Calculus
7th Edition
ISBN: 9781524916817
Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE
Publisher: Kendall Hunt Publishing
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Question
Chapter 5.2, Problem 43PS
To determine
That the area of the triangle with vertices 
has area 
using the area as the limit of a sum.
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00
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n = 1
(b) Find the sum of each of the following series.
00
Σnx",
n = 1
|x| < 1
(ii)
n = 1
sin
(c) Find the sum of each of the following series.
(i)
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Chapter 5 Solutions
Calculus
Ch. 5.1 - Prob. 1PSCh. 5.1 - Prob. 2PSCh. 5.1 - Prob. 3PSCh. 5.1 - Prob. 4PSCh. 5.1 - Prob. 5PSCh. 5.1 - Prob. 6PSCh. 5.1 - Prob. 7PSCh. 5.1 - Prob. 8PSCh. 5.1 - Prob. 9PSCh. 5.1 - Prob. 10PS
Ch. 5.1 - Prob. 11PSCh. 5.1 - Prob. 12PSCh. 5.1 - Prob. 13PSCh. 5.1 - Prob. 14PSCh. 5.1 - Prob. 15PSCh. 5.1 - Prob. 16PSCh. 5.1 - Prob. 17PSCh. 5.1 - Prob. 18PSCh. 5.1 - Prob. 19PSCh. 5.1 - Prob. 20PSCh. 5.1 - Prob. 21PSCh. 5.1 - Prob. 22PSCh. 5.1 - Prob. 23PSCh. 5.1 - Prob. 24PSCh. 5.1 - Prob. 25PSCh. 5.1 - Prob. 26PSCh. 5.1 - Prob. 27PSCh. 5.1 - Prob. 28PSCh. 5.1 - Prob. 29PSCh. 5.1 - Prob. 30PSCh. 5.1 - Prob. 31PSCh. 5.1 - Prob. 32PSCh. 5.1 - Prob. 33PSCh. 5.1 - Prob. 34PSCh. 5.1 - Prob. 35PSCh. 5.1 - Prob. 36PSCh. 5.1 - Prob. 37PSCh. 5.1 - Prob. 38PSCh. 5.1 - Prob. 39PSCh. 5.1 - Prob. 40PSCh. 5.1 - Prob. 41PSCh. 5.1 - Prob. 42PSCh. 5.1 - Prob. 43PSCh. 5.1 - Prob. 44PSCh. 5.1 - Prob. 45PSCh. 5.1 - Prob. 46PSCh. 5.1 - Prob. 47PSCh. 5.1 - Prob. 48PSCh. 5.1 - Prob. 49PSCh. 5.1 - Prob. 50PSCh. 5.1 - Prob. 51PSCh. 5.1 - Prob. 52PSCh. 5.1 - Prob. 53PSCh. 5.1 - Prob. 54PSCh. 5.1 - Prob. 55PSCh. 5.1 - Prob. 56PSCh. 5.1 - Prob. 57PSCh. 5.1 - Prob. 58PSCh. 5.1 - Prob. 59PSCh. 5.1 - Prob. 60PSCh. 5.2 - Prob. 1PSCh. 5.2 - Prob. 2PSCh. 5.2 - Prob. 3PSCh. 5.2 - Prob. 4PSCh. 5.2 - Prob. 5PSCh. 5.2 - Prob. 6PSCh. 5.2 - Prob. 7PSCh. 5.2 - Prob. 8PSCh. 5.2 - Prob. 9PSCh. 5.2 - Prob. 10PSCh. 5.2 - Prob. 11PSCh. 5.2 - Prob. 12PSCh. 5.2 - Prob. 13PSCh. 5.2 - Prob. 14PSCh. 5.2 - Prob. 15PSCh. 5.2 - Prob. 16PSCh. 5.2 - Prob. 17PSCh. 5.2 - Prob. 18PSCh. 5.2 - Prob. 19PSCh. 5.2 - Prob. 20PSCh. 5.2 - Prob. 21PSCh. 5.2 - Prob. 22PSCh. 5.2 - Prob. 23PSCh. 5.2 - Prob. 24PSCh. 5.2 - Prob. 25PSCh. 5.2 - Prob. 26PSCh. 5.2 - Prob. 27PSCh. 5.2 - Prob. 28PSCh. 5.2 - Prob. 29PSCh. 5.2 - Prob. 30PSCh. 5.2 - Prob. 31PSCh. 5.2 - Prob. 32PSCh. 5.2 - Prob. 33PSCh. 5.2 - Prob. 34PSCh. 5.2 - Prob. 35PSCh. 5.2 - Prob. 36PSCh. 5.2 - Prob. 37PSCh. 5.2 - Prob. 38PSCh. 5.2 - Prob. 39PSCh. 5.2 - Prob. 40PSCh. 5.2 - Prob. 41PSCh. 5.2 - Prob. 42PSCh. 5.2 - Prob. 43PSCh. 5.2 - Prob. 44PSCh. 5.2 - Prob. 45PSCh. 5.2 - Prob. 46PSCh. 5.2 - Prob. 47PSCh. 5.2 - Prob. 48PSCh. 5.2 - Prob. 49PSCh. 5.2 - Prob. 50PSCh. 5.2 - Prob. 51PSCh. 5.2 - 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Prob. 58PSCh. 5.7 - Prob. 59PSCh. 5.7 - Prob. 60PSCh. 5.8 - Prob. 1PSCh. 5.8 - Prob. 2PSCh. 5.8 - Prob. 3PSCh. 5.8 - Prob. 4PSCh. 5.8 - Prob. 5PSCh. 5.8 - Prob. 6PSCh. 5.8 - Prob. 7PSCh. 5.8 - Prob. 8PSCh. 5.8 - Prob. 9PSCh. 5.8 - Prob. 10PSCh. 5.8 - Prob. 11PSCh. 5.8 - Prob. 12PSCh. 5.8 - Prob. 13PSCh. 5.8 - Prob. 14PSCh. 5.8 - Prob. 15PSCh. 5.8 - Prob. 16PSCh. 5.8 - Prob. 17PSCh. 5.8 - Prob. 18PSCh. 5.8 - Prob. 19PSCh. 5.8 - Prob. 20PSCh. 5.8 - Prob. 21PSCh. 5.8 - Prob. 22PSCh. 5.8 - Prob. 23PSCh. 5.8 - Prob. 24PSCh. 5.8 - Prob. 25PSCh. 5.8 - Prob. 26PSCh. 5.8 - Prob. 27PSCh. 5.8 - Prob. 28PSCh. 5.8 - Prob. 29PSCh. 5.8 - Prob. 30PSCh. 5.8 - Prob. 31PSCh. 5.8 - Prob. 32PSCh. 5.8 - Prob. 33PSCh. 5.8 - Prob. 34PSCh. 5.8 - Prob. 35PSCh. 5.8 - Prob. 36PSCh. 5.8 - Prob. 37PSCh. 5.8 - Prob. 38PSCh. 5.8 - Prob. 39PSCh. 5.8 - Prob. 40PSCh. 5.8 - Prob. 41PSCh. 5.8 - Prob. 42PSCh. 5.8 - Prob. 43PSCh. 5.8 - Prob. 44PSCh. 5.8 - Prob. 45PSCh. 5.8 - Prob. 46PSCh. 5.8 - Prob. 47PSCh. 5.8 - Prob. 48PSCh. 5.8 - 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Prob. 40PSCh. 5.9 - Prob. 41PSCh. 5.9 - Prob. 42PSCh. 5.9 - Prob. 43PSCh. 5.9 - Prob. 44PSCh. 5.9 - Prob. 45PSCh. 5.9 - Prob. 46PSCh. 5.9 - Prob. 47PSCh. 5.9 - Prob. 48PSCh. 5.9 - Prob. 49PSCh. 5.9 - Prob. 50PSCh. 5.9 - Prob. 51PSCh. 5.9 - Prob. 52PSCh. 5.9 - Prob. 53PSCh. 5.9 - Prob. 54PSCh. 5.9 - Prob. 55PSCh. 5.9 - Prob. 56PSCh. 5.9 - Prob. 57PSCh. 5.9 - Prob. 58PSCh. 5.9 - Prob. 59PSCh. 5.9 - Prob. 60PSCh. 5 - Prob. 1PECh. 5 - Prob. 2PECh. 5 - Prob. 3PECh. 5 - Prob. 4PECh. 5 - Prob. 5PECh. 5 - Prob. 6PECh. 5 - Prob. 7PECh. 5 - Prob. 8PECh. 5 - Prob. 9PECh. 5 - Prob. 10PECh. 5 - Prob. 11PECh. 5 - Prob. 12PECh. 5 - Prob. 13PECh. 5 - Prob. 14PECh. 5 - Prob. 15PECh. 5 - Prob. 16PECh. 5 - Prob. 17PECh. 5 - Prob. 18PECh. 5 - Prob. 19PECh. 5 - Prob. 20PECh. 5 - Prob. 21PECh. 5 - Prob. 22PECh. 5 - Prob. 23PECh. 5 - Prob. 24PECh. 5 - Prob. 25PECh. 5 - Prob. 26PECh. 5 - Prob. 27PECh. 5 - Prob. 28PECh. 5 - Prob. 29PECh. 5 - Prob. 30PECh. 5 - Prob. 1SPCh. 5 - Prob. 2SPCh. 5 - Prob. 3SPCh. 5 - 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- (a) Use differentiation to find a power series representation for 1 f(x) = (4 + x)²* f(x) = 00 Σ n = 0 What is the radius of convergence, R? R = (b) Use part (a) to find a power series for f(x) = 1 (4 + x)³° f(x) = 00 Σ n = 0 What is the radius of convergence, R? R = (c) Use part (b) to find a power series for f(x) = x² (4 + x)³* 00 f(x) = Σ n = 2 What is the radius of convergence, R? R = Need Help? Read It Watch It SUBMIT ANSWERarrow_forwardanswer for question 4 pleasearrow_forward(3) (20 points) Let F(x, y, z) = (y, z, x²z). Define E = {(x, y, z) | x² + y² ≤ z ≤ 1, x ≤ 0}. (a) (2 points) Calculate the divergence V. F. (b) (4 points) Let D = {(x, y) | x² + y² ≤ 1, x ≤ 0} Without calculation, show that the triple integral √ (V · F) dV = √ 2²(1. = x²(1 − x² - y²) dA. Earrow_forward
- (2) (22 points) Let F(x, y, z) = (x sin y, cos y, ―xy). (a) (2 points) Calculate V. F. (b) (6 points) Given a vector field is everywhere defined with V G₁(x, y, z) = * G2(x, y, z) = − G3(x, y, z) = 0. 0 0 F(x, y, z) = (F₁(x, y, z), F₂(x, y, z), F(x, y, z)) that F = 0, let G = (G1, G2, G3) where F₂(x, y, y, t) dt - √ F³(x, t, 0) dt, * F1(x, y, t) dt, t) dt - √ F Calculate G for the vector field F(x, y, z) = (x sin y, cos y, -xy).arrow_forwardEvaluate the following integral over the Region R. (Answer accurate to 2 decimal places). √ √(x + y) A R R = {(x, y) | 25 < x² + y² ≤ 36, x < 0} Hint: The integral and Region is defined in rectangular coordinates.arrow_forwardFind the volume of the solid that lies under the paraboloid z = 81 - x² - y² and within the cylinder (x − 1)² + y² = 1. A plot of an example of a similar solid is shown below. (Answer accurate to 2 decimal places). Volume using Double Integral Paraboloid & Cylinder -3 Hint: The integral and region is defined in polar coordinates.arrow_forward
- Evaluate the following integral over the Region R. (Answer accurate to 2 decimal places). √4(1–2² 4(1 - x² - y²) dA R 3 R = {(r,0) | 0 ≤ r≤ 2,0π ≤0≤¼˜}. Hint: The integral is defined in rectangular coordinates. The Region is defined in polar coordinates.arrow_forwardEvaluate the following integral over the Region R. (Answer accurate to 2 decimal places). R - 1 · {(r,0) | 1 ≤ r≤ 5,½π≤ 0<1π}. Hint: Be sure to convert to Polar coordinates. Use the correct differential for Polar Coordinates.arrow_forwardEvaluate the following integral over the Region R. (Answer accurate to 2 decimal places). √ √2(x+y) dA R R = {(x, y) | 4 < x² + y² < 25,0 < x} Hint: The integral and Region is defined in rectangular coordinates.arrow_forward
- HW: The frame shown in the figure is pinned at A and C. Use moment distribution method, with and without modifications, to draw NFD, SFD, and BMD. B I I 40 kN/m A 3 m 4 marrow_forwardLet the region R be the area enclosed by the function f(x)= = 3x² and g(x) = 4x. If the region R is the base of a solid such that each cross section perpendicular to the x-axis is an isosceles right triangle with a leg in the region R, find the volume of the solid. You may use a calculator and round to the nearest thousandth. y 11 10 9 00 8 7 9 5 4 3 2 1 -1 -1 x 1 2arrow_forwardLet the region R be the area enclosed by the function f(x) = ex — 1, the horizontal line y = -4 and the vertical lines x = 0 and x = 3. Find the volume of the solid generated when the region R is revolved about the line y = -4. You may use a calculator and round to the nearest thousandth. 20 15 10 5 y I I I | I + -1.5 -1 -0.5 0.5 1 1.5 2 2.5 3 -5 I -10 -15 I + I I T I I + -20 I + -25 I I I -30 I 3.5 4 xarrow_forward
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