Chapter 5.7, Problem 2RCF

Interpretation Introduction

Interpretation:

The given gases which one is effuses faster has to be determined.

Concept Introduction:

Graham's law of effusion expressed as the rates of effusion of two different gases vary inversely as the square roots of the mass of their particles.

The rate of effusion is the number of molecules passing through a porous barrier in a given time.  The longer it takes, the slower the rate of effusion.

Using given Equation we find the molar mass of unknown gas

$\frac{{\text{r}}_2}{{\text{r}}_1}\text{=}\frac{{\text{t}}_{\text{1}}}{{\text{t}}_{\text{2}}}\sqrt{\frac{{\text{M}}_{\text{2}}}{{\text{M}}_{\text{1}}}}$

Where $\text{Rate}\text{1 and Rate}\text{2 }$ are the rates of the two gases and

${\text{M}}_{\text{1}}{\text{ and M}}_{\text{2}}$ are their respective relative molar masses.