Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN: 9780547587776
Author: HOLT MCDOUGAL
Publisher: HOLT MCDOUGAL
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Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
Units and Measurements
Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experime…
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Question
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Chapter 5.2, Problem 8C
To determine

To find: The sum or difference.

Expert Solution & Answer
Check Mark

Answer to Problem 8C

The sum of the equation −327−637 is −687 .

Explanation of Solution

Given information: −327−637.

Calculation:

Converting from mixed fraction to improper fraction,

=327=(7×3)+27=21+27=237......(1)

=637=(7×6)+37=42+37=457......(2)

Since both, 237 and 457 are negative number.

Adding improper fraction (1) and (2),

=−237−457=−23−457=−687 , Taking 7 as the LCM (Least common multiple)

Hence, The sum of the equation −327−637 is −687.

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Chapter 5.2, Problem 7C
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Chapter 5.2, Problem 1E

Chapter 5 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 5.1 - Prob. 1CCh. 5.1 - Prob. 2CCh. 5.1 - Prob. 3CCh. 5.1 - Prob. 4CCh. 5.1 - Prob. 5CCh. 5.1 - Prob. 1ECh. 5.1 - Prob. 2ECh. 5.1 - Prob. 3ECh. 5.1 - Prob. 4ECh. 5.1 - Prob. 5E
Ch. 5.1 - Prob. 6ECh. 5.1 - Prob. 7ECh. 5.1 - Prob. 8ECh. 5.1 - Prob. 9ECh. 5.1 - Prob. 10ECh. 5.1 - Prob. 11ECh. 5.1 - Prob. 12ECh. 5.1 - Prob. 13ECh. 5.1 - Prob. 14ECh. 5.1 - Prob. 15ECh. 5.1 - Prob. 16ECh. 5.1 - Prob. 17ECh. 5.1 - Prob. 18ECh. 5.1 - Prob. 19ECh. 5.1 - Prob. 20ECh. 5.1 - Prob. 21ECh. 5.1 - Prob. 22ECh. 5.1 - Prob. 23ECh. 5.1 - Prob. 24ECh. 5.1 - Prob. 25ECh. 5.1 - Prob. 26ECh. 5.1 - Prob. 27ECh. 5.1 - Prob. 28ECh. 5.1 - Prob. 29ECh. 5.1 - Prob. 30ECh. 5.1 - Prob. 31ECh. 5.1 - Prob. 32ECh. 5.1 - Prob. 33ECh. 5.1 - Prob. 34ECh. 5.1 - Prob. 35ECh. 5.1 - Prob. 36ECh. 5.1 - Prob. 37ECh. 5.1 - Prob. 38ECh. 5.1 - Prob. 39ECh. 5.1 - Prob. 40ECh. 5.1 - Prob. 41ECh. 5.1 - Prob. 42ECh. 5.1 - Prob. 43ECh. 5.1 - Prob. 44ECh. 5.1 - Prob. 45ECh. 5.1 - Prob. 46ECh. 5.1 - Prob. 47ECh. 5.1 - Prob. 48ECh. 5.1 - Prob. 49ECh. 5.1 - Prob. 50ECh. 5.1 - Prob. 51ECh. 5.1 - Prob. 52ECh. 5.1 - Prob. 53ECh. 5.1 - Prob. 54ECh. 5.1 - Prob. 55ECh. 5.1 - Prob. 56ECh. 5.1 - Prob. 57ECh. 5.1 - Prob. 58ECh. 5.1 - 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Prob. 48ECh. 5.7 - Prob. 49ECh. 5.7 - Prob. 50ECh. 5.7 - Prob. 51ECh. 5.7 - Prob. 52ECh. 5.7 - Prob. 53ECh. 5.7 - Prob. 54ECh. 5.7 - Prob. 55ECh. 5.7 - Prob. 56ECh. 5.7 - Prob. 57ECh. 5 - Prob. 1PSQCh. 5 - Prob. 2PSQCh. 5 - Prob. 3PSQCh. 5 - Prob. 4PSQCh. 5 - Prob. 5PSQCh. 5 - Prob. 6PSQCh. 5 - Prob. 7PSQCh. 5 - Prob. 8PSQCh. 5 - Prob. 9PSQCh. 5 - Prob. 10PSQCh. 5 - Prob. 11PSQCh. 5 - Prob. 12PSQCh. 5 - Prob. 13PSQCh. 5 - Prob. 14PSQCh. 5 - Prob. 15PSQCh. 5 - Prob. 16PSQCh. 5 - Prob. 17PSQCh. 5 - Prob. 1MCQCh. 5 - Prob. 2MCQCh. 5 - Prob. 3MCQCh. 5 - Prob. 4MCQCh. 5 - Prob. 5MCQCh. 5 - Prob. 6MCQCh. 5 - Prob. 7MCQCh. 5 - Prob. 8MCQCh. 5 - Prob. 9MCQCh. 5 - Prob. 10MCQCh. 5 - Prob. 11MCQCh. 5 - Prob. 12MCQCh. 5 - Prob. 13MCQCh. 5 - Prob. 14MCQCh. 5 - Prob. 15MCQCh. 5 - Prob. 16MCQCh. 5 - Prob. 17MCQCh. 5 - Prob. 18MCQCh. 5 - Prob. 19MCQCh. 5 - Prob. 20MCQCh. 5 - Prob. 21MCQCh. 5 - Prob. 22MCQCh. 5 - Prob. 23MCQCh. 5 - Prob. 24MCQCh. 5 - Prob. 25MCQCh. 5 - Prob. 1CRCh. 5 - Prob. 2CRCh. 5 - 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