The volume of sulfur dioxide at 29 ∘ C and at 1.00 atm pressure has to be calculated Concept Introduction: Charles’s Law: Boyle’s law states that “ at a constant pressure (P), the volume (V) occupied by any sample of gas is directly proportional to the absolute temperature (T)’’ V α T (at constant P) For a sample of gas supposing a change in temperature, Charles’s law can be written as V f T f = V i T i (at constant P) On rearranging, we get V f = V i × T f T i (at constant P) Where, T i a n d T f are initial temperature and final temperature respectively V i a n d V f are initial volume and final volume respectively
The volume of sulfur dioxide at 29 ∘ C and at 1.00 atm pressure has to be calculated Concept Introduction: Charles’s Law: Boyle’s law states that “ at a constant pressure (P), the volume (V) occupied by any sample of gas is directly proportional to the absolute temperature (T)’’ V α T (at constant P) For a sample of gas supposing a change in temperature, Charles’s law can be written as V f T f = V i T i (at constant P) On rearranging, we get V f = V i × T f T i (at constant P) Where, T i a n d T f are initial temperature and final temperature respectively V i a n d V f are initial volume and final volume respectively
Solution Summary: The author explains how the volume of sulfur dioxide at 29circC and at 1.00 atm pressure is calculated.
The volume of sulfur dioxide at 29∘C and at 1.00 atm pressure has to be calculated
Concept Introduction:
Charles’s Law:
Boyle’s law states that “at a constant pressure (P), the volume (V) occupied by any sample of gas is directly proportional to the absolute temperature (T)’’
Vα T (at constant P)
For a sample of gas supposing a change in temperature, Charles’s law can be written as
VfTf=ViTi (at constant P)
On rearranging, we get
Vf=Vi×TfTi (at constant P)
Where,
Tiand Tf are initial temperature and final temperature respectively
Viand Vf are initial volume and final volume respectively
need help not sure what am doing wrong step by step please answer is 971A
During the lecture, we calculated the Debye length at physiological salt concentrations and temperature, i.e. at an ionic strength of 150 mM (i.e. 0.150 mol/l) and a temperature of T=310 K. We predicted that electrostatic interactions are effectively screened beyond distances of 8.1 Å in solutions with a physiological salt concentration.
What is the Debye length in a sample of distilled water with an ionic strength of 10.0 µM (i.e. 1.00 * 10-5 mol/l)? Assume room temperature, i.e. T= 298 K, and provide your answer as a numerical expression with 3 significant figures in Å (1 Å = 10-10 m).
Influence of salt concentrations on electrostatic interactions 2
Answer is 2.17A why not sure step by step please
What is the Debye length in a concentrated salt solution with an ionic strength of 2.00 mol/l? Assume room temperature, i.e. T= 298 K, and provide your answer as a numerical expression with 3 significant figures in Å (1 Å = 10-10 m).
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