagent set. If a reaction cannot be carried out with reagents (sets) class, write NP (not possible) in the solvent box for reagent set #1. Use the letter abbreviation for each solvent; use a number abbreviation for reagent(s). Solvents: CH2Cl2 (A); H₂O (B); Reagents: HBr (1); H2SO4 (2); CH3OH (C); Br₂ (3); CH3CO₂H (D) NaHCO3 (4); Hg(OAc)2 (5); R₂BH (6); H₂O₂ / HO- (7); NaBH4 (8) Reagent Set #1 Reagent Set #2 FGI Solvent Reagent(s) Solvent Reagent(s) HO OHarrow_forwardFor which of the following ionic compounds would you expect the smallest difference between its theoretical and experimental lattice enthalpies? (You may assume these all have the same unit cell structure.) Electronegativities: Ca (1.0), Fe (1.8), Mg (1.2), O (3.5), S (2.5), Zn (1.6) Group of answer choices ZnO MgS CaO FeSarrow_forward
- In the Born-Haber cycle for KCl crystal formation, what enthalpy component must be divided by two? Group of answer choices KCl(s) enthalpy of formation Ionization energy for K(g) K(s) sublimation enthalpy Cl2 bond dissociation enthalpyarrow_forward2. Specify the solvent and reagent(s) required to carry out each of the following FGI. If two reagent sets must be used for the FGI, specify the solvent and reagent(s) for each reagent set. If a reaction cannot be carried out with reagents (sets) class, write NP (not possible) in the solvent box for reagent set #1. Use the letter abbreviation for each solvent; use a number abbreviation for reagent(s). Solvents: CH2Cl2 (A); H₂O (B); Reagents: HBr (1); R₂BH (6); H2SO4 (2); CH3OH (C); Br₂ (3); CH3CO₂H (D) NaHCO3 (4); Hg(OAc)2 (5); H₂O₂ / HO (7); NaBH4 (8) Reagent Set #1 Reagent Set #2 FGI хот Br Solvent Reagent(s) Solvent Reagent(s)arrow_forwardWhat is the correct chemical equation for the lattice formation reaction for CaBr2? Group of answer choices Ca2+(g) + 2 Br−(g) → CaBr2(s) ½ Ca2+(g) + Br−(g) → ½ CaBr2(s) Ca(s) + Br2(l) → CaBr2(s) Ca(s) + 2 Br−(g) → CaBr2(s)arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning

