Concept explainers
Interpretation:
Given alkene whether has cis, trans isomerization has to be identified and if present, the structure of trans isomer has to be drawn.
Concept Introduction:
- • Name the main chain: Find the longest carbon chain and name the chain according to the number of carbon atoms it contains; is also the root name.
- • Number the carbon atoms in the main chain: The carbons are numbered, in which the substituents must get lowest possible numbers.
- • Identify the substituents, and number each: The number at where substituents are present has to be noted. The substituents written as prefix.
- • Write the names as a single word: Use the hyphen to separate the numbers from the different prefix; commas to separate numbers. If two or more different substituents are present, arrange them in alphabetical order. If two or more identical substituents are present, use prefixes di-, tri-, tetra-, but this particular prefix should not be used for alphabetizing purpose.
Alkene:
The systematic name of alkenes are written by replacing “ane” of
Trans configuration: In trans configuration, carbon atoms present in the main chain are placed on opposite sides of the carbon-carbon double bond.
Cis configuration: In cis configuration, carbon atoms present in the main chain are placed on same sides of the carbon-carbon double bond.
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Organic Chemistry
- Why do alkanes, alkenes, and alkynes have a relatively low boiling point? O They have no large intermolecular forces holding them together. O They have no diple moments or polarity. O They have a lot of electron density in a very small amout of space.arrow_forwardFill in the whole tablearrow_forwardAmong alkenes, alkynes, and aromatic hydrocarbons, onlyalkenes exhibit cis-transisomerism. Why don’t the others?arrow_forward
- What is cis-trans isomerism in alkenes? cis-trans isomerism in alkenes involves having the major groups in an alkene on the same or opposite side of the double bond cis-trans isomerism in alkenes involves having different or identical substituents at the both ends of the double bond cis-trans isomerism in alkenes involves having the major groups in an alkene in staggered or eclipsed conformations cis-trans isomerism in alkenes involves different location of double bond along the carbon chainarrow_forwardThese are different isomers for C4H8O. Which structure would not be an isomer of butanal?arrow_forward1. Although there is only one alkene with the formula C2H4 (ethene) and only one with the formula C3H6 (propene), there are several alkenes with the formula C4H8. Draw all of the possible bond line structures for alkenes with the formula C4H3 including all possible structural and stereoisomers.arrow_forward
- o When an alkene has multiple groups bonded to the main parent chain, how do we start counting the carbons along the main chain? For example, number the longest continuous carbon chain in the structure below:arrow_forwardQuestion 5: The name of compound A in Figure 5 is 1-(butan-2-yl)-3- methylcyclohexane. Use this information to determine the IUPAC name of compound B. [Numbers are separated by commas and numbers and letters by hyphens Use lower case letters and do not use spaces.] * Your answer Figure 5 Question 6: Which of the alkenes in Figure 6 can exist both as a cis and trans A.arrow_forwardAn alkene having 7 carbon atoms has Molecular formula and its name is O C;H14, heptene O C7H14, hexene C7H16, heptane O GH12, heptynearrow_forward
- Draw an alkane that has only tertiary hydrogens.arrow_forwardLine-bond structures appear to imply that there are two different isomers of 1,2-dibromobenzene, one with the bromine-bearing carbon atoms joined by a double bond and one with the bromine-bearing carbons joined by a single bond. In fact, though, there is only one 1,2-dibromobenzene. Explain. H H. C. Br H. .C. Br || || .C and 1,2-Dibromobenzene Br Brarrow_forwardInterconversion of the staggered and eclipsed conformations of alkanes requires rotation around a -C bond such as the one depicted below (see arrow). Using your knowledge of bonding, explain why these rotations do not significantly affect the energy (strength) of these bonds. You may find it helpful to describe the type of bond being rotated.arrow_forward
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