Organic Chemistry: Structure and Function
Organic Chemistry: Structure and Function
8th Edition
ISBN: 9781319079451
Author: K. Peter C. Vollhardt, Neil E. Schore
Publisher: W. H. Freeman
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Chapter 5.3, Problem 5.9E

(a)

Interpretation Introduction

Interpretation: The structure of the substituent (methyl, bromomethyl, trichloromethyl and ethyl)needs to be determined and they need to be arranged in descending priority order.

Concept Introduction: The priority number of groups is decided by the atomic number. Highest atomic number group gets the highest priority number. Hydrogen atom gets the lowest priority number.

(b)

Interpretation Introduction

Interpretation:The structures of the substituents 2-methyl-propyl (isobutyl), 1-methylethyl (isopropyl), cyclohexyl)need to be drawn and they need to be arranged in descending priority order.

Concept Introduction: The priority number of groups is decided by the atomic number. Highest atomic number group gets the highest priority number. Hydrogen atom gets the lowest priority number.

(c)

Interpretation Introduction

Interpretation: The structures of the substituents butyl, 1-methylpropyl (sec-butyl), 2-methylpropyl (isobutyl), 1,1-dimethylethyl (tert-butyl) needs to be drawn and they should be arranged descending priority order.

Concept Introduction:The priority number of groups is decided by the atomic number. Highest atomic number group gets the highest priority number. Hydrogen atom gets the lowest priority number.

(d)

Interpretation Introduction

Interpretation: The structures of the substituents ethyl, 1-chloroethyl, 1-bromoethyl, 2-bromoethyl needs to be drawn and they should be arranged in descending priority order.

Concept Introduction:The highest atomic number group has the highest priority and lowest atomic number gets the lowest priority number. Hydrogen atom gets the lowest priority.

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A complete tensile test was performed on a magnesium specimen of 12 mm diameter and 30 mm length, until breaking. The specimen is assumed to maintain a constant volume. Calculate the approximate value of the actual stress at breaking. TABLE. The tensile force F and the length of the specimen are represented for each L until breaking. F/N L/mm 0 30,0000 30,0296 5000 10000 30,0592 15000 30,0888 20000 30,15 25000 30,51 26500 30,90 27000 31,50 26500 32,10 25000 32,79
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