Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN: 9781305081550
Author: Braja M. Das
Publisher: Cengage Learning
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Question
Chapter 5, Problem 5.1P
To determine
Find the gross allowable load carried by the foundation.
Expert Solution & Answer
Answer to Problem 5.1P
The gross allowable load carried by the foundation is
Explanation of Solution
Given information;
The width of the foundation (B) is 1.5 m.
The length of the foundation (L) is 2.5 m.
The depth of the foundation
The depth of base (H) is 0.9 m.
The angle of friction of soil
The cohesion of the soil
The unit weight of the soil
The factor of safety is (FS) is 3.0.
Calculation:
Determine the ratio of
Refer Figure (5.4), “Mandel and Salencon’s bearing capacity factor
Take
Refer Figure (5.5), “Mandel and Salencon’s bearing capacity factor
Take
Refer Figure (5.6), “Mandel and Salencon’s bearing capacity factor
Take
Determine the shape factor
Determine the shape factor
Determine the ultimate load bearing capacity
Determine the gross allowable load carried by the foundation .
Therefore, the gross allowable load carried by the foundation is
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Students have asked these similar questions
H.Q 1
Consider a rectangular foundation. Given: B = 1.5 m, L = 2.5 m, Df= 1.2
m, H =0.9 m, o' = 40°, c' = 0, and y= 17 kN/m3. Using a factor of safety
of 3, determine the gross allowable load the foundation can carry. Use
Meyerhof equation.
Question 2) For a shallow foundation shown below:
A. Estimate the ultimate bearing capacity when the water table located at a depth of 2 m
below the ground surface.
B. Estimate the moments about the x- and y-axis; assume that the foundation is subjected
to a vertical load and a moment. If eg and eL is 0.33 m and 0.12 m, respectively.
G.S
Iz
2 m
(2 m x 3 m)
Silty clay
Yo=17 kN/m³ , Ysat = 20 kN/m3
%3D
6 m
c'=78 kN/m? 0'=35°
Shear modulus=250 kN/m?
CS Scanned with CamScanner
The shallow foundation shown in Figure 4.24 measures 1.5 m x 2.25 m and is subjected to a centric load and a moment. If eB = 0.12 m, eL = 0.36 m, and the depth of the foundation is 0.8 m, determine the allowable load the foundation can carry. Use a factor of safety of 4. For the soil, we are told that unit weight γ = 17 kN/m3, friction angle Φ' = 35°, and cohesion c' = 0.
Chapter 5 Solutions
Principles of Foundation Engineering (MindTap Course List)
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Similar questions
- A continuous foundation with a width of 1 m is located on a slope made of clay soil. Refer to Figure 5.19 and let Df = 1 m, H = 4 m, b = 2 m, γ = 16.8 kN/m3, c = cu = 68 kN/m2, Φ= 0, and β = 60°.a. Determine the allowable bearing capacity of the foundation. Let FS = 3.b. Plot a graph of the ultimate bearing capacity qu if b is changed from 0 to 6 m.arrow_forward2 ft 2 ft 24 ft 24 ft 24 ft Problem 4 B D E F G | 3 ft DL=100 kip DL=180 kip LL = 60 kịp LL = 120 kip DL=190 kip DL=110 ki • The plan of a mat foundation with column loads is shown in Figure 2. Use the rigid method to calculate the soil pressures at point A, B, C, D, E, F, G, H, , J, K, L, M and N. The size of the mat is 76 ft x 96 ft, all columns are 24 in x 24 in in section, and qlnet = 1.5 kip/ft². Verify that the soil pressures are less than the net allowable bearing capacity. LL = 120 kip LL = 70 ki 30 ft DL=180 kip DL=400 kip DL=200 kip LL = 250 kip LL = 120 kip DL=360 kip LL = 120 kip LL = 200 kip ex 30 ft DL-190 kip DL=500 kip LL = 130'kip LL = 240 kip DL=T10 kip DL=200 kip LL =300 kip LL =120 kip 30 ft DL=180 kip DL=120 kip LL =120 kip L =70 kip x' 3 ft IDL=120 kip DL=180 kip ILL =70 kip LL =120 kip J Figure 2: Plan of a Mat Foundation M L K Harrow_forward3. A square foundation is constructed in a soil deposit as shown in the figure below. Assume that the groundwater table is 6 meters below the foundation. The applied load on the shallow square foundation makes an angle of 10° with the vertical. Use FS = 3 and determine the allowable load. (Use general bearing capacity equation.) 6m 4 m y = 17.5 kN/m³ ' = 33° c' = 20 kN/m² Ysat = 20k N/m³ Groundwater tablearrow_forward
- Question 1) For a shallow foundation measuring (1.7 m x 2.2 m) as shown below: , A. Estimate the elastic settlement proposed by Mayerhof. Then, B. Estimate the elastic settlement proposed by Bowles, if the water table rises 1.5 m. Then, Use yw=10 kN/m³ qnet= 1.2 MN/m2 G.S 1.5 m Sand Yd=16 kN/m³ Ysat= 17 kN/m3 %3D 2.5 m N60=52 V W.T. Silty Sand Ya=18 kN/m³ Ysat = 18.5 kN/m? N60=52 3.5 m Sand Ya=19 kN/m3 Ysat = 22 kN/m³ e, = 0.4, Ae=0.04 , o'= 194 kN/m2 5 m Cc= 0.3, Cs= 0.2 , Ca= 0.05 N60=60 CS Scanned with CamScannerarrow_forwardThe shallow foundation shown below measures 2 m x 3 m and is subjected to a centric load and a moment. If eg = 0.2 m, ez = 0.3 m, and the depth of foundation is 1 m, determine the allowable load the foundation can carry. Use a factor of safety of 3. For the soil, we are told that the unit weight, y = 17 kn/m³, friction angle o' = 30°, and the cohesion, c' = 0. Qult B× L Qult eL Qult Qaln My Barrow_forwardELABORATE Try solving the following problem: Practice Problem: A rigid foundation is subjected to a vertical column load, P = 550 kN, as shown in Figure 4.9. Estimate the elastic settlement due to the net applied pressure, Ao, at the center of the foundation. Given: B = 2 m; L = 3 m; Df = 1.5 m; H = 5 m; Es = 13,500 kN/m²; and μs = 0.5. SAP Foundation BXL D Soil H, Poisson's ratio. E₂ -modulus of elasticity H Rock Figure 4.9 Ag Cengage Leaming 2014arrow_forward
- Consider a continuous foundation of width B = 1.4 m on a sand deposit with c' = 0, Φ' = 38° and γ = 17.5 kN/m3. The foundation is subjected to an eccentrically inclined load (see Figure 4.31). Given: load eccentricity e = 0.15 m, Df = 1 m, and load inclination β = 18°. Estimate the failure load Qu(ei) per unit length of the foundation a. for a partially compensated type of loading [Eq. (4.85)] b. for a reinforced type of loading [Eq. (4.86)]arrow_forwardProblem 2: A square foundation is 1.5 m by 1.5 m in plan with other characteristics shown in the figure. The soil supporting the foundation has a friction angle ø = 20° and c = 15.2 kN/m?. The unit weight of the soil is 17.8 kN/m³. Determine the allowable gross load on the foundation with a factor of safety of 4. Use general shear failure with Nc = 17.69 ; Nq = 7.44 ; Ny = 3.64 %3D %3D %3D Qall Y = 17.8 kN/m3 e = 0.60 Gs = 2.65 D;= 1.0 m GWT D = 0.4 marrow_forward5.2 A square column foundation has to carry a gross allowable load of 1805 kN (FS = 3). Given: D,= 1.5 m, y = 15.9 kN/m³, o' = 34°, and c' = 0. Use Terzaghi's equation to determine the size of the foundation (B). Assume general shear failure.arrow_forward
- answer in complete solution plsarrow_forwardA column foundation (Figure P3.5) is 3 m x 2 m in plan. Given: D; = 2 m, o' = 25°, c' = 50 kN/m². Using Eq. (3.23) and FS = 4, determine the net allowable load [see Eq. (3.15)] the foundation could carry. Use bearing capac- ity, shape, and depth factors given in Şection 3.6.arrow_forwardA column foundation is 3 m × 2 m in plan. Given: Dƒ = 1.5 m, þ' = 30°, c′ = 80 kN/m². Using the general bearing capacity equation (CFEM see class slides from March 17 similar to Example 1 and 2 but with an added capacity term related to cohesion) and 0.5, determine the factored bearing capacity of the foundation (i.e. – use Þ). Use Yw = 9.81 kN/m³. For simplicity, read the values of Nc, Ną, and Ny directly from the table on page 26 of the lecture slides use the highlighted columns. Also, determine the maximum factored load for the column. - 1.5 m ↑ 1 m 3m x 2m - y = 17 kN/m³ Groundwater level Ysat = 19.5 kN/m³ =arrow_forward
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