Calculus
7th Edition
ISBN: 9781524916817
Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE
Publisher: Kendall Hunt Publishing
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Chapter 5.9, Problem 3PS
To determine
To define:The exponential function
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Math Test
3 3
x³+y³ =
Ꭹ = 9
2 2
x²+y² = 5
x+y=?
For each of the following series, determine whether the absolute convergence series test
determines absolute convergence or fails. For the ¿th series, if the test is inconclusive then let
Mi = 4, while if the test determines absolute convergence let Mi
1 :
2:
∞
Σ(−1)"+¹ sin(2n);
n=1
Σ
n=1
Σ
((−1)”.
COS
n²
3+2n4
3: (+
4:
5 :
n=1
∞
n
2+5n3
ПП
n²
2 5+2n3
пп
n²
Σ(+)+
n=1
∞
n=1
COS
4
2 3+8n3
П
ηπ
n-
(−1)+1 sin (+727) 5 + 2m³
4
= 8.
Then the value of cos(M₁) + cos(2M2) + cos(3M3) + sin(2M) + sin(M5) is
-0.027
-0.621
-1.794
-1.132
-1.498
-4.355
-2.000
2.716
i need help with this question i tried by myself and so i am uploadding the question to be quided with step by step solution and please do not use chat gpt i am trying to learn thank you.
Chapter 5 Solutions
Calculus
Ch. 5.1 - Prob. 1PSCh. 5.1 - Prob. 2PSCh. 5.1 - Prob. 3PSCh. 5.1 - Prob. 4PSCh. 5.1 - Prob. 5PSCh. 5.1 - Prob. 6PSCh. 5.1 - Prob. 7PSCh. 5.1 - Prob. 8PSCh. 5.1 - Prob. 9PSCh. 5.1 - Prob. 10PS
Ch. 5.1 - Prob. 11PSCh. 5.1 - Prob. 12PSCh. 5.1 - Prob. 13PSCh. 5.1 - Prob. 14PSCh. 5.1 - Prob. 15PSCh. 5.1 - Prob. 16PSCh. 5.1 - Prob. 17PSCh. 5.1 - Prob. 18PSCh. 5.1 - Prob. 19PSCh. 5.1 - Prob. 20PSCh. 5.1 - Prob. 21PSCh. 5.1 - Prob. 22PSCh. 5.1 - Prob. 23PSCh. 5.1 - Prob. 24PSCh. 5.1 - Prob. 25PSCh. 5.1 - Prob. 26PSCh. 5.1 - Prob. 27PSCh. 5.1 - Prob. 28PSCh. 5.1 - Prob. 29PSCh. 5.1 - Prob. 30PSCh. 5.1 - Prob. 31PSCh. 5.1 - Prob. 32PSCh. 5.1 - Prob. 33PSCh. 5.1 - Prob. 34PSCh. 5.1 - Prob. 35PSCh. 5.1 - Prob. 36PSCh. 5.1 - Prob. 37PSCh. 5.1 - Prob. 38PSCh. 5.1 - Prob. 39PSCh. 5.1 - Prob. 40PSCh. 5.1 - Prob. 41PSCh. 5.1 - Prob. 42PSCh. 5.1 - Prob. 43PSCh. 5.1 - Prob. 44PSCh. 5.1 - Prob. 45PSCh. 5.1 - Prob. 46PSCh. 5.1 - Prob. 47PSCh. 5.1 - Prob. 48PSCh. 5.1 - Prob. 49PSCh. 5.1 - Prob. 50PSCh. 5.1 - Prob. 51PSCh. 5.1 - Prob. 52PSCh. 5.1 - Prob. 53PSCh. 5.1 - Prob. 54PSCh. 5.1 - Prob. 55PSCh. 5.1 - Prob. 56PSCh. 5.1 - Prob. 57PSCh. 5.1 - Prob. 58PSCh. 5.1 - Prob. 59PSCh. 5.1 - Prob. 60PSCh. 5.2 - Prob. 1PSCh. 5.2 - Prob. 2PSCh. 5.2 - Prob. 3PSCh. 5.2 - Prob. 4PSCh. 5.2 - Prob. 5PSCh. 5.2 - Prob. 6PSCh. 5.2 - Prob. 7PSCh. 5.2 - Prob. 8PSCh. 5.2 - Prob. 9PSCh. 5.2 - Prob. 10PSCh. 5.2 - Prob. 11PSCh. 5.2 - Prob. 12PSCh. 5.2 - Prob. 13PSCh. 5.2 - Prob. 14PSCh. 5.2 - Prob. 15PSCh. 5.2 - Prob. 16PSCh. 5.2 - Prob. 17PSCh. 5.2 - Prob. 18PSCh. 5.2 - Prob. 19PSCh. 5.2 - Prob. 20PSCh. 5.2 - Prob. 21PSCh. 5.2 - Prob. 22PSCh. 5.2 - Prob. 23PSCh. 5.2 - Prob. 24PSCh. 5.2 - Prob. 25PSCh. 5.2 - Prob. 26PSCh. 5.2 - Prob. 27PSCh. 5.2 - Prob. 28PSCh. 5.2 - Prob. 29PSCh. 5.2 - Prob. 30PSCh. 5.2 - Prob. 31PSCh. 5.2 - Prob. 32PSCh. 5.2 - Prob. 33PSCh. 5.2 - Prob. 34PSCh. 5.2 - Prob. 35PSCh. 5.2 - Prob. 36PSCh. 5.2 - Prob. 37PSCh. 5.2 - Prob. 38PSCh. 5.2 - Prob. 39PSCh. 5.2 - Prob. 40PSCh. 5.2 - Prob. 41PSCh. 5.2 - Prob. 42PSCh. 5.2 - Prob. 43PSCh. 5.2 - Prob. 44PSCh. 5.2 - Prob. 45PSCh. 5.2 - Prob. 46PSCh. 5.2 - Prob. 47PSCh. 5.2 - Prob. 48PSCh. 5.2 - Prob. 49PSCh. 5.2 - Prob. 50PSCh. 5.2 - Prob. 51PSCh. 5.2 - 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Prob. 43PSCh. 5.3 - Prob. 44PSCh. 5.3 - Prob. 45PSCh. 5.3 - Prob. 46PSCh. 5.3 - Prob. 47PSCh. 5.3 - Prob. 48PSCh. 5.3 - Prob. 49PSCh. 5.3 - Prob. 50PSCh. 5.3 - Prob. 51PSCh. 5.3 - Prob. 52PSCh. 5.3 - Prob. 53PSCh. 5.3 - Prob. 54PSCh. 5.3 - Prob. 55PSCh. 5.3 - Prob. 56PSCh. 5.3 - Prob. 57PSCh. 5.3 - Prob. 58PSCh. 5.3 - Prob. 59PSCh. 5.3 - Prob. 60PSCh. 5.4 - Prob. 1PSCh. 5.4 - Prob. 2PSCh. 5.4 - Prob. 3PSCh. 5.4 - Prob. 4PSCh. 5.4 - Prob. 5PSCh. 5.4 - Prob. 6PSCh. 5.4 - Prob. 7PSCh. 5.4 - Prob. 8PSCh. 5.4 - Prob. 9PSCh. 5.4 - Prob. 10PSCh. 5.4 - Prob. 11PSCh. 5.4 - Prob. 12PSCh. 5.4 - Prob. 13PSCh. 5.4 - Prob. 14PSCh. 5.4 - Prob. 15PSCh. 5.4 - Prob. 16PSCh. 5.4 - Prob. 17PSCh. 5.4 - Prob. 18PSCh. 5.4 - Prob. 19PSCh. 5.4 - Prob. 20PSCh. 5.4 - Prob. 21PSCh. 5.4 - Prob. 22PSCh. 5.4 - Prob. 23PSCh. 5.4 - Prob. 24PSCh. 5.4 - Prob. 25PSCh. 5.4 - Prob. 26PSCh. 5.4 - Prob. 27PSCh. 5.4 - Prob. 28PSCh. 5.4 - Prob. 29PSCh. 5.4 - Prob. 30PSCh. 5.4 - Prob. 31PSCh. 5.4 - Prob. 32PSCh. 5.4 - Prob. 33PSCh. 5.4 - Prob. 34PSCh. 5.4 - Prob. 35PSCh. 5.4 - Prob. 36PSCh. 5.4 - Prob. 37PSCh. 5.4 - Prob. 38PSCh. 5.4 - Prob. 39PSCh. 5.4 - Prob. 40PSCh. 5.4 - Prob. 41PSCh. 5.4 - Prob. 42PSCh. 5.4 - Prob. 43PSCh. 5.4 - Prob. 44PSCh. 5.4 - Prob. 45PSCh. 5.4 - Prob. 46PSCh. 5.4 - Prob. 47PSCh. 5.4 - Prob. 48PSCh. 5.4 - Prob. 49PSCh. 5.4 - Prob. 50PSCh. 5.4 - Prob. 51PSCh. 5.4 - Prob. 52PSCh. 5.4 - Prob. 53PSCh. 5.4 - Prob. 54PSCh. 5.4 - Prob. 55PSCh. 5.4 - Prob. 56PSCh. 5.4 - Prob. 57PSCh. 5.4 - Prob. 58PSCh. 5.4 - Prob. 59PSCh. 5.4 - Prob. 60PSCh. 5.5 - Prob. 1PSCh. 5.5 - Prob. 2PSCh. 5.5 - Prob. 3PSCh. 5.5 - Prob. 4PSCh. 5.5 - Prob. 5PSCh. 5.5 - Prob. 6PSCh. 5.5 - Prob. 7PSCh. 5.5 - Prob. 8PSCh. 5.5 - Prob. 9PSCh. 5.5 - Prob. 10PSCh. 5.5 - Prob. 11PSCh. 5.5 - Prob. 12PSCh. 5.5 - Prob. 13PSCh. 5.5 - Prob. 14PSCh. 5.5 - Prob. 15PSCh. 5.5 - Prob. 16PSCh. 5.5 - Prob. 17PSCh. 5.5 - Prob. 18PSCh. 5.5 - Prob. 19PSCh. 5.5 - Prob. 20PSCh. 5.5 - Prob. 21PSCh. 5.5 - Prob. 22PSCh. 5.5 - Prob. 23PSCh. 5.5 - Prob. 24PSCh. 5.5 - Prob. 25PSCh. 5.5 - Prob. 26PSCh. 5.5 - Prob. 27PSCh. 5.5 - Prob. 28PSCh. 5.5 - Prob. 29PSCh. 5.5 - Prob. 30PSCh. 5.5 - Prob. 31PSCh. 5.5 - Prob. 32PSCh. 5.5 - Prob. 33PSCh. 5.5 - Prob. 34PSCh. 5.5 - Prob. 35PSCh. 5.5 - Prob. 36PSCh. 5.5 - Prob. 37PSCh. 5.5 - Prob. 38PSCh. 5.5 - Prob. 39PSCh. 5.5 - Prob. 40PSCh. 5.5 - Prob. 41PSCh. 5.5 - Prob. 42PSCh. 5.5 - Prob. 43PSCh. 5.5 - Prob. 44PSCh. 5.5 - Prob. 45PSCh. 5.5 - Prob. 46PSCh. 5.5 - Prob. 47PSCh. 5.5 - Prob. 48PSCh. 5.5 - Prob. 49PSCh. 5.5 - Prob. 50PSCh. 5.5 - Prob. 51PSCh. 5.5 - Prob. 52PSCh. 5.5 - Prob. 53PSCh. 5.5 - Prob. 54PSCh. 5.5 - Prob. 55PSCh. 5.5 - Prob. 56PSCh. 5.5 - Prob. 57PSCh. 5.5 - Prob. 58PSCh. 5.5 - Prob. 59PSCh. 5.5 - Prob. 60PSCh. 5.6 - Prob. 1PSCh. 5.6 - Prob. 2PSCh. 5.6 - Prob. 3PSCh. 5.6 - Prob. 4PSCh. 5.6 - Prob. 5PSCh. 5.6 - Prob. 6PSCh. 5.6 - Prob. 7PSCh. 5.6 - Prob. 8PSCh. 5.6 - Prob. 9PSCh. 5.6 - Prob. 10PSCh. 5.6 - Prob. 11PSCh. 5.6 - Prob. 12PSCh. 5.6 - Prob. 13PSCh. 5.6 - Prob. 14PSCh. 5.6 - Prob. 15PSCh. 5.6 - 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Prob. 7PSCh. 5.7 - Prob. 8PSCh. 5.7 - Prob. 9PSCh. 5.7 - Prob. 10PSCh. 5.7 - Prob. 11PSCh. 5.7 - Prob. 12PSCh. 5.7 - Prob. 13PSCh. 5.7 - Prob. 14PSCh. 5.7 - Prob. 15PSCh. 5.7 - Prob. 16PSCh. 5.7 - Prob. 17PSCh. 5.7 - Prob. 18PSCh. 5.7 - Prob. 19PSCh. 5.7 - Prob. 20PSCh. 5.7 - Prob. 21PSCh. 5.7 - Prob. 22PSCh. 5.7 - Prob. 23PSCh. 5.7 - Prob. 24PSCh. 5.7 - Prob. 25PSCh. 5.7 - Prob. 26PSCh. 5.7 - Prob. 27PSCh. 5.7 - Prob. 28PSCh. 5.7 - Prob. 29PSCh. 5.7 - Prob. 30PSCh. 5.7 - Prob. 31PSCh. 5.7 - Prob. 32PSCh. 5.7 - Prob. 33PSCh. 5.7 - Prob. 34PSCh. 5.7 - Prob. 35PSCh. 5.7 - Prob. 36PSCh. 5.7 - Prob. 37PSCh. 5.7 - Prob. 38PSCh. 5.7 - Prob. 39PSCh. 5.7 - Prob. 40PSCh. 5.7 - Prob. 41PSCh. 5.7 - Prob. 42PSCh. 5.7 - Prob. 43PSCh. 5.7 - Prob. 44PSCh. 5.7 - Prob. 45PSCh. 5.7 - Prob. 46PSCh. 5.7 - Prob. 47PSCh. 5.7 - Prob. 48PSCh. 5.7 - Prob. 49PSCh. 5.7 - Prob. 50PSCh. 5.7 - Prob. 51PSCh. 5.7 - Prob. 52PSCh. 5.7 - Prob. 53PSCh. 5.7 - Prob. 54PSCh. 5.7 - Prob. 55PSCh. 5.7 - Prob. 56PSCh. 5.7 - Prob. 57PSCh. 5.7 - Prob. 58PSCh. 5.7 - Prob. 59PSCh. 5.7 - Prob. 60PSCh. 5.8 - Prob. 1PSCh. 5.8 - Prob. 2PSCh. 5.8 - Prob. 3PSCh. 5.8 - Prob. 4PSCh. 5.8 - Prob. 5PSCh. 5.8 - Prob. 6PSCh. 5.8 - Prob. 7PSCh. 5.8 - Prob. 8PSCh. 5.8 - Prob. 9PSCh. 5.8 - Prob. 10PSCh. 5.8 - Prob. 11PSCh. 5.8 - Prob. 12PSCh. 5.8 - Prob. 13PSCh. 5.8 - Prob. 14PSCh. 5.8 - Prob. 15PSCh. 5.8 - Prob. 16PSCh. 5.8 - Prob. 17PSCh. 5.8 - Prob. 18PSCh. 5.8 - Prob. 19PSCh. 5.8 - Prob. 20PSCh. 5.8 - Prob. 21PSCh. 5.8 - Prob. 22PSCh. 5.8 - Prob. 23PSCh. 5.8 - Prob. 24PSCh. 5.8 - Prob. 25PSCh. 5.8 - Prob. 26PSCh. 5.8 - Prob. 27PSCh. 5.8 - Prob. 28PSCh. 5.8 - Prob. 29PSCh. 5.8 - Prob. 30PSCh. 5.8 - Prob. 31PSCh. 5.8 - Prob. 32PSCh. 5.8 - Prob. 33PSCh. 5.8 - Prob. 34PSCh. 5.8 - Prob. 35PSCh. 5.8 - Prob. 36PSCh. 5.8 - Prob. 37PSCh. 5.8 - Prob. 38PSCh. 5.8 - Prob. 39PSCh. 5.8 - Prob. 40PSCh. 5.8 - Prob. 41PSCh. 5.8 - Prob. 42PSCh. 5.8 - Prob. 43PSCh. 5.8 - Prob. 44PSCh. 5.8 - Prob. 45PSCh. 5.8 - Prob. 46PSCh. 5.8 - Prob. 47PSCh. 5.8 - Prob. 48PSCh. 5.8 - 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Prob. 40PSCh. 5.9 - Prob. 41PSCh. 5.9 - Prob. 42PSCh. 5.9 - Prob. 43PSCh. 5.9 - Prob. 44PSCh. 5.9 - Prob. 45PSCh. 5.9 - Prob. 46PSCh. 5.9 - Prob. 47PSCh. 5.9 - Prob. 48PSCh. 5.9 - Prob. 49PSCh. 5.9 - Prob. 50PSCh. 5.9 - Prob. 51PSCh. 5.9 - Prob. 52PSCh. 5.9 - Prob. 53PSCh. 5.9 - Prob. 54PSCh. 5.9 - Prob. 55PSCh. 5.9 - Prob. 56PSCh. 5.9 - Prob. 57PSCh. 5.9 - Prob. 58PSCh. 5.9 - Prob. 59PSCh. 5.9 - Prob. 60PSCh. 5 - Prob. 1PECh. 5 - Prob. 2PECh. 5 - Prob. 3PECh. 5 - Prob. 4PECh. 5 - Prob. 5PECh. 5 - Prob. 6PECh. 5 - Prob. 7PECh. 5 - Prob. 8PECh. 5 - Prob. 9PECh. 5 - Prob. 10PECh. 5 - Prob. 11PECh. 5 - Prob. 12PECh. 5 - Prob. 13PECh. 5 - Prob. 14PECh. 5 - Prob. 15PECh. 5 - Prob. 16PECh. 5 - Prob. 17PECh. 5 - Prob. 18PECh. 5 - Prob. 19PECh. 5 - Prob. 20PECh. 5 - Prob. 21PECh. 5 - Prob. 22PECh. 5 - Prob. 23PECh. 5 - Prob. 24PECh. 5 - Prob. 25PECh. 5 - Prob. 26PECh. 5 - Prob. 27PECh. 5 - Prob. 28PECh. 5 - Prob. 29PECh. 5 - Prob. 30PECh. 5 - Prob. 1SPCh. 5 - Prob. 2SPCh. 5 - Prob. 3SPCh. 5 - 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- i need help with this question i tried by myself and so i am uploadding the question to be quided with step by step solution and please do not use chat gpt i am trying to learn thank you.arrow_forward1. 3 2 fx=14x²-15x²-9x- 2arrow_forwardNo it is not a graded assignment, its a review question but i only have the final answer not the working or explanationarrow_forward
- Class, the class silues, and the class notes, whether the series does alternate and the absolute values of the terms decrease), and if the test does apply, determine whether the series converges or diverges. For the ith series, if the test does not apply the let Mi = 2, while if the test determines divergence then M¿ = 4, and if it determines convergence then M¿ = 8. 1: 2: 3 : 4: 5 : ∞ n=1 ∞ (−1)n+1. Σ(-1) +1 n=1 ∞ п 3m² +2 Σ(-1)+1 sin(2n). n=1 ∞ 2n² + 2n +3 4n2 +6 1 e-n + n² 3n23n+1 9n² +3 In(n + 1) 2n+1 Σ(-1) +1 n=1 ∞ Σ(-1)". n=1 Then the value of cos(M₁) + cos(2M2) + cos(3M3) + sin(2M4) + sin(M5) is 1.715 0.902 0.930 -1.647 -0.057 ● 2.013 1.141 4.274arrow_forward3. FCX14) = x²+3xx-y3 +.arrow_forwardA cylindrical chemical storage tank with a capacity of 950m3 is going to be constructed in a warehouse that is 11m by 14m with a height of 10m. The specifications call for the case to be made of sheet metal that costs $90/m2, the top to be made from sheet metal that costs $45/m2 and the wall to be made of sheet metal that costs $80/m2. If you want to minimize the cost to make the storage house, how much would you end up spending to build the tank?arrow_forward
- Calculate the max value of the directional derivatearrow_forwardCalculus III May I please have the example, definition semicolons, and all blanks completed and solved? Thank you so much,arrow_forwardA company estimates that the revenue (in dollars) from the sale of x doghouses is given by R(x) = 12,000 In (0.02x+1). Use the differential to approximate the change in revenue from the sale of one more doghouse if 80 doghouses have already been sold. The revenue will increase by $ if one more doghouse is made. (Round to the nearest cent as needed.)arrow_forward
- The population of bacteria (in millions) in a certain culture x hours after an experimental 20x nutrient is introduced into the culture is P(x) = - 2 Use the differential to approximate the changes in population for the following changes in x. 8+x a. 1 to 1.5 b. 3 to 3.25 a. Use the differential to approximate the change in population for x=1 to 1.5. Between 1 and 1.5 hours, the population of bacteria changes by million. (Round to three decimal places as needed.)arrow_forwardThe demand for grass seed (in thousands of pounds) at price p dollars is given by the following function. D(p) 3p³-2p² + 1460 Use the differential to approximate the changes in demand for the following changes in p. a. $4 to $4.11 b. $6 to $6.19arrow_forwardLet the region R be the area enclosed by the function f(x) = 3 ln (x) and g(x) = 3 x + 1. Write an integral in terms of x and also an integral in terms of y that would represent the area of the region R. If necessary, round limit values to the nearest thousandth. Answer Attempt 1 out of 2 y 7 10 6 5 4 3 2 -1 2 3 4 5 6 x2 dx x1 = x2 = x1 Y1 = Y2 = Y1 dyarrow_forward
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