Explanation Given : L ( t ) = t e − 0.01 t 2 on [ 0 , 3 ] The average value of function on interval [ a , b ] f a v g = 1 b − a ∫ a b f ( x ) d x For 0 ≤ t ≤ 3 Thus, the average of L ( t ) = t e − 0.01 t 2 on [ 0 , 3 ] Average = 1 3 − 0 ∫ 0 3 t e − 0

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Question

Chapter 5.7, Problem 52PS

To determine

To find: The average value of L(t)=te−0.01t2 on [0,3]

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Chapter 5.7, Problem 51PS

Chapter 5.7, Problem 53PS

Chapter 5 Solutions

Calculus

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The average value of L ( t ) = t e − 0.01 t 2 on [ 0 , 3 ]

Solution Summary: The author explains that the average value of L(t)=Te-0.01t

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To find: The average value of L(t)=te−0.01t2 on [0,3]

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Chapter 5 Solutions