(a)
Interpretation:
The type of isomers in limonene has to be identified.
Concept Introduction:
Chiral carbon: A carbon is said to be chiral carbon if it is bonded to four different substituents.
Chirality: It refers to a Carbon atom in a molecule that contains four different substituents.
Enantiomers: They are chiral molecules whose mirror images are not superimposable.
(b)
Interpretation:
Possibility of having E, Z isomers in limonene has to be identified.
Concept Introduction:
Geometric isomers: Two compounds are considered as geometric isomers of each other if both contain same number of atoms but different in their arrangement.
E configuration: The geometric isomers are given E configuration if high priority groups are placed on opposite sides of the double bond.
Z configuration: The geometric isomers are given Z configuration if high priority groups are placed on same sides of the double bond.
(c)
Interpretation:
Reason for why isomers of limonene smell differently has to be explained.
Concept Introduction:
Chiral carbon: A carbon is said to be chiral carbon if it is bonded to four different substituents.
Chirality: It refers to a Carbon atom in a molecule that contains four different substituents.
Enantiomers: They are chiral molecules whose mirror images are not superimposable.
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Chapter 5 Solutions
Organic Chemistry
- When the conjugate acid of aniline, C6H5NH3+, reacts with the acetate ion, the following reaction takes place: C6H5NH3+(aq)+CH3COO(aq)C6H5NH2(aq)+CH3COOH(aq) If Kafor C6H5NH3+ is 1.35105 and Kafor CH3COOH is 1.86105 , what is K for the reaction?arrow_forwardPyrethrins, such as jasmolin II(below), are a group of naturalcompounds synthesized by flowers of the genus Chrysanthemum(known as pyrethrum flowers) to act as insecticides.(a) Circle and name the functional groups in jasmolin II.(b) What is the hybridization of the numbered carbons?(c) Which, if any, of the numbered carbons are chiral centers?arrow_forwardFor each structure below, identify the type of molecule (one of the four classes of molecules ). Give a reason/explanation for each choice..arrow_forward
- Draw the structural formulas for the following compounds. Include all the bonds to hydrogen atoms. Be sure to answer both parts. (a) 1,2,4-trimethylbenzene: (b) chlorobenzene:arrow_forwardAnswer ALL parts of this question. Benzoic acid can be converted to the two products (A and B) shown in Figure Q24a. Draw the structures of A and B and name both compounds. (a) (b) (c) Benzoic acid OH F C LiAlH then HCI (aq.) CH₂CH₂OH, HCI OH Figure Q24a Describe, in words, the type of chemistry involved in converting benzoic acid to the two products (A and B) shown in Figure Q24a. Drawings of curly arrow mechanisms are not required. Explain why compound C is more acidic than compound D (see Figure Q24c). A Figure Q24c B D OHarrow_forwardTrue or false: (a) The C¬C bonds in benzene are all the samelength and correspond to typical single C¬C bond lengths.(b) The C¬C bond in acetylene, HCCH, is longer than theaverage C¬C bond length in benzene.arrow_forward
- a) If the pH value of an aqueous solution of trimethylamine [(CH3) 3N] is 10.75, what should be the molarity of this solution? (CH3) 3N + H2O ↔ (CH3) 3NH + + OH-, Kb = 6.3 × 10-5 b) What will be the pH of the solution prepared by dissolving 8.35 g of aniline hydrochloride (C6H5NH3 + Cl-) in 750 mL of 0.215 M aniline (C6H5NH2)? Is this solution an effective buffer? Explain (Kb = 7.4 × 10-10 for aniline, C: 12.0 g / mol, H: 1.0 g / mol, N: 14.0 g / mol, Cl: 35.4 g / mol) .arrow_forwardWrite the reagent or draw structures of the starting material or organic product(s) in the following reactions. If more than one product is formed, identify the major product where possible. (a) (b) HO OH OH H2SO4 ? Cl₂ ? FeCl3arrow_forwardBriefly, but clearly, explain why the –OH hydrogen in acetic acid (CH3CO2H) is more acidic than in ethanol (C2H5OH).arrow_forward
- 5) Which of the following compounds is aromatic? B C H Darrow_forwardReaction of (CH3)3CH with Cl2 forms two products: (CH3)2CHCH2Cl (63%) and (CH3)3CCl (37%). Why is the major product formed by cleavage of the stronger 1° C–H bond?arrow_forward4 But-2-enal, CH₂CH=CHCHO, is a pale yellow, flammable liquid with an irritating odour. (a) But-2-enal exists as two stereoisomers. Draw skeletal formulae to show the structure of the two stereoisomers of but-2-enal. (b) (i) Describe a simple chemical test that would show that but-2-enal is an aldehyde. (ii) Explain why this test gives a different result with aldehydes than it does with keton (c) But-2-enal also reacts with sodium borohydride, NaBH4. (i) Identify the organic compound formed in this reaction. (ii) State the type of chemical reaction occurring. (d) Precautions must be taken to prevent but-2-enal catching fire. Construct a balanced equation for the complete combustion of but-2-enal, C₂HO.arrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning