Algebra 1
1st Edition
ISBN: 9780078884801
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Question
Chapter 5.1, Problem 45PPS
(a)
To determine
Draw a picture to represent this situation.
(a)
Expert Solution
Answer to Problem 45PPS
The right side must be down than the right side
Explanation of Solution
Given:
In a balance have 12 pounds on the left side and 18 pounds on the right side.
Concept Used:
As 12 lbs is less than 18 lbs. So the right side must be down than the right side.
Thus, the right side must be down than the right side as 12pounds on the left side and 18 pounds on the right side
(b)
To determine
Write an inequality.
(b)
Expert Solution
Answer to Problem 45PPS
Explanation of Solution
Given:
In a balance have 12 pounds on the left side and 18 pounds on the tight side.
Concept Used:
Left side 12 lbs is less than the right side 18 lbs.
Inequality:
Calculation:
Inequality:
Thus, we can write the inequality
(c)
To determine
Create a table showing the result of doubling, tripling or quadrupling the weight of each side of the balance.
Create a second table showing the result of reducing the weight on each side of the balance by a factor of
(c)
Expert Solution
Answer to Problem 45PPS
Explanation of Solution
Given: In a balance have 12 pounds on the left side and 18 pounds on the tight side.
Concept Used:
Make two tables to represent the situation doubling, tripling or quadrupling the weight of each side of the balance and by a factor of
Calculation:
Create a table showing the result of doubling, tripling or quadrupling the weight of each side of the balance.
| x | Original | 12 Pound | 18 Pound | |
| x2 | Doubling | 24 Pound | < | 36 Pound |
| x3 | Tripling | 36 Pound | < | 54 Pound |
| x4 | Quadrupling | 48 Pound | < | 72 Pound |
Create a second table showing the result of reducing the weight on each side of the balance by a factor of
| x | Original | 12 Pound | < | 18 Pound |
| by a factor of | 6 Pound | < | 9 Pound | |
| by a factor of | 4 Pound | < | 6 Pound | |
| by a factor of | 3 Pound | < | 4.5 Pound |
Thus, the two tables represent the situations.
(d)
To determine
Describe the effect multiplying or dividing each side of an inequality by the same positive value has on the inequality.
(d)
Expert Solution
Explanation of Solution
Given: In a balance have 12 pounds on the left side and 18 pounds on the tight side.
Concept Used:
If a true inequality is multiplied by a positive number, the resulting inequality is also true.
If a true inequality is divided by a positive number, the resulting inequality is also true.
Thus, if a true inequality is multiplied by a positive number, the resulting inequality is also true and if a true inequality is divided by a positive number, the resulting inequality is also true.
Chapter 5 Solutions
Algebra 1
Ch. 5.1 - Prob. 1ACYPCh. 5.1 - Prob. 1BCYPCh. 5.1 - Prob. 2CYPCh. 5.1 - Prob. 3ACYPCh. 5.1 - Prob. 3BCYPCh. 5.1 - Prob. 4CYPCh. 5.1 - Prob. 1CYUCh. 5.1 - Prob. 2CYUCh. 5.1 - Prob. 3CYUCh. 5.1 - Prob. 4CYU
Ch. 5.1 - Prob. 5CYUCh. 5.1 - Prob. 6CYUCh. 5.1 - Prob. 7CYUCh. 5.1 - Prob. 8CYUCh. 5.1 - Prob. 9CYUCh. 5.1 - Prob. 10CYUCh. 5.1 - Prob. 11CYUCh. 5.1 - Prob. 12PPSCh. 5.1 - Prob. 13PPSCh. 5.1 - Prob. 14PPSCh. 5.1 - Prob. 15PPSCh. 5.1 - Prob. 16PPSCh. 5.1 - Prob. 17PPSCh. 5.1 - Prob. 18PPSCh. 5.1 - Prob. 19PPSCh. 5.1 - Prob. 20PPSCh. 5.1 - Prob. 21PPSCh. 5.1 - Prob. 22PPSCh. 5.1 - Prob. 23PPSCh. 5.1 - Prob. 24PPSCh. 5.1 - Prob. 25PPSCh. 5.1 - Prob. 26PPSCh. 5.1 - Prob. 27PPSCh. 5.1 - Prob. 28PPSCh. 5.1 - Prob. 29PPSCh. 5.1 - Prob. 30PPSCh. 5.1 - Prob. 31PPSCh. 5.1 - Prob. 32PPSCh. 5.1 - Prob. 33PPSCh. 5.1 - Prob. 34PPSCh. 5.1 - Prob. 35PPSCh. 5.1 - Prob. 36PPSCh. 5.1 - Prob. 37PPSCh. 5.1 - Prob. 38PPSCh. 5.1 - Prob. 39PPSCh. 5.1 - Prob. 40PPSCh. 5.1 - Prob. 41PPSCh. 5.1 - Prob. 42PPSCh. 5.1 - Prob. 43PPSCh. 5.1 - Prob. 44PPSCh. 5.1 - Prob. 45PPSCh. 5.1 - Prob. 46PPSCh. 5.1 - Prob. 47PPSCh. 5.1 - Prob. 48PPSCh. 5.1 - Prob. 49PPSCh. 5.1 - Prob. 50PPSCh. 5.1 - Prob. 51PPSCh. 5.1 - Prob. 52HPCh. 5.1 - 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Prob. 1BCYPCh. 5.4 - Prob. 2BCYPCh. 5.4 - Prob. 3ACYPCh. 5.4 - Prob. 3BCYPCh. 5.4 - Prob. 1CYUCh. 5.4 - Prob. 2CYUCh. 5.4 - Prob. 3CYUCh. 5.4 - Prob. 4CYUCh. 5.4 - Prob. 5CYUCh. 5.4 - Prob. 6PPSCh. 5.4 - Prob. 7PPSCh. 5.4 - Prob. 8PPSCh. 5.4 - Prob. 9PPSCh. 5.4 - Prob. 10PPSCh. 5.4 - Prob. 11PPSCh. 5.4 - Prob. 12PPSCh. 5.4 - Prob. 13PPSCh. 5.4 - Prob. 14PPSCh. 5.4 - Prob. 15PPSCh. 5.4 - Prob. 16PPSCh. 5.4 - Prob. 17PPSCh. 5.4 - Prob. 18PPSCh. 5.4 - Prob. 19PPSCh. 5.4 - Prob. 20PPSCh. 5.4 - Prob. 21PPSCh. 5.4 - Prob. 22PPSCh. 5.4 - Prob. 23PPSCh. 5.4 - Prob. 24PPSCh. 5.4 - Prob. 25PPSCh. 5.4 - Prob. 26PPSCh. 5.4 - Prob. 27PPSCh. 5.4 - Prob. 28PPSCh. 5.4 - Prob. 29PPSCh. 5.4 - Prob. 30PPSCh. 5.4 - Prob. 31PPSCh. 5.4 - Prob. 32PPSCh. 5.4 - Prob. 33PPSCh. 5.4 - Prob. 34PPSCh. 5.4 - Prob. 35PPSCh. 5.4 - Prob. 36PPSCh. 5.4 - Prob. 37PPSCh. 5.4 - Prob. 38PPSCh. 5.4 - Prob. 39HPCh. 5.4 - Prob. 40HPCh. 5.4 - Prob. 41HPCh. 5.4 - Prob. 42HPCh. 5.4 - Prob. 43HPCh. 5.4 - Prob. 44STPCh. 5.4 - Prob. 45STPCh. 5.4 - Prob. 46STPCh. 5.4 - Prob. 47STPCh. 5.4 - Prob. 48SRCh. 5.4 - Prob. 49SRCh. 5.4 - Prob. 50SRCh. 5.4 - Prob. 51SRCh. 5.4 - Prob. 52SRCh. 5.4 - Prob. 53SRCh. 5.4 - Prob. 54SRCh. 5.4 - Prob. 55SRCh. 5.4 - Prob. 56SRCh. 5.4 - Prob. 57SRCh. 5.4 - Prob. 58SRCh. 5.4 - Prob. 59SRCh. 5.4 - Prob. 60SRCh. 5.4 - Prob. 61SRCh. 5.4 - Prob. 62SRCh. 5.4 - Prob. 63SRCh. 5.4 - Prob. 64SCh. 5.4 - Prob. 65SCh. 5.4 - Prob. 66SCh. 5.4 - Prob. 67SCh. 5.4 - Prob. 68SCh. 5.4 - Prob. 69SCh. 5.4 - Prob. 70SCh. 5.4 - Prob. 71SCh. 5.4 - Prob. 72SCh. 5.5 - Prob. 1BCYPCh. 5.5 - Prob. 2CYPCh. 5.5 - Prob. 3ACYPCh. 5.5 - Prob. 3BCYPCh. 5.5 - Prob. 20PPSCh. 5.5 - Prob. 24PPSCh. 5.5 - Prob. 25PPSCh. 5.5 - Prob. 26PPSCh. 5.5 - Prob. 27PPSCh. 5.5 - Prob. 28PPSCh. 5.5 - Prob. 29PPSCh. 5.5 - Prob. 32PPSCh. 5.5 - Prob. 33PPSCh. 5.5 - Prob. 34PPSCh. 5.5 - Prob. 35PPSCh. 5.5 - Prob. 36PPSCh. 5.5 - Prob. 37PPSCh. 5.5 - Prob. 38PPSCh. 5.5 - Prob. 39PPSCh. 5.5 - Prob. 40PPSCh. 5.5 - Prob. 41PPSCh. 5.5 - Prob. 43HPCh. 5.5 - Prob. 44HPCh. 5.5 - Prob. 45HPCh. 5.5 - Prob. 1ACYPCh. 5.5 - Prob. 1CYUCh. 5.5 - Prob. 2CYUCh. 5.5 - Prob. 3CYUCh. 5.5 - Prob. 4CYUCh. 5.5 - Prob. 5CYUCh. 5.5 - Prob. 6CYUCh. 5.5 - Prob. 7CYUCh. 5.5 - Prob. 8PPSCh. 5.5 - Prob. 9PPSCh. 5.5 - Prob. 10PPSCh. 5.5 - Prob. 11PPSCh. 5.5 - Prob. 12PPSCh. 5.5 - Prob. 13PPSCh. 5.5 - Prob. 14PPSCh. 5.5 - Prob. 15PPSCh. 5.5 - Prob. 16PPSCh. 5.5 - Prob. 17PPSCh. 5.5 - Prob. 18PPSCh. 5.5 - Prob. 19PPSCh. 5.5 - Prob. 21PPSCh. 5.5 - Prob. 22PPSCh. 5.5 - Prob. 23PPSCh. 5.5 - Prob. 30PPSCh. 5.5 - Prob. 31PPSCh. 5.5 - Prob. 42PPSCh. 5.5 - Prob. 46HPCh. 5.5 - Prob. 47HPCh. 5.5 - Prob. 48STPCh. 5.5 - Prob. 49STPCh. 5.5 - Prob. 50STPCh. 5.5 - Prob. 51STPCh. 5.5 - Prob. 52SRCh. 5.5 - Prob. 53SRCh. 5.5 - Prob. 54SRCh. 5.5 - Prob. 55SRCh. 5.5 - Prob. 56SRCh. 5.5 - Prob. 57SRCh. 5.5 - Prob. 58SRCh. 5.5 - Prob. 59SRCh. 5.5 - Prob. 60SRCh. 5.5 - Prob. 61SCh. 5.5 - Prob. 62SCh. 5.5 - Prob. 63SCh. 5.5 - Prob. 64SCh. 5.5 - Prob. 65SCh. 5.5 - Prob. 66SCh. 5.5 - Prob. 67SCh. 5.5 - Prob. 68SCh. 5.6 - Prob. 13PPSCh. 5.6 - Prob. 14PPSCh. 5.6 - Prob. 15PPSCh. 5.6 - Prob. 16PPSCh. 5.6 - Prob. 17PPSCh. 5.6 - Prob. 20PPSCh. 5.6 - Prob. 21PPSCh. 5.6 - Prob. 22PPSCh. 5.6 - Prob. 25PPSCh. 5.6 - Prob. 1ACYPCh. 5.6 - Prob. 1BCYPCh. 5.6 - Prob. 2ACYPCh. 5.6 - Prob. 2BCYPCh. 5.6 - Prob. 3ACYPCh. 5.6 - Prob. 3BCYPCh. 5.6 - Prob. 4CYPCh. 5.6 - Prob. 1CYUCh. 5.6 - Prob. 2CYUCh. 5.6 - Prob. 3CYUCh. 5.6 - Prob. 4CYUCh. 5.6 - Prob. 5CYUCh. 5.6 - Prob. 6CYUCh. 5.6 - Prob. 7CYUCh. 5.6 - Prob. 8CYUCh. 5.6 - Prob. 9CYUCh. 5.6 - Prob. 10CYUCh. 5.6 - Prob. 11CYUCh. 5.6 - Prob. 12PPSCh. 5.6 - Prob. 18PPSCh. 5.6 - Prob. 19PPSCh. 5.6 - Prob. 23PPSCh. 5.6 - Prob. 24PPSCh. 5.6 - Prob. 26PPSCh. 5.6 - Prob. 27PPSCh. 5.6 - Prob. 28PPSCh. 5.6 - Prob. 29PPSCh. 5.6 - Prob. 30PPSCh. 5.6 - Prob. 31PPSCh. 5.6 - Prob. 32PPSCh. 5.6 - Prob. 33PPSCh. 5.6 - Prob. 34PPSCh. 5.6 - Prob. 35PPSCh. 5.6 - Prob. 36PPSCh. 5.6 - Prob. 37PPSCh. 5.6 - Prob. 38PPSCh. 5.6 - Prob. 39PPSCh. 5.6 - Prob. 40PPSCh. 5.6 - Prob. 41PPSCh. 5.6 - Prob. 42PPSCh. 5.6 - Prob. 43PPSCh. 5.6 - Prob. 44PPSCh. 5.6 - Prob. 45PPSCh. 5.6 - Prob. 46HPCh. 5.6 - Prob. 47HPCh. 5.6 - Prob. 48HPCh. 5.6 - Prob. 49HPCh. 5.6 - Prob. 50HPCh. 5.6 - Prob. 51STPCh. 5.6 - Prob. 52STPCh. 5.6 - Prob. 53STPCh. 5.6 - Prob. 54STPCh. 5.6 - Prob. 55SRCh. 5.6 - Prob. 56SRCh. 5.6 - Prob. 57SRCh. 5.6 - Prob. 58SRCh. 5.6 - Prob. 59SRCh. 5.6 - Prob. 60SRCh. 5.6 - Prob. 61SRCh. 5.6 - Prob. 62SRCh. 5.6 - Prob. 63SRCh. 5.6 - Prob. 64SRCh. 5.6 - Prob. 65SCh. 5 - Prob. 1SGRCh. 5 - Prob. 2SGRCh. 5 - Prob. 3SGRCh. 5 - Prob. 4SGRCh. 5 - Prob. 5SGRCh. 5 - Prob. 6SGRCh. 5 - Prob. 7SGRCh. 5 - Prob. 9SGRCh. 5 - Prob. 10SGRCh. 5 - Prob. 11SGRCh. 5 - Prob. 12SGRCh. 5 - Prob. 13SGRCh. 5 - Prob. 14SGRCh. 5 - Prob. 15SGRCh. 5 - Prob. 16SGRCh. 5 - Prob. 17SGRCh. 5 - Prob. 18SGRCh. 5 - Prob. 20SGRCh. 5 - Prob. 21SGRCh. 5 - Prob. 22SGRCh. 5 - Prob. 23SGRCh. 5 - Prob. 24SGRCh. 5 - Prob. 25SGRCh. 5 - Prob. 26SGRCh. 5 - Prob. 30SGRCh. 5 - Prob. 41SGRCh. 5 - Prob. 44SGRCh. 5 - Prob. 46SGRCh. 5 - Prob. 47SGRCh. 5 - 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Prob. 27MCQCh. 5 - Prob. 8SGRCh. 5 - Prob. 19SGRCh. 5 - Prob. 27SGRCh. 5 - Prob. 28SGRCh. 5 - Prob. 29SGRCh. 5 - Prob. 31SGRCh. 5 - Prob. 32SGRCh. 5 - Prob. 33SGRCh. 5 - Prob. 34SGRCh. 5 - Prob. 35SGRCh. 5 - Prob. 36SGRCh. 5 - Prob. 37SGRCh. 5 - Prob. 38SGRCh. 5 - Prob. 39SGRCh. 5 - Prob. 40SGRCh. 5 - Prob. 42SGRCh. 5 - Prob. 43SGRCh. 5 - Prob. 45SGRCh. 5 - Prob. 1PTCh. 5 - Prob. 2PTCh. 5 - Prob. 3PTCh. 5 - Prob. 4PTCh. 5 - Prob. 5PTCh. 5 - Prob. 6PTCh. 5 - Prob. 7PTCh. 5 - Prob. 8PTCh. 5 - Prob. 9PTCh. 5 - Prob. 10PTCh. 5 - Prob. 11PTCh. 5 - Prob. 12PTCh. 5 - Prob. 13PTCh. 5 - Prob. 14PTCh. 5 - Prob. 17PTCh. 5 - Prob. 18PTCh. 5 - Prob. 25PTCh. 5 - Prob. 26PTCh. 5 - Prob. 1STPCh. 5 - Prob. 2STPCh. 5 - Prob. 3STPCh. 5 - Prob. 4STPCh. 5 - Prob. 5STPCh. 5 - Prob. 6STPCh. 5 - Prob. 7STPCh. 5 - Prob. 8STPCh. 5 - Prob. 9STPCh. 5 - Prob. 10STPCh. 5 - Prob. 11STPCh. 5 - Prob. 12STPCh. 5 - Prob. 13STPCh. 5 - Prob. 14STPCh. 5 - Prob. 15STPCh. 5 - Prob. 16STPCh. 5 - Prob. 17STP
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- @when ever one Point sets in x are closed a collection of functions which separates Points from closed set will separates Point. 18 (prod) is product topological space then VaeA (xx, Tx) is homeomorphic to sul space of the Product space (Txa, prod). KeA © The Bin Projection map B: Tx XP is continuous and open but heed hot to be closed. A collection (SEA) of continuos function oha topolgical Space X se partes Points from closed sets inx iff the set (v) for KEA and Vopen set in Xx from a base for top on x.arrow_forwardSimply:(p/(x-a))-(p/(x+a))arrow_forwardQ1lal Let X be an arbitrary infinite set and let r the family of all subsets F of X which do not contain a particular point x, EX and the complements F of all finite subsets F of X show that (X.r) is a topology. bl The nbhd system N(x) at x in a topological space X has the following properties NO- N(x) for any xX N1- If N EN(x) then x€N N2- If NEN(x), NCM then MeN(x) N3- If NEN(x), MEN(x) then NOMEN(x) N4- If N = N(x) then 3M = N(x) such that MCN then MeN(y) for any уем Show that there exist a unique topology τ on X. Q2\a\let (X,r) be the topology space and BST show that ẞ is base for a topology on X iff for any G open set xEG then there exist A Eẞ such that x E ACG. b\Let ẞ is a collection of open sets in X show that is base for a topology on X iff for each xex the collection B, (BEB\xEB) is is a nbhd base at x. - Q31 Choose only two: al Let A be a subspace of a space X show that FCA is closed iff F KOA, K is closed set in X. الرياضيات b\ Let X and Y be two topological space and f:X -…arrow_forward
- Q1\ Let X be a topological space and let Int be the interior operation defined on P(X) such that 1₁.Int(X) = X 12. Int (A) CA for each A = P(X) 13. Int (int (A) = Int (A) for each A = P(X) 14. Int (An B) = Int(A) n Int (B) for each A, B = P(X) 15. A is open iff Int (A) = A Show that there exist a unique topology T on X. Q2\ Let X be a topological space and suppose that a nbhd base has been fixed at each x E X and A SCX show that A open iff A contains a basic nbdh of each its point Q3\ Let X be a topological space and and A CX show that A closed set iff every limit point of A is in A. A'S A ACA Q4\ If ẞ is a collection of open sets in X show that ẞ is a base for a topology on X iff for each x E X then ẞx = {BE B|x E B} is a nbhd base at x. Q5\ If A subspace of a topological space X, if x Є A show that V is nbhd of x in A iff V = Un A where U is nbdh of x in X.arrow_forward+ Theorem: Let be a function from a topological space (X,T) on to a non-empty set y then is a quotient map iff vesy if f(B) is closed in X then & is >Y. ie Bclosed in bp closed in the quotient topology induced by f iff (B) is closed in x- التاريخ Acy الموضوع : Theorem:- IP & and I are topological space and fix sy is continuous او function and either open or closed then the topology Cony is the quatient topology p proof: Theorem: Lety have the quotient topology induced by map f of X onto y. The-x: then an arbirary map g:y 7 is continuous 7. iff gof: x > z is "g of continuous Continuous function farrow_forwardFor the problem below, what are the possible solutions for x? Select all that apply. 2 x²+8x +11 = 0 x2+8x+16 = (x+4)² = 5 1116arrow_forward
- For the problem below, what are the possible solutions for x? Select all that apply. x² + 12x - 62 = 0 x² + 12x + 36 = 62 + 36 (x+6)² = 98arrow_forwardSelect the polynomials below that can be solved using Completing the Square as written. 6m² +12m 8 = 0 Oh²-22x 7 x²+4x-10= 0 x² + 11x 11x 4 = 0arrow_forwardProve that the usual toplogy is firast countble or hot and second countble. ①let cofinte toplogy onx show that Sivast countble or hot and second firast. 3) let (x,d) be matricspace show that is first and second countble. 6 Show that Indiscret toplogy is firstand Second op countble or not.arrow_forward
- a) Find the scalars p, q, r, s, k1, and k2. b) Is there a different linearly independent eigenvector associated to either k1 or k2? If yes,find it. If no, briefly explain.arrow_forwardThis box plot represents the score out of 90 received by students on a driver's education exam. 75% of the students passed the exam. What is the minimum score needed to pass the exam? Submitting x and Whickers Graph Low 62, C 62 66 70 74 78 82 86 90 Driver's education exam score (out of 90)arrow_forwardHow many different rectangles can be made whose side lengths, in centimeters, are counting numbers and whose are is 1,159 square centimeters? Draw and label all possible rectangles.arrow_forward
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