(a) Explanation Write the expression for the work of the cycle. W c y c l e = Q 1 + Q 2 + Q 3 (I) Here, the work done in the cycle is W c y c l e , heat added to the system at 1000 ° R is Q 1 , heat discharged at 800 ° R is Q 2 and heat transferred at 600 ° R is Q 3 . Since the work of the cycle should be W c y c l e ≥ 0 . Simplify the Equation (I) for the heat transfer at 600 ° R . − Q 3 ≥ Q 1 + Q 2 (II) Write the expression for the clausius inequality. ∮ δ Q T = − σ c y c l e (III) Here, the heat trasfered from the reservoir is Q , temperature of the reservoir is T and strength of the inequality for a cycle is σ c y c l e . Simplify the Equation (III) for the power cycle. Q 1 T 1 + Q 2 T 2 + Q 3 T 3 = − σ c y c l e (IV) Since the strenth of inquality of the cycle should be σ c y c l e ≥ 0 . Simplify the Equation (IV) the heat transfer at 600 ° R (b) To determine The maximum thermal efficiency of the cycle.

Fundamentals of Engineering Thermodynamics

8th Edition

ISBN: 9781118412930

Author: Michael J. Moran, Howard N. Shapiro, Daisie D. Boettner, Margaret B. Bailey

Publisher: WILEY

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Chapter 5.11, Problem 94P

(a)

To determine

The range of the heat transfer at 600°R.

(b)

To determine

The maximum thermal efficiency of the cycle.

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Chapter 5.11, Problem 93P

Chapter 6.13, Problem 1E

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The range of the heat transfer at 600 ° R .