
(a)
Interpretation:The structures of two constitutional isomers of bromochloropropane formed upon radical bromination of
Concept introduction:The enantiomers are identical chemical compounds that have a mirror-image relationship to each other while diastereomers do not hold mirror image relationships. The former are chiral and optically active while the latter can be chiral or achiral.
Four kinds of symmetry elements that may be present are tabulated as follows:
Presence of any symmetry element makes molecule achiral and optically inactive.
(b)
Interpretation: The structures of all possible forms of dimethylcyclobutanes should be written, the chiral structures should be specified and mirror planes for achiral ones should be drawn.
Concept introduction: The enantiomers are identical chemical compounds that have a mirror-image relationship to each other while diastereomers do not hold mirror image relationships. The former are chiral and optically active while the latter can be chiral or achiral.
Any organic compound must have no plane of symmetry in order to be chiral or optically active. The compounds with any plane of symmetry are achiral and optically inactive.
Four kinds of symmetry elements that may be present are tabulated as follows:
Presence of any symmetry element makes molecule achiral and optically inactive.

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Chapter 5 Solutions
Organic Chemistry: Structure and Function
- Understanding the general acid-base properties of amino acids O Proteins Imagine each of the molecules shown below was found in an aqueous solution. Can you tell whether the solution is acidic, basic, or neutral? molecule The solution is... 010 H3N-CH-C-OH CH HO CH3 O acidic O basic neutral O (unknown) H3N HO 0 O acidic O basic neutral ○ (unknown) H3N-CH-C-O CH2 CH3-CH-CH3 O acidic O basic Oneutral ○ (unknown) O= X H2N-CH-C-O CH3 CH CH3 acidic O basic O neutral ○ (unknown) ? 000arrow_forwardImagine each of the molecules shown below was found in an aqueous solution. Can you tell whether the solution is acidic, basic, or neutral? molecule 0=0 H3N-CH-C-o HO CH2 OH The solution is... O acidic O basic O neutral O (unknown) H₂N acidic O basic O neutral ○ (unknown) + H3N O OH O acidic O basic O neutral O (unknown) H2N-CH-C-O CH3 O acidic O basic neutral ○ (unknown) X ? olo HEarrow_forwardRecognizing ampli Draw an a amino acid with a methyl (-CH3) side chain. Explanation Check Click and drag to start drawing a structure. X Carrow_forward
- Write the systematic name of each organic molecule: structure name × HO OH ☐ OH CI CI O CI OH OHarrow_forwardく Check the box under each a amino acid. If there are no a amino acids at all, check the "none of them" box under the table. Note for advanced students: don't assume every amino acid shown must be found in nature. COO H3N-C-H CH2 HO CH3 NH3 O CH3-CH CH2 OH Onone of them Explanation Check + H3N O 0. O OH + NH3 CH2 CH3-CH H2N C-COOH H O HIC + C=O H3N-C-O CH3- - CH CH2 OH Х 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accesarrow_forwardWrite the systematic name of each organic molecule: structure HO-C-CH2-CH3 O -OH CH3-CH2-CH2-CH2-CH2-C-OH CH3 CH3-CH-CH2-C-OH Explanation Check S namearrow_forward
- theres 2 productsarrow_forwardDraw the major product of this solvolysis reaction. Ignore any inorganic byproducts. + CH3CH2OH Drawing Q Atoms, Bonds and Rings OCH2CH3 || OEt Charges OH 00-> | Undo Reset | Br Remove Done Drag To Pan +arrow_forwardDraw the major product of this SN1 reaction. Ignore any inorganic byproducts. CH3CO2Na CH3CO2H Drawing + Br Q Atoms, Bonds and Rings OAC Charges OH ОАс Na ဂ Br Undo Reset Remove Done Drag To Pan +arrow_forward
- Organic Functional Groups entifying positions labeled with Greek letters in acids and derivatives 1/5 ssible, replace an H atom on the a carbon of the molecule in the drawing area with a ce an H atom on the ẞ carbon with a hydroxyl group substituent. ne of the substituents can't be added for any reason, just don't add it. If neither substi er the drawing area. O H OH Oneither substituent can be added. Check D 1 Accessibility ado na witharrow_forwardDifferentiate between electrophilic and nucleophilic groups. Give examples.arrow_forwardAn aldehyde/ketone plus an alcohol gives a hemiacetal, and an excess of alcohol gives an acetal. The reaction is an equilibrium; in aldehydes, it's shifted to the right and in ketones, to the left. Explain.arrow_forward
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