Thiosulfate ion, S 2 O 3 2 , is a reducing agent can be oxidized to different products, depending on the strength of the oxidizing agent and other conditions. By adding H ' , H 2 O , and/or OH- as necessary, write redox equations to show the oxidation of S 2 O 3 2 to a. S 4 O 6 2- by I 2 (iodide ion is another product) b. HSO 4 by CI 2 (iodide ion is another product) c. SO 4 2 − , by OCI- basic solution (chloride ion is another product)
Thiosulfate ion, S 2 O 3 2 , is a reducing agent can be oxidized to different products, depending on the strength of the oxidizing agent and other conditions. By adding H ' , H 2 O , and/or OH- as necessary, write redox equations to show the oxidation of S 2 O 3 2 to a. S 4 O 6 2- by I 2 (iodide ion is another product) b. HSO 4 by CI 2 (iodide ion is another product) c. SO 4 2 − , by OCI- basic solution (chloride ion is another product)
Solution Summary: The author explains that a balanced redox chemical equation for oxidization of S_2TextO32- by I 2 should be obtained.
Thiosulfate ion,
S
2
O
3
2
, is a reducing agent can be oxidized to different products, depending on the strength of the oxidizing agent and other conditions. By adding H',
H
2
O
, and/or OH- as necessary, write redox equations to show the oxidation of
S
2
O
3
2
to a.
S
4
O
6
2-
by I2(iodide ion is another product) b.
HSO
4
by CI2(iodide ion is another product) c.
SO
4
2
−
, by OCI- basic solution (chloride ion is another product)
Predict the major products of this organic reaction.
If there will be no major products, check the box under the drawing area instead.
No reaction.
:
+
Х
è
OH
K Cr O
2 27
2 4' 2
Click and drag to start
drawing a structure.
Laminar compounds are characterized by havinga) a high value of the internal surface of the solid.b) a high adsorption potential.
Intercalation compounds have their sheetsa) negatively charged.b) positively charged.
Chapter 5 Solutions
General Chemistry: Principles And Modern Applications Plus Mastering Chemistry With Pearson Etext -- Access Card Package (11th Edition)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.