(a) Interpretation: The amount of concentrated HCl ( a q ) should be determined. Concept introduction: By applying M 1 V 1 = M 2 V 2 formula, the volume of concentrated H C l ( a q ) solution for the preparation of 20.0 L 0.10 M H C l ( a q ) solution could be determined. M 1 V 1 = M 2 V 2 Where, M 1 is the molarity of the concentrated H C l ( a q ) solution. M 2 is the molarity of the required diluted H C l ( a q ) solution. V 1 is the volume of the concentrated H C l ( a q ) solution. V 2 is the volume of the required diluted H C l ( a q ) solution.
(a) Interpretation: The amount of concentrated HCl ( a q ) should be determined. Concept introduction: By applying M 1 V 1 = M 2 V 2 formula, the volume of concentrated H C l ( a q ) solution for the preparation of 20.0 L 0.10 M H C l ( a q ) solution could be determined. M 1 V 1 = M 2 V 2 Where, M 1 is the molarity of the concentrated H C l ( a q ) solution. M 2 is the molarity of the required diluted H C l ( a q ) solution. V 1 is the volume of the concentrated H C l ( a q ) solution. V 2 is the volume of the required diluted H C l ( a q ) solution.
Solution Summary: The author explains the formula for determining the volume of concentrated HCl(aq) solution for preparation of 20.0L 0.10M
#1. Retro-Electrochemical Reaction: A ring has been made, but the light is causing the molecule to un-
cyclize. Undo the ring into all possible molecules. (2pts, no partial credit)
hv
Don't used Ai solution
Chapter 5 Solutions
General Chemistry: Principles And Modern Applications Plus Mastering Chemistry With Pearson Etext -- Access Card Package (11th Edition)
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