Concept explainers
(a)
Interpretation:
Principal organic product obtained on reaction of
Concept introduction:
In an electrophilic addition reaction, there is an addition of an electrophilic reagent on a nucleophilic group. The double bond and triple bond containing compounds act as a nucleophile. The addition of electrophilic reagent on nucleophilic compound leads to the dissociation of

Answer to Problem 5.28AP
The product formed on reaction of
Explanation of Solution
In the reaction of
Figure 1
The product formed by reaction of
The reaction between
(b)
Interpretation:
Principal organic product obtained on reaction of
Concept introduction:
In the reactionof

Answer to Problem 5.28AP
The product formed by the reaction of
Explanation of Solution
In the reaction,
The general view of
Figure 2
In the same manner,
Figure 3
The product formed by the reaction between
(c)
Interpretation:
Principal organic product obtained on the reaction of
Concept introduction:
In the reactionof alkene with ozone, the oxidation of alkene takes place which leads to form molozonide product. This reaction takes place through

Answer to Problem 5.28AP
The product formed by the reaction of
Explanation of Solution
The compound
Figure 3
The molozonide formed is unstable in nature, therefore, it gets easily reduced by
Figure 4
Therefore, the product formed by the reaction between
The reaction between
(d)
Interpretation:
Principal organic product obtained on the reaction of
Concept introduction:
In the reactionof alkene with ozone, the oxidation of alkene takes place which leads to form molozonide product. This reaction takes place through

Answer to Problem 5.28AP
The product formed by the reaction of
Explanation of Solution
The compound
Figure 3
The molozonide formed is unstable in nature, therefore, it gets easily oxidized by
Figure 5
Therefore, the product formed by the reaction between
The reaction between
(e)
Interpretation:
Principal organic product on reaction of
Concept introduction:
The reaction between unsaturated alkene with

Answer to Problem 5.28AP
The product formed by the reaction of
Explanation of Solution
The reaction between
Figure 6
Therefore, the reaction between
The reaction between
(f)
Interpretation:
Principal organic product on reaction of
Concept introduction:
In markovnikov’s addition of

Answer to Problem 5.28AP
The product formed by the reaction of
Explanation of Solution
In the reaction of
Figure 7
Therefore, the product formed by the reaction between
Thereaction between
(g)
Interpretation:
Principal organic product on reaction of
Concept introduction:
.In an electrophilic addition reaction, there is an addition of an electrophilic reagent on a nucleophilic group. The double bond and triple bond containing compounds act as nucleophile. The addition of electrophilic reagent on nucleophilic compound leads to the dissociation of

Answer to Problem 5.28AP
The product formed by the reaction of
Explanation of Solution
In the reaction first reaction between
Figure 8
Therefore, the reaction between
The reaction between
(h)
Interpretation:
Principal organic product on reaction of
Concept introduction:
In acatalytic hydrogenation reaction, palladium is used as a catalyst which accelerates the

Answer to Problem 5.28AP
The product formed by the reaction of
Explanation of Solution
In this reaction, palladium is used as a catalyst which helps in accelerating the rate of hydrogenation reaction. This reaction leads to conversion of
The product formed by the reaction between
Figure 9
Theproduct formed by the reaction between
(i)
Interpretation:
Principal organic product on reaction of
Concept introduction:
In Anti-Markovnikov’s addition of

Answer to Problem 5.28AP
The product formed on reaction of
Explanation of Solution
In thereaction, in presence of peroxides,
The product formed by the reaction between
Figure 10
The product formed by the reaction between
(j)
Interpretation:
Principal organic product on reaction of with
Concept introduction:
In hydroboration reaction, antimarkovnikov’s addition of

Answer to Problem 5.28AP
The product formed by thereaction of
Explanation of Solution
The reaction between
The product formed by thereaction between
Figure 11
The product formed by the reaction between
(k)
Interpretation:
Principal organic product formed by the reaction of product of
Concept introduction:
In hydroboration reaction, antimarkovnikov’s addition of
The compound

Answer to Problem 5.28AP
The product formed on reaction of boron substitued
Explanation of Solution
In the reaction,.the hydroxide group of
The product formed by the reaction between boron substitued
Figure 12
The product formed by thereaction between boron substitued
(l)
Interpretation:
Principal organic product on reaction of
Concept introduction:
Inan oxymercuration reaction,

Answer to Problem 5.28AP
The product formed on reaction of
Explanation of Solution
This is an oxymercuration reaction in which
The product formed by the reaction between
Figure 13
The product formed by thereaction between
(m)
Interpretation:
Principal organic product formed by the treatment of product of reaction of
Concept introduction:
In an oxymercuration reaction,
In demercuration reaction,

Answer to Problem 5.28AP
The Principal organic product formed by the treatment of product of reaction of
Explanation of Solution
The product formed by the reaction between
In demercuration reaction,
Figure 14
The product formed on reaction is
The product formed by the treatment of product of reaction of
(n)
Interpretation:
Principal organic product formed by the treatment of product of reaction of
Concept introduction:
In an electrophilic addition reaction, there is an addition of an electrophilic reagent on a nucleophilic group. The double bond and triple bond containing compounds act as a nucleophile. The addition of electrophilic reagent on nucleophilic compound leads to the dissociation of

Answer to Problem 5.28AP
The product formed by the treatment of product of reaction of
Explanation of Solution
The reaction between
Figure 15
Principal organic product formed by the treatment of product of reaction of
(o)
Interpretation:
Principal organic product formed by the treatment of product of reaction of
Concept introduction:
The reaction between an alkene,

Answer to Problem 5.28AP
The Principal organic product formed by the treatment of product of reaction of
Explanation of Solution
The reaction between in presence of
Figure 15
The product formed by the treatment of product of reaction of
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Chapter 5 Solutions
ORGANIC CHEMISTRY SAPLING ACCESS + ETEX
- 8. Draw all the resonance forms for each of the fling molecules or ions, and indicate the major contributor in each case, or if they are equivalent (45) (2) -PH2 سمة مدarrow_forwardA J то گای ه +0 Also calculate the amount of starting materials chlorobenzaldehyde and p-chloroacetophenone required to prepare 400 mg of the given chalcone product 1, 3-bis(4-chlorophenyl)prop-2-en-1-one molar mass ok 1,3-bis(4-Chlorophenyl) prop-2-en-1-one = 277.1591m01 number of moles= 0.400/277.15 = 0.00144 moles 2 x 0.00 144=0.00288 moves arams of acetophenone = 0.00144 X 120.16 = 0.1739 0.1739x2=0.3469 grams of benzaldehyde = 0.00144X106.12=0.1539 0.1539x2 = 0.3069 Starting materials: 0.3469 Ox acetophenone, 0.3069 of benzaldehyde 3arrow_forward1. Answer the questions about the following reaction: (a) Draw in the arrows that can be used make this reaction occur and draw in the product of substitution in this reaction. Be sure to include any relevant stereochemistry in the product structure. + SK F Br + (b) In which solvent would this reaction proceed the fastest (Circle one) Methanol Acetone (c) Imagine that you are working for a chemical company and it was your job to perform a similar reaction to the one above, with the exception of the S atom in this reaction being replaced by an O atom. During the reaction, you observe the formation of three separate molecules instead of the single molecule obtained above. What is the likeliest other products that are formed? Draw them in the box provided.arrow_forward
- 3. For the reactions below, draw the arrows corresponding to the transformations and draw in the boxes the reactants or products as indicated. Note: Part A should have arrows drawn going from the reactants to the middle structure and the arrows on the middle structure that would yield the final structure. For part B, you will need to draw in the reactant before being able to draw the arrows corresponding to product formation. A. B. Rearrangement ΘΗarrow_forward2. Draw the arrows required to make the following reactions occur. Please ensure your arrows point from exactly where you want to exactly where you want. If it is unclear from where arrows start or where they end, only partial credit will be given. Note: You may need to draw in lone pairs before drawing the arrows. A. B. H-Br 人 C Θ CI H Cl Θ + Br Oarrow_forward4. For the reactions below, draw the expected product. Be sure to indicate relevant stereochemistry or formal charges in the product structure. a) CI, H e b) H lux ligh Br 'Harrow_forward
- Arrange the solutions in order of increasing acidity. (Note that K (HF) = 6.8 x 10 and K (NH3) = 1.8 × 10-5) Rank solutions from least acidity to greatest acidity. To rank items as equivalent, overlap them. ▸ View Available Hint(s) Least acidity NH&F NaBr NaOH NH,Br NaCIO Reset Greatest acidityarrow_forward1. Consider the following molecular-level diagrams of a titration. O-HA molecule -Aion °° о ° (a) о (b) (c) (d) a. Which diagram best illustrates the microscopic representation for the EQUIVALENCE POINT in a titration of a weak acid (HA) with sodium. hydroxide? (e)arrow_forwardAnswers to the remaining 6 questions will be hand-drawn on paper and submitted as a single file upload below: Review of this week's reaction: H₂NCN (cyanamide) + CH3NHCH2COOH (sarcosine) + NaCl, NH4OH, H₂O ---> H₂NC(=NH)N(CH3)CH2COOH (creatine) Q7. Draw by hand the reaction of creatine synthesis listed above using line structures without showing the Cs and some of the Hs, but include the lone pairs of electrons wherever they apply. (4 pts) Q8. Considering the Zwitterion form of an amino acid, draw the Zwitterion form of Creatine. (2 pts) Q9. Explain with drawing why the C-N bond shown in creatine structure below can or cannot rotate. (3 pts) NH2(C=NH)-N(CH)CH2COOH This bond Q10. Draw two tautomers of creatine using line structures. (Note: this question is valid because problem Q9 is valid). (4 pts) Q11. Mechanism. After seeing and understanding the mechanism of creatine synthesis, students should be ready to understand the first half of one of the Grignard reactions presented in a past…arrow_forward
- Propose a synthesis pathway for the following transformations. b) c) d)arrow_forwardThe rate coefficient of the gas-phase reaction 2 NO2 + O3 → N2O5 + O2 is 2.0x104 mol–1 dm3 s–1 at 300 K. Indicate whether the order of the reaction is 0, 1, or 2.arrow_forward8. Draw all the resonance forms for each of the following molecules or ions, and indicate the major contributor in each case, or if they are equivalent. (4.5 pts) (a) PH2 سمةarrow_forward
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