
Concept explainers
(a)
Interpretation:
The electron dot formula for hydrogen is to be drawn.
Concept introduction:
The electron dot formula for an element is a representation of chemical formula of an element with valance electrons of the atom. The electrons are denoted by dots in the electron dot formula. Only the valence electrons are presented as dots in the electron dot formula for an element.

Answer to Problem 61E
The electron dot formula for hydrogen is
Explanation of Solution
The hydrogen belongs to the Group
The general electronic configuration for the outermost shell of the Group
The number of valence electrons in hydrogen is
Therefore, The electron dot formula for hydrogen is
The electron dot formula for hydrogen is
(b)
Interpretation:
The electron dot formula for boron is to be drawn.
Concept introduction:
The electron dot formula for an element is a representation of chemical formula of an element with valance electrons of the atom. The electrons are denoted by dots in the electron dot formula. Only the valence electrons are presented as dots in the electron dot formula for an element.

Answer to Problem 61E
The electron dot formula for boron is
Explanation of Solution
The boron belongs to the Group
The general electronic configuration for the outermost shell of the Group
The total number of electrons present in the outermost shell of an element of the Group
The number of valence electrons in boron is
Therefore, the electron dot formula for boron is
The electron dot formula for boron is
(c)
Interpretation:
The electron dot formula for nitrogen is to be drawn.
Concept introduction:
The electron dot formula for an element is a representation of chemical formula of an element with valance electrons of the atom. The electrons are denoted by dots in the electron dot formula. Only the valence electrons are presented as dots in the electron dot formula for an element.

Answer to Problem 61E
The electron dot formula for nitrogen is
Explanation of Solution
The nitrogen belongs to the Group
The general electronic configuration for the outermost shell of the Group
The total number of electrons present in the outermost shell of an element of the Group
The number of valence electrons in nitrogen is
Therefore, the electron dot formula for nitrogen is
The electron dot formula for nitrogen is
(d)
Interpretation:
The electron dot formula for fluorine is to be drawn.
Concept introduction:
The electron dot formula for an element is a representation of chemical formula of an element with valance electrons of the atom. The electrons are denoted by dots in the electron dot formula. Only the valence electrons are presented as dots in the electron dot formula for an element.

Answer to Problem 61E
The electron dot formula for fluorine is
Explanation of Solution
The fluorine belongs to the Group
The general electronic configuration for the outermost shell of the Group
The total number of electrons present in the outermost shell of an element of the Group
The number of valence electrons in fluorine is
Therefore, the electron dot formula for fluorine is
The electron dot formula for fluorine is
(e)
Interpretation:
The electron dot formula for calcium is to be drawn.
Concept introduction:
The electron dot formula for an element is a representation of chemical formula of an element with valance electrons of the atom. The electrons are denoted by dots in the electron dot formula. Only the valence electrons are presented as dots in the electron dot formula for an element.

Answer to Problem 61E
The electron dot formula for calcium is
Explanation of Solution
The calcium belongs to the Group
The general electronic configuration for the outermost shell of the Group
Only two electrons are present in the
The number of valence electrons in calcium is
Therefore, the electron dot formula for calcium is
The electron dot formula for calcium is
(f)
Interpretation:
The electron dot formula for silicon is to be drawn.
Concept introduction:
The electron dot formula for an element is a representation of chemical formula of an element with valance electrons of the atom. The electrons are denoted by dots in the electron dot formula. Only the valence electrons are presented as dots in the electron dot formula for an element.

Answer to Problem 61E
The electron dot formula for silicon is
Explanation of Solution
The silicon belongs to the Group
The general electronic configuration for the outermost shell of the Group
The total number of electrons present in the outermost shell of an element of the Group
The number of valence electrons in silicon is
Therefore, the electron dot formula for silicon is
The electron dot formula for silicon is
(g)
Interpretation:
The electron dot formula for oxygen is to be drawn.
Concept introduction:
The electron dot formula for an element is a representation of chemical formula of an element with valance electrons of the atom. The electrons are denoted by dots in the electron dot formula. Only the valence electrons are presented as dots in the electron dot formula for an element.

Answer to Problem 61E
The electron dot formula for oxygen is
Explanation of Solution
The oxygen belongs to the Group
The general electronic configuration for the outermost shell of the Group
The total number of electrons present in the outermost shell of an element of the Group
The number of valence electrons in oxygen is
Therefore, the electron dot formula for oxygen is
The electron dot formula for oxygen is
(h)
Interpretation:
The electron dot formula for argon is to be drawn.
Concept introduction:
The electron dot formula for an element is a representation of chemical formula of an element with valance electrons of the atom. The electrons are denoted by dots in the electron dot formula. Only the valence electrons are presented as dots in the electron dot formula for an element.

Answer to Problem 61E
The electron dot formula for argon is
Explanation of Solution
The argon belongs to the Group
The general electronic configuration for the outermost shell of the Group
The total number of electrons present in the outermost shell of an element of the Group
The number of valence electrons in elements of argon is
Therefore, the electron dot formula for argon is
The electron dot formula for argon is
Want to see more full solutions like this?
Chapter 5 Solutions
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
- Draw the Haworth projection of the disaccharide made by joining D-glucose and D-mannose with a ẞ(1-4) glycosidic bond. If the disaccharide has more than one anomer, you can draw any of them. Click and drag to start drawing a structure. Xarrow_forwardEpoxides can be opened in aqueous acid or aqueous base to produce diols (molecules with two OH groups). In this question, you'll explore the mechanism of epoxide opening in aqueous acid. 2nd attempt Be sure to show all four bonds at stereocenters using hash and wedge lines. 0 0 Draw curved arrows to show how the epoxide reacts with hydronium ion. 100 +1: 1st attempt Feedback Be sure to show all four bonds at stereocenters using hash and wedge lines. See Periodic Table See Hint H A 5 F F Hr See Periodic Table See Hintarrow_forward03 Question (1 point) For the reaction below, draw both of the major organic products. Be sure to consider stereochemistry. > 1. CH₂CH₂MgBr 2. H₂O 3rd attempt Draw all four bonds at chiral centers. Draw all stereoisomers formed. Draw the structures here. e 130 AN H See Periodic Table See Hint P C Brarrow_forward
- You may wish to address the following issues in your response if they are pertinent to the reaction(s) you propose to employ:1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Please make it in detail and draw it out too in what step what happens. Thank you for helping me!arrow_forward1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Everything in detail and draw out and write it.arrow_forwardCalculating the pH at equivalence of a titration 3/5 Izabella A chemist titrates 120.0 mL of a 0.7191M dimethylamine ((CH3)2NH) solution with 0.5501 M HBr solution at 25 °C. Calculate the pH at equivalence. The pk of dimethylamine is 3.27. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ✓ 18 Ar Boarrow_forward
- Alcohols can be synthesized using an acid-catalyzed hydration of an alkene. An alkene is combined with aqueous acid (e.. sulfuric acid in water). The reaction mechanism typically involves a carbocation intermediate. > 3rd attempt 3343 10 8 Draw arrows to show the reaction between the alkene and hydronium ion. that 2nd attempt Feedback 1st attempt تعمال Ju See Periodic Table See Hint F D Ju See Periodic Table See Hintarrow_forwardDraw the simplified curved arrow mechanism for the reaction of acetone and CHgLi to give the major product. 4th attempt Π Draw the simplified curved arrow mechanism T 3rd attempt Feedback Ju See Periodic Table See Hint H -H H -I H F See Periodic Table See Hintarrow_forwardSelect the correct reagent to accomplish the first step of this reaction. Then draw a mechanism on the Grignard reagent using curved arrow notation to show how it is converted to the final product. 4th attempt Part 1 (0.5 point) Select the correct reagent to accomplish the first step of this reaction. Choose one: OA Mg in ethanol (EtOH) OB. 2 Li in THF O C. Li in THF D. Mg in THF O E Mg in H2O Part 2 (0.5 point) Br Part 1 Bri Mg CH B CH, 1 Draw intermediate here, but no arrows. © TE See Periodic Table See Hint See Hint ין Harrow_forward
- Select the product for the following reaction. HO HO PCC OH ○ OH O HO ○ HO HO HOarrow_forward5:45 Х Select the final product for the following reaction sequence. O O 1. Mg. ether 2.D.Oarrow_forwardBased on the chart Two similarities between the molecule with alpha glycosidic linkages. Two similarities between the molecules with beta glycosidtic linkages. Two differences between the alpha and beta glycosidic linkages.arrow_forward
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningWorld of ChemistryChemistryISBN:9780618562763Author:Steven S. ZumdahlPublisher:Houghton Mifflin College Div

