Chapter 5, Problem 66QP

Interpretation Introduction

Interpretation:

The enthalpy of formationand neutralization are to be calculated.

Concept introduction:

The standard enthalpy for a reaction is the change in enthalpy that occursunder standard conditions that is at room temperature and pressure.

The standard enthalpy of the reaction is to be determined using the equation given below:

$\Delta H{°}_{\text{rxn}}={\displaystyle \sum n}\Delta H_{\text{f}}^{°}\left(\text{products}\right)-{\displaystyle \sum m}\Delta H_{\text{f}}^{°}\left(\text{reactants}\right)$

Here, the stoichiometric coefficients are represented by m for reactants and n for products, and enthalpy of formation under standard conditions is represented by $\Delta H_{\text{f}}^{°}$.

The value of enthalpy of formation of an element is zero at its most stable state.