In froth ?otation, air is bubbled through an aqueous solution or slurry to which a foaming agent (soap) has been added. The air-soap bubbles carry ?nely dispersed solids and hydrophobic materials such as grease and oil to the surface where they can be skimmed off in the foam.
An ore-containing slurry is to be processed in a froth ?otation tank at a rate of 300 tons/h. The slurry consists of 20.0 wt% solids (the ore, SG = 1.2) and the remainder an aqueous solution with a density close to that of water. Air is sparged (blown through a nozzle designed to produce small bubbles) into the slurry at a rate of 40.0 ft3(STP)/1000 gal of slurry. The entry point of the air is 10 ft below the slurry surface. The tank contents are at 75°F and the barometric pressure is 28.3 inches of Hg. The sparger design is such that the average bubble diameter on entry is 2.0 mm.
(a) What is the volumetric ?ow rate of the air at its entering conditions?
(b) By what percentage does the average bubble diameter change between the entry point and the slurry surface?
Want to see the full answer?
Check out a sample textbook solutionChapter 5 Solutions
Elementary Principles Of Chemical Processes
Additional Engineering Textbook Solutions
Degarmo's Materials And Processes In Manufacturing
Starting Out With Visual Basic (8th Edition)
Database Concepts (8th Edition)
Java How to Program, Early Objects (11th Edition) (Deitel: How to Program)
Starting Out with C++ from Control Structures to Objects (9th Edition)
Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
- A semi-truck tire is inflated to 110 psig with nitrogen. What will be the initial gas discharge ratein lbm/s due to a 1/16-inch diameter hole? Assume at temperature of 80℉ and an ambientpressure of 1 atm.arrow_forward# 4 The reaction, AB, is to be carried out isothermally in a continuous flow reactor. The entering volumetric flow rate, vo is 10 L/h and is constant (v=vo). Calculate both the CSTR and PFR volumes necessary to reduce the entering concentration of species A from CAD to CA = 0.01 CAO when the entering molar flow rate of species A is 5 mol/h. (a) This reaction is a second order reaction. The reaction rate constant, k is given as 300 L/mol.h. (b) This reaction is a zeroth order reaction. The reaction rate constant, k is given as 0.05 mol/h.L.arrow_forward#3 Using the initial rates method and the given experimental data below to determine the rate law and the value of the rate constant for the reaction, as shown below. All trials are performed at the same temperature. 2NO + Cl2 → 2NCOCI Trial [NO] (mol/L) [Cl₂] (mol/L) Initial rates (mol/L.s) 1 0.10 0.10 0.00300 2 0.10 0.15 0.00450 3 0.15 0.10 0.00675arrow_forward
- #2 The reaction rate constant at temperature, T₁, is 15 mol/L-s while at the reaction rate constant changed to 7 mol/L-s when temperature changed to T2 at 398 K. What is T₁? Given the activation energy is 600 kJ/mol. Assume at this temperature interval, pre-exponential factor and activation energy are constant.arrow_forward#1 Chloral is consumed at a rate of 10 mol/L-s when reacting with chlorobenzene to form DDT and water in the reaction given below. Determine: i) the rate of disappearance of chlorobenzene. ii) the rate of formation of DDT. CCI CHO (Chloral) + 2C6H5Cl (Chlorobenzene) → (C6H4Cl)2CHCCI 3 (DDT) + H2Oarrow_forward#5 The irreversible liquid phase second order reaction, 2A → B, is carried out in a CSTR. The entering concentration of A, CAD is 2 mol/L, and the exit concentration of A, CA is 0.1 mol/L. The volumetric flow rate, vo, is at 3 L/s and is constant (v=vo). The reaction rate constant, k is 0.03 L/mol's. What is the corresponding reactor volume?arrow_forward
- Problem 9.11 An 80 mm long line MN has its end M 15 mm in front of the V.P. The distance between the ends projector is 50 mm. The front view is parallel to and 20 mm above reference line. Draw the projections of the line and determine its inclination with the V.P. Also, locate the traces. Interpretation Front view of a line is parallel to xy, therefore, 1. The line is parallel to the H.P. 2. The top view of the line has true length. 3. The front view has projected length equal to the distance be- tween the projectors. Construction Refer to Fig. 9.11. 1. Draw a reference line xy. Mark point m' 20 mm above xy and point m 15 mm below xy. 2. Draw a 50 mm long line m'n' parallel to xy. 3. Draw an arc with centre m and radius 80 mm to meet projec- tor from point n' at point n. Join mn to represent the top view. Determine its inclination with xy as the inclination of line MN with the V.P. Here = 51°. 4. Traces Extend line mn to meet xy at point v. Project point v to meet m'n' produced at…arrow_forwardoh 30 20 D и D P 60 60 80arrow_forward⑤ b Δε m ab C 40arrow_forward
- Problem 10.16 An isosceles triangle of base 40 mm and altitude 54 mm has its base in the V.P. The surface of the plane is inclined at 50° to the V.P. and perpendicular to the H.P. Draw its projections. Construction Refer to Fig. 10.17. An isosceles triangle has its base in the V.P., so con- sider that initially the triangle ABC is placed in the V.P. with base AB perpendicular to the H.P. 1. First stage Draw a triangle a'b'c' keeping a'b' perpendicular to xy to represent the front view. Project the corners to xy and obtain ac as the top view. 2. Second stage Reproduce the top view of first stage keeping ab on xy and ac inclined at 50° to xy. Obtain new points a', b' and c' in the front view by joining the points of intersection of the vertical projectors from a, b and c of the second stage with the corresponding horizontal locus lines from a', b' and c' of the first stage. Join a'b'c' to represent the final front view. Here, the front view is an equilateral triangle of side 40 mm. X 54…arrow_forward%9..+ ۱:۱۹ X خطأ عذرا ، الرقم الذي أدخلته خاطئ. يرجى إدخال رقم بطاقة الشحن الصالحة والمحاولة مرة أخرى. رصيد هاتفك قم بمسح الرمز = رقم بطاقة التعبئة 7794839909080 رمز مكون من 13 او 14 رقماً طريقة إعادة التعبئة قم باعادة تعبئة الرصيد إعادة تعبئة الإنترنت إعادة تعبئة الرصيد O >arrow_forwardProblem 10.14 A hexagonal plane of side 30 mm has a corner in the V.P. The surface of the plane is inclined at 45° to the V.P. and perpendicular to the H.P. Draw its projections. Assume that the diagonal through the corner in the V.P. is parallel to the H.P. d' a 2 b b.f C' c.e b 'C' H.P. (a) V.P E HEX 30 e' O' d' a a' b' C' b' X y a b,f c,e d b,f (b) c,earrow_forward
- Introduction to Chemical Engineering Thermodynami...Chemical EngineeringISBN:9781259696527Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark SwihartPublisher:McGraw-Hill EducationElementary Principles of Chemical Processes, Bind...Chemical EngineeringISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEYElements of Chemical Reaction Engineering (5th Ed...Chemical EngineeringISBN:9780133887518Author:H. Scott FoglerPublisher:Prentice Hall
- Industrial Plastics: Theory and ApplicationsChemical EngineeringISBN:9781285061238Author:Lokensgard, ErikPublisher:Delmar Cengage LearningUnit Operations of Chemical EngineeringChemical EngineeringISBN:9780072848236Author:Warren McCabe, Julian C. Smith, Peter HarriottPublisher:McGraw-Hill Companies, The