Chapter 5, Problem 5J.3ST

Interpretation Introduction

Interpretation:

For the formation reaction of water, the biological standard potential has to be calculated.

Concept Introduction:

Biological standard potential:

The biological cell potential is given by,

$\begin{array}{l}{\text{E}}^{\oplus }\text{=}{\text{E}}^{\sout{0}}\text{-}\frac{{\text{7v}}_p\text{R}\text{T}\text{ln}\text{10}}{\text{vF}}\\ \text{where,}\\ {\text{E}}^{\oplus }\text{-}\text{standard}\text{biological}\text{potential}\\ {\text{E}}^{\sout{0}}\text{-}\text{standard}\text{cell potential}\\ \text{F}\text{-}\text{Faraday's}\text{constant}\\ \text{v}\text{-}\text{number}\text{of}\text{electrons}\text{transfered}\\ \text{R}\text{-}\text{gas}\text{constant}\text{and}\text{T}\text{-}\text{temperature}\end{array}$