Explanation Given : v = − g t + v 0 on [ t 0 , t 1 ] The average value of function on interval [ a , b ] f a v g = 1 b − a ∫ a b f ( x ) d x Thus, the average of v = − g t + v 0 on [ t 0 , t 1 ] Average = 1 t 1 − t 0 ∫ t 0 t 1 ( − g t + v 0 ) d t = 1 t 1 − t 0 ( − 1 2 g t 2 + v 0 t ) t 0 t 1 = 1 t 1 − t 0 [ ( − 1 2 g t 1 2 + v 0

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differentia…

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Chapter 5.7, Problem 49PS

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To show: The average value of v=−gt+v0 on [t0,t1]

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Chapter 5.7, Problem 48PS

Chapter 5.7, Problem 50PS

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Chapter 5 Solutions

Calculus

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The average value of v = − g t + v 0 on [ t 0 , t 1 ]

Solution Summary: The author explains the average value of v=-gt+v_0onleft[t,bright].

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Chapter 5 Solutions