To find :
Answer to Problem 103E
c. 0.02
Explanation of Solution
Given information : Test A has probability 0.9 of being positive if steroids have been used. Test B has probability 0.8 of being positive if steroids have been used.
Let A denote the
Let B denote the event that an athlete is given test B.
P(A)=0.9,P(B)=0.8
P(Aâ‹‚B' )=P(A' )P(B') (as A and B are independent)
=[1-P(A) ][1-P(B)]
=(1-0.9)(1-0.8)
=0.1(0.2)
=0.02
Option c.is correct
Chapter 5 Solutions
EBK PRACTICE OF STAT.F/AP EXAM,UPDATED
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