EBK PRACTICE OF STAT.F/AP EXAM,UPDATED
EBK PRACTICE OF STAT.F/AP EXAM,UPDATED
6th Edition
ISBN: 9781319287573
Author: Starnes
Publisher: MPS PUB
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Chapter 5.1, Problem 10E

(a)

To determine

To describe how to use a random generator to perform one trial of the simulation.

(a)

Expert Solution
Check Mark

Explanation of Solution

It is given that a professional tennis player claims to get 90% of her second serves in. Now, the probability of missing a second serve is 0.10 . So, we will carry out a simulation that 20 second serves. This implies,

  0.10=110

Since the probability of missing the second serve is 0.10 on each second serve, we expect about 1 out of 10 second serves to miss. Let us now use a random generator to randomly generate 20 digits from 0 to 9 , where zero represents a miss and the other digits represents no miss.

(b)

To determine

To explain what the dot at 6 represents.

(b)

Expert Solution
Check Mark

Answer to Problem 10E

One trial in the simulation where the player missed 6 of the 20 second serves.

Explanation of Solution

It is given that a professional tennis player claims to get 90% of her second serves in. And the dot plot is given which shows the number of serves missed in a simulated match of 20 second serves among 100 simulated matches. The dot at 6 represents one trial in the simulation where the player missed 6 of the 20 second serves.

(c)

To determine

To use the result of the simulation to estimate the probability that the player would miss five or more of her first 20 second serves in a match.

(c)

Expert Solution
Check Mark

Answer to Problem 10E

  0.06 .

Explanation of Solution

It is given that a professional tennis player claims to get 90% of her second serves in. And the dot plot is given which shows the number of serves missed in a simulated match of 20 second serves among 100 simulated matches. We then note that there are six dots at 5 and one dot at 6 in the dot plot which implies that 6 of the 100 simulated matches results in 5 or more misses of the second serves. Then,

  6100=0.06

We then implies that the probability of missing 5 or more of the first 20 second serves in a match is 0.06 .

(d)

To determine

To explain is there a convincing evidence that the player misses more than 10% of her second serves.

(d)

Expert Solution
Check Mark

Answer to Problem 10E

No, there is no convincing evidence.

Explanation of Solution

It is given that a professional tennis player claims to get 90% of her second serves in. And the dot plot is given which shows the number of serves missed in a simulated match of 20 second serves among 100 simulated matches. Thus, we have,

  10% of the 20 second serve is10%×20=0.10×20=2

We then note that there are many dots in the dot plot at 2 and to the left of 2 which implies that is very common to have less than 2 missed serves in a simulated match and thus it is very likely that the player misses at most 10% of her second serves. Thus there is not convincing evidence that the player misses more than 10% of her second serves.

Chapter 5 Solutions

EBK PRACTICE OF STAT.F/AP EXAM,UPDATED

Ch. 5.1 - Prob. 11ECh. 5.1 - Prob. 12ECh. 5.1 - Prob. 13ECh. 5.1 - Prob. 14ECh. 5.1 - Prob. 15ECh. 5.1 - Prob. 16ECh. 5.1 - Prob. 17ECh. 5.1 - Prob. 18ECh. 5.1 - Prob. 19ECh. 5.1 - Prob. 20ECh. 5.1 - Prob. 21ECh. 5.1 - Prob. 22ECh. 5.1 - Prob. 23ECh. 5.1 - Prob. 24ECh. 5.1 - Prob. 25ECh. 5.1 - Prob. 26ECh. 5.1 - Prob. 27ECh. 5.1 - Prob. 28ECh. 5.1 - Prob. 29ECh. 5.1 - Prob. 30ECh. 5.2 - Prob. 31ECh. 5.2 - Prob. 32ECh. 5.2 - Prob. 33ECh. 5.2 - Prob. 34ECh. 5.2 - Prob. 35ECh. 5.2 - Prob. 36ECh. 5.2 - Prob. 37ECh. 5.2 - Prob. 38ECh. 5.2 - Prob. 39ECh. 5.2 - Prob. 40ECh. 5.2 - Prob. 41ECh. 5.2 - Prob. 42ECh. 5.2 - Prob. 43ECh. 5.2 - Prob. 44ECh. 5.2 - Prob. 45ECh. 5.2 - Prob. 46ECh. 5.2 - Prob. 47ECh. 5.2 - Prob. 48ECh. 5.2 - Prob. 49ECh. 5.2 - Prob. 50ECh. 5.2 - Prob. 51ECh. 5.2 - Prob. 52ECh. 5.2 - Prob. 53ECh. 5.2 - Prob. 54ECh. 5.2 - Prob. 55ECh. 5.2 - Prob. 56ECh. 5.2 - Prob. 57ECh. 5.2 - Prob. 58ECh. 5.2 - Prob. 59ECh. 5.2 - Prob. 60ECh. 5.3 - Prob. 61ECh. 5.3 - Prob. 62ECh. 5.3 - Prob. 63ECh. 5.3 - Prob. 64ECh. 5.3 - Prob. 65ECh. 5.3 - Prob. 66ECh. 5.3 - Prob. 67ECh. 5.3 - Prob. 68ECh. 5.3 - Prob. 69ECh. 5.3 - Prob. 70ECh. 5.3 - Prob. 71ECh. 5.3 - Prob. 72ECh. 5.3 - Prob. 73ECh. 5.3 - Prob. 74ECh. 5.3 - Prob. 75ECh. 5.3 - Prob. 76ECh. 5.3 - Prob. 77ECh. 5.3 - Prob. 78ECh. 5.3 - Prob. 79ECh. 5.3 - Prob. 80ECh. 5.3 - Prob. 81ECh. 5.3 - Prob. 82ECh. 5.3 - Prob. 83ECh. 5.3 - Prob. 84ECh. 5.3 - Prob. 85ECh. 5.3 - Prob. 86ECh. 5.3 - Prob. 87ECh. 5.3 - Prob. 88ECh. 5.3 - Prob. 89ECh. 5.3 - Prob. 90ECh. 5.3 - Prob. 91ECh. 5.3 - Prob. 92ECh. 5.3 - Prob. 93ECh. 5.3 - Prob. 94ECh. 5.3 - Prob. 95ECh. 5.3 - Prob. 96ECh. 5.3 - Prob. 97ECh. 5.3 - Prob. 98ECh. 5.3 - Prob. 99ECh. 5.3 - Prob. 100ECh. 5.3 - Prob. 101ECh. 5.3 - Prob. 102ECh. 5.3 - Prob. 103ECh. 5.3 - Prob. 104ECh. 5.3 - Prob. 105ECh. 5.3 - Prob. 106ECh. 5.3 - Prob. 107ECh. 5.3 - Prob. 108ECh. 5 - Prob. R5.1RECh. 5 - Prob. R5.2RECh. 5 - Prob. R5.3RECh. 5 - Prob. R5.4RECh. 5 - Prob. R5.5RECh. 5 - Prob. R5.6RECh. 5 - Prob. R5.7RECh. 5 - Prob. R5.8RECh. 5 - Prob. T5.1SPTCh. 5 - Prob. T5.2SPTCh. 5 - Prob. T5.3SPTCh. 5 - Prob. T5.4SPTCh. 5 - Prob. T5.5SPTCh. 5 - Prob. T5.6SPTCh. 5 - Prob. T5.7SPTCh. 5 - Prob. T5.8SPTCh. 5 - Prob. T5.9SPTCh. 5 - Prob. T5.10SPTCh. 5 - Prob. T5.11SPTCh. 5 - Prob. T5.12SPTCh. 5 - Prob. T5.13SPTCh. 5 - Prob. T5.14SPT
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