Analysis of the given code: The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

Question

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Answer 1

Question

Chapter 5.5, Problem 5.5CP

A)

Program Plan Intro

Analysis of the given code:

The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

B)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “v” variable once. The process is carried out using a “do…while” loop with a “v” variable initially assigned as “10” and the loop iterates when the value of “v” is lesser than “5”.

C)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “value” and “count” variable after performing mathematical operations. The process is carried out by defining and declaring the necessary variables and by using a “do…while” loop that iterates to add the value of “number” by “2” and increment the value of the “counter” by “1”, when the value of “count” is less than “limit”. Final process is to display the values of the variables “number” and “count”.

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#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…

Answer 2

Question

Chapter 5.5, Problem 5.5CP

A)

Program Plan Intro

Analysis of the given code:

The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

B)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “v” variable once. The process is carried out using a “do…while” loop with a “v” variable initially assigned as “10” and the loop iterates when the value of “v” is lesser than “5”.

C)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “value” and “count” variable after performing mathematical operations. The process is carried out by defining and declaring the necessary variables and by using a “do…while” loop that iterates to add the value of “number” by “2” and increment the value of the “counter” by “1”, when the value of “count” is less than “limit”. Final process is to display the values of the variables “number” and “count”.

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Answer 3

Question

Chapter 5.5, Problem 5.5CP

A)

Program Plan Intro

Analysis of the given code:

The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

B)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “v” variable once. The process is carried out using a “do…while” loop with a “v” variable initially assigned as “10” and the loop iterates when the value of “v” is lesser than “5”.

C)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “value” and “count” variable after performing mathematical operations. The process is carried out by defining and declaring the necessary variables and by using a “do…while” loop that iterates to add the value of “number” by “2” and increment the value of the “counter” by “1”, when the value of “count” is less than “limit”. Final process is to display the values of the variables “number” and “count”.

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Answer 4

Question

Chapter 5.5, Problem 5.5CP

A)

Program Plan Intro

Analysis of the given code:

The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

B)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “v” variable once. The process is carried out using a “do…while” loop with a “v” variable initially assigned as “10” and the loop iterates when the value of “v” is lesser than “5”.

C)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “value” and “count” variable after performing mathematical operations. The process is carried out by defining and declaring the necessary variables and by using a “do…while” loop that iterates to add the value of “number” by “2” and increment the value of the “counter” by “1”, when the value of “count” is less than “limit”. Final process is to display the values of the variables “number” and “count”.

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Answer 5

Chapter 5.5, Problem 5.5CP

A)

Program Plan Intro

Analysis of the given code:

The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

B)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “v” variable once. The process is carried out using a “do…while” loop with a “v” variable initially assigned as “10” and the loop iterates when the value of “v” is lesser than “5”.

C)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “value” and “count” variable after performing mathematical operations. The process is carried out by defining and declaring the necessary variables and by using a “do…while” loop that iterates to add the value of “number” by “2” and increment the value of the “counter” by “1”, when the value of “count” is less than “limit”. Final process is to display the values of the variables “number” and “count”.

Answer 6

Chapter 5.5, Problem 5.5CP

A)

Program Plan Intro

Analysis of the given code:

The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

Answer 7

Chapter 5.5, Problem 5.5CP

A)

Program Plan Intro

Analysis of the given code:

The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

Answer 8

B)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “v” variable once. The process is carried out using a “do…while” loop with a “v” variable initially assigned as “10” and the loop iterates when the value of “v” is lesser than “5”.

Answer 9

B)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “v” variable once. The process is carried out using a “do…while” loop with a “v” variable initially assigned as “10” and the loop iterates when the value of “v” is lesser than “5”.

Answer 10

C)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “value” and “count” variable after performing mathematical operations. The process is carried out by defining and declaring the necessary variables and by using a “do…while” loop that iterates to add the value of “number” by “2” and increment the value of the “counter” by “1”, when the value of “count” is less than “limit”. Final process is to display the values of the variables “number” and “count”.

Answer 11

C)

Program Plan Intro

Analysis of the given code:

The given code is used to print the value of “value” and “count” variable after performing mathematical operations. The process is carried out by defining and declaring the necessary variables and by using a “do…while” loop that iterates to add the value of “number” by “2” and increment the value of the “counter” by “1”, when the value of “count” is less than “limit”. Final process is to display the values of the variables “number” and “count”.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

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Analysis of the given code: The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

Concept explainers

Analysis of the given code:

The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

Analysis of the given code:

The given code is used to print the value of “v” variable once. The process is carried out using a “do…while” loop with a “v” variable initially assigned as “10” and the loop iterates when the value of “v” is lesser than “5”.

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Chapter 5 Solutions

Analysis of the given code: The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

Concept explainers

Analysis of the given code: The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

Analysis of the given code: The given code is used to print the value of “v” variable once. The process is carried out using a “do…while” loop with a “v” variable initially assigned as “10” and the loop iterates when the value of “v” is lesser than “5”.

Want to see the full answer?

Chapter 5 Solutions

Analysis of the given code:

The given code is used to print the display statement once. The process is carried out using a “do…while” loop with a “counter” variable initially assigned as “10” and the loop iterates when the value of “counter” is lesser than “1”.

Analysis of the given code:

The given code is used to print the value of “v” variable once. The process is carried out using a “do…while” loop with a “v” variable initially assigned as “10” and the loop iterates when the value of “v” is lesser than “5”.