Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 5, Problem 31CT

To determine

To solve the equation and check the solution for 117g+8=2

Expert Solution & Answer

Answer to Problem 31CT

The solution is g=−102

Explanation of Solution

Given information:

Consider, the provided equation 117g+8=2

Calculation:

Use multiplicative inverse property and solve for the equation.

117g+8=2 [Original equation]17⋅(117g+8)=17⋅2 [Multiply each side by LCD of fractions]17⋅(117g)+17⋅(8)=17⋅2 [Use dributive property] g+136=34 [Simplify] g+136−136=34−136 [Subtract 5 from each side]g=−102 [Simplify]

To check the solution, in the original equation 117g+8=2 substitute the value of g=−102 in expression 117g+8 and if it gives a result equals to 2 then the solution correct.

117g+8 [Expression]=117⋅(−102)+8 [Substitute value g=−102]=(−10217)+8 [Simplify]=(−10217)+13617 [Write fraction using LCD]=(−102)+13617 [Write sum of numerator over denominator]=3417 [Add]=2 [Simplify fraction]

Hence, the solution is g=−102 and is correct.

Chapter 5, Problem 30CT

Chapter 5, Problem 32CT

Chapter 5 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 5.1 - Prob. 1C Ch. 5.1 - Prob. 2C Ch. 5.1 - Prob. 3C Ch. 5.1 - Prob. 4C Ch. 5.1 - Prob. 5C Ch. 5.1 - Prob. 1E Ch. 5.1 - Prob. 2E Ch. 5.1 - Prob. 3E Ch. 5.1 - Prob. 4E Ch. 5.1 - Prob. 5E

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