Organic Chemistry: Structure and Function
8th Edition
ISBN: 9781319079451
Author: K. Peter C. Vollhardt, Neil E. Schore
Publisher: W. H. Freeman
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Chapter 5.2, Problem 5.6E
(a)
Interpretation Introduction
Interpretation:The observed specific rotation of table sugar should be calculated and whether any information about the optical rotation for the enantiomer of natural sucrose is obtained from this calculation or not is to be determined.
Concept introduction:The formula to calculate specific rotation is given as follows:
Where,
The enantiomers are identical chemical compounds that have a mirror-image relationship to each other. The two enantiomers rotate the plane-polarized in opposite direction. This indicates one is dextrorotatory and one is levorotatory.
(b)
Interpretation Introduction
Interpretation: The observed specific rotation of
Concept introduction:The formula to calculate observed rotation from specific rotation is given as follows:
Where,
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Students have asked these similar questions
Part VII. The H-NMR of a compound with molecular formula C5 H 10 O2 is given below.
Find the following:
(a) The no. of protons corresponding to each signal in the spectra
(6) Give the structure of the compound and assign the signals to each
proton in the compound.
a
70.2
Integration Values
C5H10O2
b
47.7
C
46.5
d
69.5
3.6 3.5
3.4 3.3 3.2 3.1 3.0
2.9 2.8
2.7
2.6 2.5
2.4 2.3 2.2 2.1 2.0
Chemical Shift (ppm)
1.9
1.8
1.7 1.6
1.5
1.4 1.3 1.2
1.1 1.0
0.9 0.8
Part 111. 1 H-NMR spectrum of a compound with integration values in red is given below.
Answer the following:
(a) write the signals in the 'H-NMR spectrum to the corresponding protons on the structure
of the molecule below.
(b) Identify the theoretical multiplicities for each proton in the compound. Also give the possible.
complex splitting patterns assuming J values are not similar.
там
Br
22
2
3
6
4 7.2 7.0 6.8 6.6 6.4 6.2 6.0 5.8 5.6 5.4 5.2 5.0 4.8 4.6 4.4 4.2 4.0 3.8 3.6 3.4 3.2 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0
Chemical Shift (ppm)
ra.
Br
2
3
6
6
2.5
2.4
2.3
2.2
2.1
2.0
1.9
1.8
1.7
1.6
1.5
1.4
1.3
1.2
1.1
1.0
0.9
0.8
Chemical Shift (ppm)
2
2
Br
7.3
7.2
7.1
7.0 6.9
6.7 6.6 6.5
6.4
6.3
6.2
6.1
6.0
Chemical Shift (ppm)
5.9
5.8 5.7
5.5 5.4 5.3 5.2
5.0 4.9
1600°
1538°C
1493°C
In the diagram, the letter L indicates
that it is a liquid. Indicate its
components in the upper region
where only L is indicated.
The
iron-iron carbide phase
diagram.
Temperature (°C)
1400
8
1394°C
y+L
1200
2.14
y, Austenite
10000
912°C
800a
0.76
0.022
600
400
(Fe)
a, Ferrite
Composition (at% C)
15
1147°C
a + Fe3C
2
3
Composition (wt% C)
L
2500
4.30
2000
y + Fe3C
727°C
1500
Cementite (Fe3C)
1000
4
5
6
6.70
Temperature (°F)
Chapter 5 Solutions
Organic Chemistry: Structure and Function
Ch. 5.1 - Prob. 5.3ECh. 5.1 - Prob. 5.4ECh. 5.1 - Prob. 5.5ECh. 5.2 - Prob. 5.6ECh. 5.2 - Prob. 5.8TIYCh. 5.3 - Prob. 5.9ECh. 5.3 - Prob. 5.11TIYCh. 5.3 - Prob. 5.12ECh. 5.4 - Prob. 5.13ECh. 5.4 - Prob. 5.14E
Ch. 5.4 - Prob. 5.16TIYCh. 5.4 - Prob. 5.17ECh. 5.5 - Prob. 5.18ECh. 5.5 - Prob. 5.19ECh. 5.5 - Prob. 5.20ECh. 5.6 - Prob. 5.21ECh. 5.6 - Prob. 5.22ECh. 5.6 - Prob. 5.23ECh. 5.7 - Prob. 5.24ECh. 5.7 - Prob. 5.26TIYCh. 5.7 - Prob. 5.27ECh. 5 - Prob. 5.1ECh. 5 - Prob. 5.2ECh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 64PCh. 5 - Prob. 65PCh. 5 - Prob. 66PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71P
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