Chemistry: An Atoms-Focused Approach (Second Edition)
2nd Edition
ISBN: 9780393614053
Author: Thomas R. Gilbert, Rein V. Kirss, Stacey Lowery Bretz, Natalie Foster
Publisher: W. W. Norton & Company
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when performing the reaction that involves 2 equivalents of 3-(diethylamino)-phenol and Phthalic anhydride with sulfuric acid and water react to form rhodamine b where the Phthalic anhydride cleaves in acid and how does Excessive Washing (w/ Base) & Subsequent Resonance Structure get affected
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Please explain your steps and thought process. Thank you!
Using the general properties of equilibrium constants
At a certain temperature, the equilibrium constant K for the following reaction is 1.3 × 10 4:
Cl2(g) + CHCl3(g) HCl(g) + CC₁(g)
Use this information to complete the following table.
Suppose a 16. L reaction vessel is filled with 1.6 mol of HCI and
1.6 mol of CCl4. What can you say about the composition of the
mixture in the vessel at equilibrium?
There will be very little Cl2 and CHCl3.
☐ x10
There will be very little HCI and CCl4.
Neither of the above is true.
What is the equilibrium constant for the following reaction? Be
sure your answer has the correct number of significant digits.
HCl(g)+CC14(g)
12
Cl2(9)+CHCl3(9)
K = 0 ☐
What is the equilibrium constant for the following reaction? Be
sure your answer has the correct number of significant digits.
2 Cl₂(9)+2CHCl3(9)
2 HCl(9)+2CC₁₁(9)
K =
✓
00.
18
Ar
Chapter 5 Solutions
Chemistry: An Atoms-Focused Approach (Second Edition)
Ch. 5 - Prob. 5.1VPCh. 5 - Prob. 5.2VPCh. 5 - Prob. 5.3VPCh. 5 - Prob. 5.4VPCh. 5 - Prob. 5.5VPCh. 5 - Prob. 5.6VPCh. 5 - Prob. 5.7VPCh. 5 - Prob. 5.8VPCh. 5 - Prob. 5.9VPCh. 5 - Prob. 5.10VP
Ch. 5 - Prob. 5.11QACh. 5 - Prob. 5.12QACh. 5 - Prob. 5.13QACh. 5 - Prob. 5.14QACh. 5 - Prob. 5.15QACh. 5 - Prob. 5.16QACh. 5 - Prob. 5.17QACh. 5 - Prob. 5.18QACh. 5 - Prob. 5.19QACh. 5 - Prob. 5.20QACh. 5 - Prob. 5.21QACh. 5 - Prob. 5.22QACh. 5 - Prob. 5.23QACh. 5 - Prob. 5.24QACh. 5 - Prob. 5.25QACh. 5 - Prob. 5.26QACh. 5 - Prob. 5.27QACh. 5 - Prob. 5.28QACh. 5 - Prob. 5.29QACh. 5 - Prob. 5.30QACh. 5 - Prob. 5.31QACh. 5 - Prob. 5.32QACh. 5 - Prob. 5.33QACh. 5 - Prob. 5.34QACh. 5 - Prob. 5.35QACh. 5 - Prob. 5.36QACh. 5 - Prob. 5.37QACh. 5 - Prob. 5.38QACh. 5 - Prob. 5.39QACh. 5 - Prob. 5.40QACh. 5 - Prob. 5.41QACh. 5 - Prob. 5.42QACh. 5 - Prob. 5.43QACh. 5 - Prob. 5.44QACh. 5 - Prob. 5.45QACh. 5 - Prob. 5.46QACh. 5 - Prob. 5.47QACh. 5 - Prob. 5.48QACh. 5 - Prob. 5.49QACh. 5 - Prob. 5.50QACh. 5 - Prob. 5.51QACh. 5 - Prob. 5.52QACh. 5 - Prob. 5.53QACh. 5 - Prob. 5.54QACh. 5 - Prob. 5.55QACh. 5 - Prob. 5.56QACh. 5 - Prob. 5.57QACh. 5 - Prob. 5.58QACh. 5 - Prob. 5.59QACh. 5 - Prob. 5.60QACh. 5 - Prob. 5.61QACh. 5 - Prob. 5.62QACh. 5 - Prob. 5.63QACh. 5 - Prob. 5.64QACh. 5 - Prob. 5.65QACh. 5 - Prob. 5.66QACh. 5 - Prob. 5.67QACh. 5 - Prob. 5.68QACh. 5 - Prob. 5.69QACh. 5 - Prob. 5.70QACh. 5 - Prob. 5.71QACh. 5 - Prob. 5.72QACh. 5 - Prob. 5.73QACh. 5 - Prob. 5.74QACh. 5 - Prob. 5.75QACh. 5 - Prob. 5.76QACh. 5 - Prob. 5.77QACh. 5 - Prob. 5.78QACh. 5 - Prob. 5.79QACh. 5 - Prob. 5.80QACh. 5 - Prob. 5.81QACh. 5 - Prob. 5.82QACh. 5 - Prob. 5.83QACh. 5 - Prob. 5.84QACh. 5 - Prob. 5.85QACh. 5 - Prob. 5.86QACh. 5 - Prob. 5.87QACh. 5 - Prob. 5.88QACh. 5 - Prob. 5.89QACh. 5 - Prob. 5.90QACh. 5 - Prob. 5.91QACh. 5 - Prob. 5.92QACh. 5 - Prob. 5.93QACh. 5 - Prob. 5.94QACh. 5 - Prob. 5.95QACh. 5 - Prob. 5.96QACh. 5 - Prob. 5.97QACh. 5 - Prob. 5.98QACh. 5 - Prob. 5.99QACh. 5 - Prob. 5.100QACh. 5 - Prob. 5.101QACh. 5 - Prob. 5.102QACh. 5 - Prob. 5.103QACh. 5 - Prob. 5.104QACh. 5 - Prob. 5.105QACh. 5 - Prob. 5.106QACh. 5 - Prob. 5.107QACh. 5 - Prob. 5.108QACh. 5 - Prob. 5.109QACh. 5 - Prob. 5.110QACh. 5 - Prob. 5.111QACh. 5 - Prob. 5.112QACh. 5 - Prob. 5.113QACh. 5 - Prob. 5.114QACh. 5 - Prob. 5.115QACh. 5 - Prob. 5.116QACh. 5 - Prob. 5.117QACh. 5 - Prob. 5.118QACh. 5 - Prob. 5.119QACh. 5 - Prob. 5.120QACh. 5 - Prob. 5.121QACh. 5 - Prob. 5.122QACh. 5 - Prob. 5.123QACh. 5 - Prob. 5.124QACh. 5 - Prob. 5.125QACh. 5 - Prob. 5.126QACh. 5 - Prob. 5.127QACh. 5 - Prob. 5.128QACh. 5 - Prob. 5.129QACh. 5 - Prob. 5.130QACh. 5 - Prob. 5.131QACh. 5 - Prob. 5.132QACh. 5 - Prob. 5.133QACh. 5 - Prob. 5.134QACh. 5 - Prob. 5.135QACh. 5 - Prob. 5.136QACh. 5 - Prob. 5.137QACh. 5 - Prob. 5.138QACh. 5 - Prob. 5.139QACh. 5 - Prob. 5.140QA
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- 10. The most important reason why Br- is a better nucleophile than Cl-is ___. A. polarizability; B. size; C. solvation; D. basicity; E. polarity. Please include all steps. Thanks!arrow_forwardPredicting the qualitative acid-base properties of salts Consider the following data on some weak acids and weak bases: base acid Ка K₁₁ name formula name formula nitrous acid HNO2 4.5×10 4 pyridine CHEN 1.7 × 10 9 4 hydrofluoric acid HF 6.8 × 10 methylamine CH3NH2 | 4.4 × 10¯ Use this data to rank the following solutions in order of increasing pH. In other words, select a '1' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. solution 0.1 M NaNO2 0.1 M KF pH choose one v choose one v 0.1 M C5H5NHBr 0.1 M CH3NH3CI choose one v ✓ choose one 1 (lowest) 2 ☑ 3 4 (highest) 000 18 Ararrow_forward4. The major product from treatment of 2-propanol with the Jonesreagent is ___.A. acetone; B. none of the other answers is correct C. propene; D.propanoic acid; E carbon dioxide. Please include all steps! Thank you!arrow_forward
- 7. All of the following compounds that are at the same oxidation levelare ___.u. methyl epoxide, v. propyne, w. propanal, x. propene,y. 2,2-dihydroxypropane, z. isopropanol?A. u,v,w,y; B. u,v,w; C. v,w,y,z; D. v, z; E. x,y,z Please include all steps. Thank you!arrow_forward9. Which one of the following substituents is the worst leaving group inan SN2 reaction? A. -NH2; B. -OH; C. –F; D. NH3; E. H2O Please include all steps. Thanks!arrow_forwardUsing the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 2.5 × 105: CO(g) + H2O(g) CO2(g) + H2(g) Use this information to complete the following table. Suppose a 7.0 L reaction vessel is filled with 1.7 mol of CO and 1.7 mol of H2O. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. CO2(9)+H2(g) CO(g)+H₂O(g) What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 3 CO(g)+3H2O(g) = 3 CO2(g)+3H2(g) There will be very little CO and H2O. x10 There will be very little CO2 and H2. 000 Neither of the above is true. K = ☐ K = ☐ 18 Ararrow_forward
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- Predicting the qualitative acid-base properties of salts Consider the following data on some weak acids and weak bases: base acid K K a name formula name formula nitrous acid HNO2 4.5×10 hydroxylamine HONH2 1.1 × 10 8 hypochlorous acid HCIO 8 3.0 × 10 methylamine CH3NH2 | 4.4 × 10¯ 4 Use this data to rank the following solutions in order of increasing pH. In other words, select a '1' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. 0.1 M KCIO solution PH choose one 0.1 M NaNO2 0.1 M CH3NH3Br 0.1 M NaBr choose one ✓ choose one v ✓ choose one 1 (lowest) ☑ 2 3 4 (highest)arrow_forwardFor this Orgo problem, don't worry about question 3 below it. Please explain your thought process, all your steps, and also include how you would tackle a similar problem. Thank you!arrow_forwardUsing the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 0.84: H2(g) + 2(g) 2 HI(g) = Use this information to complete the following table. Suppose a 34. L reaction vessel is filled with 0.79 mol of HI. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little H2 and 12. ☐ x10 There will be very little HI. Neither of the above is true. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 HI(g) H₂(9)+12(9) K = What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 H2(g)+212(9) 4 HI(g) K = ☐ ☑arrow_forward
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