In Problems 39 and 40, explain why Theorem 2 cannot be used to conclude that a maximum or minimum value exists. Graph the feasible regions and use graphs of the objective function z = x − y for various values of z to discuss the existence of a maximum value and a minimum value. Minimize and maximize z = x − y subject to x − 2 y ≤ 0 2 x − y ≤ 6 x , y ≥ 0
In Problems 39 and 40, explain why Theorem 2 cannot be used to conclude that a maximum or minimum value exists. Graph the feasible regions and use graphs of the objective function z = x − y for various values of z to discuss the existence of a maximum value and a minimum value. Minimize and maximize z = x − y subject to x − 2 y ≤ 0 2 x − y ≤ 6 x , y ≥ 0
Solution Summary: The author explains that theorem 2 cannot be used to conclude that a minimum or maximum value exists for the objective function z=x-y subject to constraints.
In Problems 39 and 40, explain why Theorem 2 cannot be used to conclude that a maximum or minimum value exists. Graph the feasible regions and use graphs of the objective function
z
=
x
−
y
for various values of
z
to discuss the existence of a maximum value and a minimum value.
Minimize and maximize
z
=
x
−
y
subject to
x
−
2
y
≤
0
2
x
−
y
≤
6
x
,
y
≥
0
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