COLLEGE PHYSICS,VOL.1
2nd Edition
ISBN: 9781111570958
Author: Giordano
Publisher: CENGAGE L
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Chapter 5, Problem 9Q
To determine
Obtain a relationship between the orbital period and orbital radius, and compare the result with the Kepler’s third law.
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Chapter 5 Solutions
COLLEGE PHYSICS,VOL.1
Ch. 5.1 - Velocity and Acceleration in Circular Motion...Ch. 5.1 - Prob. 5.2CCCh. 5.2 - Prob. 5.3CCCh. 5.3 - Prob. 5.5CCCh. 5.4 - Prob. 5.6CCCh. 5.4 - Prob. 5.7CCCh. 5 - Prob. 1QCh. 5 - Prob. 2QCh. 5 - Prob. 3QCh. 5 - Consider the Cavendish experiment in Figure 5.22....
Ch. 5 - Prob. 5QCh. 5 - Prob. 6QCh. 5 - Prob. 7QCh. 5 - What force makes it possible for a car to move...Ch. 5 - Prob. 9QCh. 5 - Prob. 10QCh. 5 - Prob. 11QCh. 5 - Prob. 12QCh. 5 - Prob. 13QCh. 5 - Prob. 14QCh. 5 - Prob. 15QCh. 5 - Prob. 16QCh. 5 - Prob. 17QCh. 5 - Prob. 18QCh. 5 - Plutos mass. In 1978, it was discovered that Pluto...Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10PCh. 5 - A compact disc spins at 2.5 revolutions per...Ch. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Consider the motion of a rock tied to a string of...Ch. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 29PCh. 5 - Consider a Ferris wheel in which the chairs hang...Ch. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 64PCh. 5 - Prob. 65PCh. 5 - Prob. 66PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - A rock of mass m is tied to a string of length L...Ch. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77P
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- What is the orbital radius of an Earth satellite having a period of 1.00 h? (b) What is unreasonable about this result?arrow_forwardModel the Moons orbit around the Earth as an ellipse with the Earth at one focus. The Moons farthest distance (apogee) from the center of the Earth is rA = 4.05 108 m, and its closest distance (perigee) is rP = 3.63 108 m. a. Calculate the semimajor axis of the Moons orbit. b. How far is the Earth from the center of the Moons elliptical orbit? c. Use a scale such as 1 cm 108 m to sketch the EarthMoon system at apogee and at perigee and the Moons orbit. (The semiminor axis of the Moons orbit is roughly b = 3.84 108 m.)arrow_forwardLet gM represent the difference in the gravitational fields produced by the Moon at the points on the Earths surface nearest to and farthest from the Moon. Find the fraction gM/g, where g is the Earths gravitational field. (This difference is responsible for the occurrence of the lunar tides on the Earth.)arrow_forward
- To find some of the parameters characterizing an object moving in a circular orbit.The motivation for Isaac Newton to discover his laws of motion was to explain the properties of planetary orbits that were observed by Tycho Brahe and analyzed by Johannes Kepler. A good starting point for understanding this (as well as the speed of the space shuttle and the height of geostationary satellites) is the simplest orbit: a circular one. This problem concerns the properties of circular orbits for a satellite orbiting a planet of mass M. For all parts of this problem, where appropriate, use G for the universal gravitational constant. Find the orbital speed v of a satellite in a circular orbit of radius R around a planet of mass M . Express the orbital speed in terms of G , M , and R . Find the kinetic energy K of a satellite with mass m in a circular orbit of radius R around a planet of mass M . Express your answer in terms of m , M , G , and R . Find the satellite's orbital…arrow_forwardThe International Space Station is in a 210-mile-high orbit. What is the station's orbital speed? The radius of Earth is 6.37×10^6 m, its mass is 5.98×10^24kg. Express your answer with the appropriate units. What is the station's orbital period? Express your answer in minutes.arrow_forwardIn recent years, scientists have discovered hundreds of planets orbiting other stars. Some of these planets are in orbits that are similar to that of earth, which orbits the sun (MsunMsun = 1.99× 10^30kg) at a distance of 1.50 × 10^11 m, called 1 astronomical unit (1 auau). Others have extreme orbits that are much different from anything in our solar system. The following problem relates to one of these planets that follows circular orbit around its star. WASP-32b orbits with a period of only 2.7 days a star with a mass that is 1.1 times that of the sun. How many au from the star is this planet? Assume the orbital period of earth is 365 days.arrow_forward
- A satellite has an orbital radius of 100km above the earth's surface. Earths mass= 5.97x10^24kg. Earths radius=6.38x10^6. What is the speed of the satellite? How many minutes does it take the satellite to complete one orbit?arrow_forwardScientists determine the masses of planets by observing the effect of the gravitational field of those planets on nearby objects - mainly upon their moons. By measuring the orbital period and orbital radius of a moon about a planet, Newton's laws of motion can be used to determine the mass of the planet. Phobos, a moon of the planet Mars, was discovered in 1877. It's orbital radius is 9380 km and its orbital period is 0.319 days (2.77 x 104 seconds). Determine the mass of Mars based on this data.arrow_forwardNewton’s version of Kepler’s third law is: P2 = 4 π2 / [G (M1 + M2)] × a3. The space shuttle orbits 271 km above the Earth's surface. How often do the astronauts see a sunrise (in minutes)? Use the gravitational constant G = 6.67 × 10-11 m3 kg-1 s-2, the mass of the Earth M = 5.97 × 1024 kg, and the radius of the Earth to be 7000 km.arrow_forward
- A 200 kg satellite is orbiting around the Earth at an altitude of 35768 km above Earth's equator. Since the Earth's radius is 6378 km, the satellite is (35768 km + 6378 km) = 42146 km from the center of the Earth. (The mass of the Earth is 5,972 x 1024 kg.) a) What is the gravitational force between the Earth and the satellite? b) What is the acceleration of the satellite due to this gravitational force? c) Assuming the satellite is orbiting the Earth in a circular orbit, what is the speed of the satellite? d) How long does it take the satellite to complete one orbit around the Earth? Show your answer in unit of day.,arrow_forwardOn October 15, 2001, a planet was discovered orbiting around the star HD68988. Its orbital distance was measured to be Part A 10.5 million kilometers from the center of the star, and its orbital period was estimated at 6.3 days. What is the mass of HD68988? For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Kepler's third law. Express your answer in kilograms. ΑΣφ ? M = kg Submit Request Answer Part B What is the mass of HD68988? Express your answer in terms of our sun's mass. M = Msun Submit Request Answerarrow_forwardIn recent years, scientists have discovered hundreds of planets orbiting other stars. Some of these planets are in orbits that are similar to that of earth, which orbits the sun (MsunMsun = 1.99 ×× 103030 kgkg) at a distance of 1.50 ×× 101111 mm, called 1 astronomical unit (1 auau). Others have extreme orbits that are much different from anything in our solar system. The following problem relates to one of these planets that follows circular orbit around its star. WASP-32b orbits with a period of only 2.7 days a star with a mass that is 1.1 times that of the sun. How many au from the star is this planet? Assume the orbital period of earth is 365 days. Express your answer in astronomical units.arrow_forward
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Kepler's Three Laws Explained; Author: PhysicsHigh;https://www.youtube.com/watch?v=kyR6EO_RMKE;License: Standard YouTube License, CC-BY