Fundamentals of Engineering Thermodynamics
8th Edition
ISBN: 9781118412930
Author: Michael J. Moran, Howard N. Shapiro, Daisie D. Boettner, Margaret B. Bailey
Publisher: WILEY
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Chapter 5.11, Problem 3E
To determine
The cost associated, per lb, of the refrigerant used in the air conditioner of the car
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Chapter 5 Solutions
Fundamentals of Engineering Thermodynamics
Ch. 5.11 - Prob. 1ECh. 5.11 - 2. Are health risks associated with consuming...Ch. 5.11 - Prob. 3ECh. 5.11 - Prob. 4ECh. 5.11 - Prob. 5ECh. 5.11 - 6. Does the second law impose performance limits...Ch. 5.11 - Prob. 7ECh. 5.11 - 8. What is delaying the appearance in new car...Ch. 5.11 - Prob. 9ECh. 5.11 - 10. How significant is the roughness at a pipe’s...
Ch. 5.11 - Prob. 11ECh. 5.11 - 12. What factors influence the actual coefficient...Ch. 5.11 - Prob. 13ECh. 5.11 - 14. How does the thermal glider (Sec. 5.4) sustain...Ch. 5.11 - 1. A reversible heat pump cycle operates between...Ch. 5.11 - Prob. 2CUCh. 5.11 - 3. Referring to the list of Sec. 5.3.1,...Ch. 5.11 - 4. Uses of the second law of thermodynamics...Ch. 5.11 - Prob. 5CUCh. 5.11 - Prob. 6CUCh. 5.11 - Prob. 7CUCh. 5.11 - Prob. 8CUCh. 5.11 - Prob. 9CUCh. 5.11 - Prob. 10CUCh. 5.11 - Prob. 11CUCh. 5.11 - Prob. 12CUCh. 5.11 - Prob. 13CUCh. 5.11 - Prob. 14CUCh. 5.11 - Prob. 15CUCh. 5.11 - Prob. 16CUCh. 5.11 - Prob. 17CUCh. 5.11 - 18. Referring to Fig. 5.15, if the boiler and...Ch. 5.11 - Prob. 19CUCh. 5.11 - Prob. 20CUCh. 5.11 - Prob. 21CUCh. 5.11 - 22. A cell phone initially has a fully charged...Ch. 5.11 - Prob. 23CUCh. 5.11 - Prob. 24CUCh. 5.11 - Prob. 25CUCh. 5.11 - Prob. 26CUCh. 5.11 - Prob. 27CUCh. 5.11 - 28. As shown in Fig. P5.28C, energy transfer...Ch. 5.11 - 29. As shown in Fig. P5.29C, a rigid, insulated...Ch. 5.11 - 30. As shown in Fig. P5.30C, when the steam in the...Ch. 5.11 - Prob. 31CUCh. 5.11 - Prob. 32CUCh. 5.11 - Prob. 33CUCh. 5.11 - Prob. 34CUCh. 5.11 - Prob. 35CUCh. 5.11 - Prob. 36CUCh. 5.11 - Prob. 37CUCh. 5.11 - Prob. 38CUCh. 5.11 - Prob. 39CUCh. 5.11 - Prob. 40CUCh. 5.11 - Prob. 41CUCh. 5.11 - Prob. 42CUCh. 5.11 - 43. The maximum coefficient of performance of any...Ch. 5.11 - Prob. 44CUCh. 5.11 - Prob. 45CUCh. 5.11 - Prob. 46CUCh. 5.11 - 47. When an isolated system undergoes a process,...Ch. 5.11 - Prob. 48CUCh. 5.11 - Prob. 49CUCh. 5.11 - Prob. 50CUCh. 5.11 - 5.1 Complete the demonstration of the equivalence...Ch. 5.11 - 5.2 Shown in Fig. P5.2 is a proposed system that...Ch. 5.11 - 5.3 Classify the following processes of a closed...Ch. 5.11 - Prob. 4PCh. 5.11 - Prob. 5PCh. 5.11 - Prob. 6PCh. 5.11 - 5.7 Provide the details left to the reader in the...Ch. 5.11 - 5.8 Using the Kelvin–Planck statement of the...Ch. 5.11 - Prob. 9PCh. 5.11 - Prob. 10PCh. 5.11 - Prob. 11PCh. 5.11 - Prob. 12PCh. 5.11 - Prob. 13PCh. 5.11 - Prob. 14PCh. 5.11 - 5.15 To increase the thermal efficiency of a...Ch. 5.11 - Prob. 16PCh. 5.11 - Prob. 17PCh. 5.11 - Prob. 18PCh. 5.11 - 5.19 A power cycle operating at steady state...Ch. 5.11 - 5.20 As shown in Fig. P5.20, a reversible power...Ch. 5.11 - Prob. 21PCh. 5.11 - Prob. 22PCh. 5.11 - Prob. 23PCh. 5.11 - Prob. 24PCh. 5.11 - Prob. 25PCh. 5.11 - Prob. 26PCh. 5.11 - Prob. 27PCh. 5.11 - Prob. 28PCh. 5.11 - Prob. 29PCh. 5.11 - Prob. 30PCh. 5.11 - Prob. 31PCh. 5.11 - Prob. 32PCh. 5.11 - Prob. 33PCh. 5.11 - 5.34 A power cycle operates between hot and cold...Ch. 5.11 - Prob. 35PCh. 5.11 - 5.36 An inventor claims to have developed a power...Ch. 5.11 - Prob. 37PCh. 5.11 - Prob. 38PCh. 5.11 - 5.39 As shown in Fig. P5.39, a system undergoing a...Ch. 5.11 - Prob. 40PCh. 5.11 - Prob. 41PCh. 5.11 - Prob. 42PCh. 5.11 - Prob. 43PCh. 5.11 - 5.44 A reversible refrigeration cycle operates...Ch. 5.11 - Prob. 45PCh. 5.11 - 5.46 A heating system must maintain the interior...Ch. 5.11 - Prob. 47PCh. 5.11 - 5.48 The thermal efficiency of a reversible power...Ch. 5.11 - 5.49 Shown in Fig. P5.49 is a system consisting of...Ch. 5.11 - 5.50 An inventor has developed a refrigerator...Ch. 5.11 - 5.51 An inventor claims to have developed a food...Ch. 5.11 - 5.52 An inventor claims to have developed a...Ch. 5.11 - 5.53 An inventor claims to have devised a...Ch. 5.11 - 5.54 Data are provided for two reversible...Ch. 5.11 - 5.55 By removing energy by heat transfer from its...Ch. 5.11 - 5.56 At steady state, a refrigeration cycle...Ch. 5.11 - Prob. 57PCh. 5.11 - 5.58 At steady state, a refrigeration cycle...Ch. 5.11 - Prob. 59PCh. 5.11 - Prob. 60PCh. 5.11 - Prob. 61PCh. 5.11 - Prob. 62PCh. 5.11 - Prob. 63PCh. 5.11 - 5.64 As shown in Fig P5.64, an air conditioner...Ch. 5.11 - Prob. 65PCh. 5.11 - Prob. 66PCh. 5.11 - 5.68 The refrigerator shown in Fig. P5.68 operates...Ch. 5.11 - Prob. 69PCh. 5.11 - 5.70 By supplying energy at an average rate of...Ch. 5.11 - 5.71 A heat pump with a coefficient of performance...Ch. 5.11 - 5.72 As shown in Fig. P5.72, a heat pump provides...Ch. 5.11 - 5.73 As shown in Fig. P 5.73, a heat pump receives...Ch. 5.11 - Prob. 74PCh. 5.11 - Prob. 75PCh. 5.11 - Prob. 76PCh. 5.11 - Prob. 77PCh. 5.11 - Prob. 78PCh. 5.11 - Prob. 79PCh. 5.11 - Prob. 80PCh. 5.11 - 5.81 A quantity of water within a piston–cylinder...Ch. 5.11 - Prob. 82PCh. 5.11 - 5.83 Two kilograms of air within a piston–cylinder...Ch. 5.11 - Prob. 84PCh. 5.11 - Prob. 85PCh. 5.11 - Prob. 86PCh. 5.11 - Prob. 87PCh. 5.11 - Prob. 88PCh. 5.11 - Prob. 89PCh. 5.11 - 5.90 Figure P5.90 gives the schematic of a vapor...Ch. 5.11 - Prob. 91PCh. 5.11 - Prob. 92PCh. 5.11 - 5.93 As shown in Fig. P5.93, a system executes a...Ch. 5.11 - Prob. 94P
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- Four-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forwardThe evaporator of a vapor compression refrigeration cycle utilizing R-123 as the refrigerant isbeing used to chill water. The evaporator is a shell and tube heat exchanger with the water flowingthrough the tubes. The water enters the heat exchanger at a temperature of 54°F. The approachtemperature difference of the evaporator is 3°R. The evaporating pressure of the refrigeration cycleis 4.8 psia and the condensing pressure is 75 psia. The refrigerant is flowing through the cycle witha flow rate of 18,000 lbm/hr. The R-123 leaves the evaporator as a saturated vapor and leaves thecondenser as a saturated liquid. Determine the following:a. The outlet temperature of the chilled waterb. The volumetric flow rate of the chilled water (gpm)c. The UA product of the evaporator (Btu/h-°F)d. The heat transfer rate between the refrigerant and the water (tons)arrow_forward(Read image) (Answer given)arrow_forward
- Problem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forwardProblem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forwardProblem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forward
- The flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forwardAn experimental setup is being built to study the flow in a large water main (i.e., a large pipe). The water main is expected to convey a discharge (Qp). The experimental tube will be built at a length scale of 1/20 of the actual water main. After building the experimental setup, the pressure drop per unit length in the model tube (APm/Lm) is measured. Problem (20): Given the value of APm/Lm [kPa/m], and assuming pressure coefficient similitude, calculate the drop in the pressure per unit length of the water main (APP/Lp) in [Pa/m]. Givens: AP M/L m = 590.637 kPa/m meen Answers: ( 1 ) 59.369 Pa/m ( 2 ) 73.83 Pa/m (3) 95.443 Pa/m ( 4 ) 44.444 Pa/m *******arrow_forwardFind the reaction force in y if Ain = 0.169 m^2, Aout = 0.143 m^2, p_in = 0.552 atm, Q = 0.367 m^3/s, α = 31.72 degrees. The pipe is flat on the ground so do not factor in weight of the pipe and fluid.arrow_forward
- Find the reaction force in x if Ain = 0.301 m^2, Aout = 0.177 m^2, p_in = 1.338 atm, Q = 0.669 m^3/s, and α = 37.183 degreesarrow_forwardProblem 5: Three-Force Equilibrium A structural connection at point O is in equilibrium under the action of three forces. • • . Member A applies a force of 9 kN vertically upward along the y-axis. Member B applies an unknown force F at the angle shown. Member C applies an unknown force T along its length at an angle shown. Determine the magnitudes of forces F and T required for equilibrium, assuming 0 = 90° y 9 kN Aarrow_forwardProblem 19: Determine the force in members HG, HE, and DE of the truss, and state if the members are in tension or compression. 4 ft K J I H G B C D E F -3 ft -3 ft 3 ft 3 ft 3 ft- 1500 lb 1500 lb 1500 lb 1500 lb 1500 lbarrow_forward
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