Chapter 5, Problem 90E

Interpretation Introduction

Interpretation:Time taken to effuse $1.0{\text{ L Cl}}_2$ gas is to be calculated.

Concept introduction:Graham’s law of effusion gives relation of rate of effusion with molar mass. Rate of effusion is inversely related to square root of molar mass of its particle. Expression of this law is as follows:

  $\frac{\text{Effusion rate of A}}{\text{Effusion rate of B}}=\sqrt{\frac{M_{\text{B}}}{M_{\text{A}}}}$

Where,

• $M_{\text{B}}$ is molar mass of gas $\text{B}$ .
• $M_{\text{A}}$ is molar mass of gas $\text{A}$ .